I appreciate the response but if this is what you have in mind I didn't get anything different. Any ideas why?
for (i in nrow(Volumes)){ plot(as.numeric(deltas[i,])) Sys.sleep(0.5); } Thanks Jan T. Kim wrote: > > On Mon, Jun 09, 2008 at 02:02:01PM -0700, Ken Spriggs wrote: >> >> Hello, >> >> This code works fine but is so fast I can't see anything but the last >> plot. >> >> for (i in nrow(X)){ >> plot(as.numeric(d[i,])) } >> >> I'd like to view a plot every 500 milliseconds, nrow(X) = 400. How? > > Adding the line > > Sys.sleep(0.5); > > to the loop should do this trick. > > Best regards, Jan > -- > +- Jan T. Kim -------------------------------------------------------+ > | email: [EMAIL PROTECTED] | > | WWW: http://www.cmp.uea.ac.uk/people/jtk | > *-----=< hierarchical systems are for files, not for humans >=-----* > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/Plot-timer-in-a-for-loop-tp17741975p17756771.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.