Thanks, you're a lifesaver.
-J
2010/3/30 Henrique Dallazuanna :
> Using lapply:
>
> as.data.frame(lapply(df, cut, breaks = c(-Inf, 3, 8, 16), labels =
> c('x', 'y', 'z')))
>
>
> On Tue, Mar 30, 2010 at 10:14 AM, johannes rara
> wrote:
>> Thanks John and Henrique, my intention is to do this for
Using lapply:
as.data.frame(lapply(df, cut, breaks = c(-Inf, 3, 8, 16), labels =
c('x', 'y', 'z')))
On Tue, Mar 30, 2010 at 10:14 AM, johannes rara wrote:
> Thanks John and Henrique, my intention is to do this for A, B and C
> (all at once), so I'll have to wrap your solution into lapply or for
Thanks John and Henrique, my intention is to do this for A, B and C
(all at once), so I'll have to wrap your solution into lapply or for
loop?
-J
2010/3/30 Henrique Dallazuanna :
> You could try this also:
>
> cut(df$A, c(-Inf, 3, 8), labels = c('x', 'y'))
>
> On Tue, Mar 30, 2010 at 8:30 AM, joh
You could try this also:
cut(df$A, c(-Inf, 3, 8), labels = c('x', 'y'))
On Tue, Mar 30, 2010 at 8:30 AM, johannes rara wrote:
> Hi,
>
> Is there an efficient way recoding variables in a data.frame using
> base R? My purpose is to create
> new variables and attach them into old data.frame. The ba
Dear Johannes,
You can use cascading ifelse()s:
> df$A <- with(df, ifelse(A <= 3, "x", ifelse(A > 3 & A <= 8, "y", "z")))
> df$A
[1] "x" "x" "x" "y" "y"
This command assumes that you want all values that don't map into "x"s and
"y"s to be "z"s, but you could adapt it if that's not what you want
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