Using lapply:
as.data.frame(lapply(df, cut, breaks = c(-Inf, 3, 8, 16), labels =
c('x', 'y', 'z')))
On Tue, Mar 30, 2010 at 10:14 AM, johannes rara <johannesr...@gmail.com> wrote:
> Thanks John and Henrique, my intention is to do this for A, B and C
> (all at once), so I'll have to wrap your solution into lapply or for
> loop?
>
> -J
>
> 2010/3/30 Henrique Dallazuanna <www...@gmail.com>:
>> You could try this also:
>>
>> cut(df$A, c(-Inf, 3, 8), labels = c('x', 'y'))
>>
>> On Tue, Mar 30, 2010 at 8:30 AM, johannes rara <johannesr...@gmail.com>
>> wrote:
>>> Hi,
>>>
>>> Is there an efficient way recoding variables in a data.frame using
>>> base R? My purpose is to create
>>> new variables and attach them into old data.frame. The basic idea is
>>> shown below, but how to create recoding for A, B and C and assing them
>>> into new variables?
>>>
>>> df <- data.frame(A = c(1:5),
>>> B = c(3,6,2,8,10),
>>> C = c(0,15,5,9,12))
>>>
>>> df$A[df$A <= 3] <- "x"
>>> df$A[df$A > 3 & df$A <= 8] <- "y"
>>> df$A[df$A <= 16] <- "z"
>>>
>>> Thanks,
>>> -J
>>>
>>> ______________________________________________
>>> R-help@r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>>
>>
>> --
>> Henrique Dallazuanna
>> Curitiba-Paraná-Brasil
>> 25° 25' 40" S 49° 16' 22" O
>>
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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