Then use strsplit() instead.
KeithC.
-Original Message-
From: kayj [mailto:kjaj...@yahoo.com]
Sent: Friday, February 26, 2010 1:02 PM
To: r-help@r-project.org
Subject: Re: [R] using grep
Hi ,
I have tried
gsub(".*York(\\d+).*", "\\1", grep("New York&
alf Of kayj
>> Sent: Friday, February 26, 2010 11:27 AM
>> To: r-help@r-project.org
>> Subject: [R] using grep
>>
>>
>> Hi All,
>>
>> I have a character vector with naems of cities in the us. I need to
>> extract
>> the number that appear
ct.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of kayj
> Sent: Friday, February 26, 2010 11:27 AM
> To: r-help@r-project.org
> Subject: [R] using grep
>
>
> Hi All,
>
> I have a character vector with naems of cities in the us. I need to
> extract
> the numb
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of kayj
> Sent: Friday, February 26, 2010 12:02 PM
> To: r-help@r-project.org
> Subject: Re: [R] using grep
>
>
> Hi ,
>
> I have tried
>
On Feb 26, 2010, at 3:02 PM, kayj wrote:
Hi ,
I have tried
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
and outputs
"P New York722AZ" "K New York20"
Strange:
> x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20")
>
> gsub(".*York(\\d+).*", "\\1", grep("New Yo
What is your R version?
Install the most recent R version (2.10.1).
On Fri, Feb 26, 2010 at 5:02 PM, kayj wrote:
>
> Hi ,
>
> I have tried
>
> gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
>
> and outputs
>
> "P New York722AZ" "K New York20"
> but that is not what i want, I w
Hi ,
I have tried
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
and outputs
"P New York722AZ" "K New York20"
but that is not what i want, I want the output to be
722,20
--
View this message in context:
http://n4.nabble.com/using-grep-tp1571102p1571251.html
Sent fro
Try this:
gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE))
On Fri, Feb 26, 2010 at 3:27 PM, kayj wrote:
>
> Hi All,
>
> I have a character vector with naems of cities in the us. I need to extract
> the number that appear after the word "New York", for example,
>
> x<-c("P Los Ang
Hi All,
I have a character vector with naems of cities in the us. I need to extract
the number that appear after the word "New York", for example,
x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20")
I want the results to be
722, 20
cab I use the grep function, if so how?
I apprecia
Here are several ways to find the last character in a string:
> x <- "abc"
> substring(x, nchar(x))
[1] "c"
> sub(".*(.)", "\\1", x)
[1] "c"
> library(gsubfn)
> strapply(x, ".$")[[1]]
[1] "c"
On Mon, Oct 19, 2009 at 3:52 PM, Jason Rupert wrote:
> I am currently being defeated by grep. I am a
stLetter <- substr(yourstring, n, n)
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jason Rupert
Sent: Monday, October 19, 2009 12:52 PM
To: R-help@r-project.org
Subject: [R] Us
I am currently being defeated by grep. I am attempting to determine the value
of the last letter of a character string.
An example of my data set is shown below. Regarding the codes, I would like to
identify the value of the last character and then take the appropriate action,
e.g.
If the
ppaarrkk wrote:
I have two vectors, a and b. b is a text file. I want to find in b those
elements of a which occur at the beginning of the line in b. I have the
following code, but it only returns a value for the first value in a, but I
want both. Any ideas please.
a = c(2,3)
b = NULL
b[1] =
Try this. For each character x in s, if "x" is punctuation it is replaced
with "\\x" otherwise with "[x]" :
library(gsubfn)
gsubfn('.', ~ if (any(grep("[[:punct:]]", x))) paste0('\\', x) else
paste0('[', x, ']'), s)
See http://gsubfn.googlecode.com
On Sat, Nov 29, 2008 at 10:09 PM, Stavros Mac
But I don't want to ignore all regexp's -- I want to build a regexp which
contains string components which are parameters.
-s
On Sat, Nov 29, 2008 at 6:51 PM, Gabor Grothendieck <[EMAIL PROTECTED]
> wrote:
> grep has a fixed = TRUE argument if you want to ignore all regexp's.
>
> On
grep has a fixed = TRUE argument if you want to ignore all regexp's.
On Sat, Nov 29, 2008 at 3:55 PM, Stavros Macrakis <[EMAIL PROTECTED]> wrote:
> Hmm, this brings up an interesting question. What if the string I'm looking
> for contains escape characters? For example, grep( paste( "^", "(ab)"
Hmm, this brings up an interesting question. What if the string I'm looking
for contains escape characters? For example, grep( paste( "^", "(ab)" ),
c("ab","(ab)") ) => c(1), not c(2).
I couldn't find an equivalent to Emacs's regexp-quote, which would let me
write regexp.quote("(ab)") => "\\(ab\
Try this:
> a <- 2:3
> b <- c("aaa 2 aaa", "2 aaa", "3 aaa", "aaa 3 aaa")
>
> re <- paste("^(", paste(a, collapse = "|"), ")", sep = "")
> re
[1] "^(2|3)"
> grep(re, b, value = TRUE)
[1] "2 aaa" "3 aaa"
On Sat, Nov 29, 2008 at 7:00 AM, ppaarrkk <[EMAIL PROTECTED]> wrote:
>
> I have two vectors, a
I have two vectors, a and b. b is a text file. I want to find in b those
elements of a which occur at the beginning of the line in b. I have the
following code, but it only returns a value for the first value in a, but I
want both. Any ideas please.
a = c(2,3)
b = NULL
b[1] = "aaa 2 aaa"
b[2] =
On 08-Oct-08 15:19:02, mentor_ wrote:
> Hi,
> I have a vector A with (200, 201, 202, 203, 204, ... 210) and
> a vector B with (201, 204, 209).
> Now I would like to get the position in vector A matches with
> the entries in vector B
> So what I want to have is the following result:
> [1] 2 5 10
Fi
A <- seq(200,210,1)
B <- c(201,204,209)
which(A %in% B)
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of mentor_
> Sent: Wednesday, October 08, 2008 11:19 AM
> To: r-help@r-project.org
> Subject: [R] Using grep
>
>
Here is a possible solution:
> A
[1] 200 201 202 203 204 205 206 207 208 209 210
> B
[1] 201 204 209
> which(!is.na(match(A,B)))
[1] 2 5 10
>
Hope this helps,
Sincerely,
Erin
On Wed, Oct 8, 2008 at 10:19 AM, mentor_ <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I have a vector A with (200, 201, 202
which(A %in% B)
-Christos
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of mentor_
> Sent: Wednesday, October 08, 2008 11:19 AM
> To: r-help@r-project.org
> Subject: [R] Using grep
>
>
> Hi,
>
> I have a vecto
Hi,
I have a vector A with (200, 201, 202, 203, 204, ... 210) and a vector B
with (201, 204, 209).
Now I would like to get the position in vector A matches with the entries in
vector B
So what I want to have is the following result:
[1] 2 5 10
I tried the following:
grep(B, A)
grep(c(B), A)
A
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