> -----Original Message----- > From: r-help-boun...@r-project.org > [mailto:r-help-boun...@r-project.org] On Behalf Of kayj > Sent: Friday, February 26, 2010 12:02 PM > To: r-help@r-project.org > Subject: Re: [R] using grep > > > Hi , > > I have tried > > gsub(".*York(\\d+).*", "\\1", grep("New York", x, value = TRUE)) > > and outputs > > "P New York722AZ" "K New York20" > but that is not what i want, I want the output to be > > 722,20
Does it work if you replace the "\\d" in the pattern with "[0-9]"? If so, your regular expression code doesn't recognize the "\\d" to mean "a decimal digit". Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com > > > -- > View this message in context: > http://n4.nabble.com/using-grep-tp1571102p1571251.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
