...or use the more generic substitute() to replace parts of an expression, e.g.
i <- 3;
xlab1 <- substitute(g[idx], list=list(idx=i));
xlab2 <- bquote(g[.(i)]);
stopifnot(identical(xlab1, xlab2));
/Henrik
On Mon, Aug 18, 2008 at 3:18 PM, Marc Schwartz
<[EMAIL PROTECTED]> wrote:
> on 08/
on 08/18/2008 05:00 PM Nanye Long wrote:
> Hi all,
>
> I want to do plot() in a loop to make 10 graphs, so I have some code like
>
> for (i in 1:10) {
>plot(... ... , xlab = expression(g[i]) )
> }
>
> I expect g_1, g_2, and so on appear on x labels, but it simply prints
> g_i for each graph.
Nanye Long said the following on 8/18/2008 3:00 PM:
Hi all,
I want to do plot() in a loop to make 10 graphs, so I have some code like
for (i in 1:10) {
plot(... ... , xlab = expression(g[i]) )
}
I expect g_1, g_2, and so on appear on x labels, but it simply prints
g_i for each graph. Does
Hi all,
I want to do plot() in a loop to make 10 graphs, so I have some code like
for (i in 1:10) {
plot(... ... , xlab = expression(g[i]) )
}
I expect g_1, g_2, and so on appear on x labels, but it simply prints
g_i for each graph. Does anybody know how to get around this problem?
Thanks.
N
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