...or use the more generic substitute() to replace parts of an expression, e.g.
i <- 3;
xlab1 <- substitute(g[idx], list=list(idx=i));
xlab2 <- bquote(g[.(i)]);
stopifnot(identical(xlab1, xlab2));
/Henrik
On Mon, Aug 18, 2008 at 3:18 PM, Marc Schwartz
<[EMAIL PROTECTED]> wrote:
> on 08/18/2008 05:00 PM Nanye Long wrote:
>> Hi all,
>>
>> I want to do plot() in a loop to make 10 graphs, so I have some code like
>>
>> for (i in 1:10) {
>> plot(... ... , xlab = expression(g[i]) )
>> }
>>
>> I expect g_1, g_2, and so on appear on x labels, but it simply prints
>> g_i for each graph. Does anybody know how to get around this problem?
>> Thanks.
>>
>> NL
>
> Try this:
>
> par(mfrow = c(5, 2))
>
> for (i in 1:10)
> plot(1, xlab = bquote(g[.(i)]))
>
>
> Note the use of bquote() and the use of .(i), which replaces 'i' with
> the value of i in each iteration.
>
> See ?plotmath for some examples and ?bquote
>
> HTH,
>
> Marc Schwartz
>
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