Hi,
Try:
dat <- read.table(text="A
1 R5000
2 R4800
3 R4700
4 3500
5 3800",sep="",header=TRUE,stringsAsFactors=FALSE)
dat$A <- as.numeric(gsub("[[:alpha:]]+","",dat$A))
A.K.
On Monday, May 19, 2014 9:02 AM, Mat wrote:
Hello togehter,
i have a litte problem to convert a data.frame. My
Hi Mat,
Try that:
gsub("[A-Za-z]", "", df$A)
This is a regular expression that looks for all characters (A to Z and a
to z) and replaces it with nothing ("")
You will need to convert the column to numeric after this operation.
HTH,
Ivan
--
Ivan Calandra
University of Franche-Comté
Laboratoir
Hello,
Try the following.
dat <- read.table(text = "
A
1 R5000
2 R4800
3 R4700
4 3500
5 3800
", header = TRUE)
dat
dat2 <- dat
dat2[] <- lapply(dat, function(x) sub("^[[:alpha:]]*(.*$)", "\\1", x))
dat2
Hope this helps,
Rui Barradas
Em 19-05-2014 14:00, Mat escreveu:
Hello togehter,
Hello togehter,
i have a litte problem to convert a data.frame. My data.frame looks like
this one
A
1 R5000
2 R4800
3 R4700
4 3500
5 3800
I need now a command, which outputs all the numbers, without the character
in front.
The solution look like this one:
A
1 5000
2 4800
3
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