Hello, Try the following.
dat <- read.table(text = " A 1 R5000 2 R4800 3 R4700 4 3500 5 3800 ", header = TRUE) dat dat2 <- dat dat2[] <- lapply(dat, function(x) sub("^[[:alpha:]]*(.*$)", "\\1", x)) dat2 Hope this helps, Rui Barradas Em 19-05-2014 14:00, Mat escreveu:
Hello togehter, i have a litte problem to convert a data.frame. My data.frame looks like this one A 1 R5000 2 R4800 3 R4700 4 3500 5 3800 I need now a command, which outputs all the numbers, without the character in front. The solution look like this one: A 1 5000 2 4800 3 4700 4 3500 5 3800 Thanks. Best regards. Mat -- View this message in context: http://r.789695.n4.nabble.com/substring-if-value-starts-with-a-character-tp4690823.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.