Alternatively if a number of such operations will be
done and memory is not an issue, then you could do:
singlefoo <- do.call('rbind', foo)
max(singlefoo[, 1])
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")
actually meant to say:
max(sapply(foo, function(x) max(x[,1])))
On Tue, Oct 14, 2008 at 5:49 PM, Carl Witthoft <[EMAIL PROTECTED]> wrote:
> Hi,
> Sorry to bother with something that should be simple, but I can't find it.
>
> Suppose I have a list, each element of which is a 2xN dataframe, where N
try:
max(sapply(foo, max))
On Tue, Oct 14, 2008 at 5:49 PM, Carl Witthoft <[EMAIL PROTECTED]> wrote:
> Hi,
> Sorry to bother with something that should be simple, but I can't find it.
>
> Suppose I have a list, each element of which is a 2xN dataframe, where N
> could be different for each eleme
Hi,
Sorry to bother with something that should be simple, but I can't find it.
Suppose I have a list, each element of which is a 2xN dataframe, where N
could be different for each element.
Is there some simple structure to let me examine all the elements of
each element's first column? For exa
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