Alternatively if a number of such operations will be
done and memory is not an issue, then you could do:
singlefoo <- do.call('rbind', foo)
max(singlefoo[, 1])
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")
jim holtman wrote:
actually meant to say:
max(sapply(foo, function(x) max(x[,1])))
On Tue, Oct 14, 2008 at 5:49 PM, Carl Witthoft <[EMAIL PROTECTED]> wrote:
Hi,
Sorry to bother with something that should be simple, but I can't find it.
Suppose I have a list, each element of which is a 2xN dataframe, where N
could be different for each element.
Is there some simple structure to let me examine all the elements of each
element's first column? For example:
foo
$first
[,1] [,2]
[1,] 1 4
[2,] 2 5
[3,] 3 6
$second
[,1] [,2]
[1,] 1 6
[2,] 2 8
[3,] 3 6
[4,] 4 8
To find the maximum element in all first columns (say, to set the range of a
plot where all first columns are x-data), I'd like the legal equivalent of
max(foo[[*]][,1])
(where here "*" is a wildcard intended to span all elements of foo)
Or do I have to use one of the apply() functions?
thanks
Carl
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