Dear njhuang86,
Here is one way:
x <- c('a', 't', 'c', 'y', 'g')
y <- c('a', 'a', 'g', 's')
table(factor(y, levels = x))
# a t c y g
# 2 0 0 0 1
HTH,
Jorge
On Tue, Jul 7, 2009 at 3:28 PM, njhuang86 wrote:
>
> Hi all,
> Suppose I have x = c('a', 't', 'c', 'y', 'g')
> and also y = c('a', 'a',
Hi all,
Suppose I have x = c('a', 't', 'c', 'y', 'g')
and also y = c('a', 'a', 'g', 's')
If I do something like x%in%y, I obtain a vector like this: [TRUE, FALSE,
FALSE, FALSE, TRUE] which I can easily turn into this: [1, 0, 0, 0, 1].
I was wondering is there anyway for me to get a vector back in
2 matches
Mail list logo