Dear njhuang86,
Here is one way:
x <- c('a', 't', 'c', 'y', 'g')
y <- c('a', 'a', 'g', 's')
table(factor(y, levels = x))
# a t c y g
# 2 0 0 0 1
HTH,
Jorge
On Tue, Jul 7, 2009 at 3:28 PM, njhuang86 <njhuan...@yahoo.com> wrote:
>
> Hi all,
> Suppose I have x = c('a', 't', 'c', 'y', 'g')
> and also y = c('a', 'a', 'g', 's')
>
> If I do something like x%in%y, I obtain a vector like this: [TRUE, FALSE,
> FALSE, FALSE, TRUE] which I can easily turn into this: [1, 0, 0, 0, 1].
> I was wondering is there anyway for me to get a vector back in return in
> the
> form of: [2, 0, 0, 0, 1]? Essentially, the 2 will tell me that in the first
> position of vector 'x', there were two matches found with vector y.
>
> Thanks a ton in advance!
> --
> View this message in context:
> http://www.nabble.com/find-duplicates...-need-help%21-tp24379828p24379828.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
