On Wed, 5 Feb 2020 09:15:16 -0600
Ana Marija wrote:
> I tried to solve the task via following code:
> all_results <- lapply(manyorders, function(ord) {
# ...
> list(fit = fit, y1 = y1)
> })
> and I wrote all_results in a file
> write.table(all_results, file="all_res", sep = " ", row.names =
I tried to solve the task via following code:
manyorders <- replicate(100, sample(colnames(dat)), simplify=FALSE)
all_results <- lapply(manyorders, function(ord) {
tmpdat <- `colnames<-`(dat, ord) # copies and renames in one line
corfit <- duplicateCorrelation(dat, block = targets$Subject)
Yes, a clear thinko... Thanks for the correction.
-- Bert
On Tue, Feb 4, 2020 at 1:41 PM Duncan Murdoch
wrote:
> On 04/02/2020 4:28 p.m., Ana Marija wrote:
> > I tired your code on this simplified data just for say 10 permutations:
> >
> > dat <- read.table(text = " code.1 code.2 code.3 code.
On 04/02/2020 4:28 p.m., Ana Marija wrote:
I tired your code on this simplified data just for say 10 permutations:
dat <- read.table(text = " code.1 code.2 code.3 code.4
1 82 93 NA NA
2 15 85 93 NA
3 93 89 NA NA
4 81 NA NA NA",
I tired your code on this simplified data just for say 10 permutations:
dat <- read.table(text = " code.1 code.2 code.3 code.4
1 82 93 NA NA
2 15 85 93 NA
3 93 89 NA NA
4 81 NA NA NA",
header = TRUE, stringsAsFacto
I am not going to do your programming for you. If the following doesn't
suffice, maybe someone else will provide you something that will.
m = your matrix
code = your code that uses m
your list of results <- lapply(seq_len(1000), FUN = function(m){
m <- m[, sample.int(132)]
code
} )
or use an
Basically I would just reshuffle column names in each of 1000 permutations
how to do that and perform everything I described in my initial email
On Tue, 4 Feb 2020 at 14:46, Ana Marija wrote:
> Hi Bert,
>
> thanks for getting back to me. I have to permute those 132 columns
> 1000 times and perfo
Hi Bert,
thanks for getting back to me. I have to permute those 132 columns
1000 times and perform the code given in the previous email.
Can you please show me how you would do that in the loop? This is also
a huge data set ...
Thanks
Ana
On Tue, Feb 4, 2020 at 2:34 PM Bert Gunter wrote:
>
> I
If you just want to permute columns of a matrix,
?sample
> sample.int(10)
[1] 9 2 10 8 4 6 3 1 5 7
and you can just use this as an index into the columns of your matrix,
presumably within a loop of some sort.
If I have misunderstood, just ignore.
Cheers,
Bert
On Tue, Feb 4, 2020 a
Hello,
I have a matrix
> dim(dat)
[1] 15568 132
It looks like this:
NoD_14381_norm.1 NoD_14381_norm.2 NoD_14381_norm.3
NoD_14520_30mM.1 NoD_14520_30mM.2 NoD_14520_30mM.3
Ku8QhfS0n_hIOABXuE 4.75 4.25 4.79
4.33 4.63
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