Hi Luigi,
It depends on how you want to put the different elements of my.list into
a data.frame. Basically, data.frames are lists, so doing
data.frame(my.list)
is straigthforward.
HTH,
Ivan
--
Ivan Calandra, PhD
University of Reims Champagne-Ardenne
GEGENAA - EA 3795
CREA - 2 esplanade Roland
You don't say how you want the new data frame (which incidentally is
also a list) to be constructed, so here are two options:
> my.list <- replicate(5, matrix(1:(6*27), ncol = 6, byrow = TRUE), FALSE)
> dim(my.list[[1]])
[1] 27 6
> dim(do.call(rbind.data.frame, my.list))
[1] 135 6
> dim(do.call(
Dear all,
i would like to convert a list onto a data frame object. Is there an
easy way of doing it? I know I should use unlist() but I am not sure
about the implementation for the addition of the row numbers; or I
could extract one member at the time with something like x <-
my.list[[i]] but then
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