You don't say how you want the new data frame (which incidentally is also a list) to be constructed, so here are two options: > my.list <- replicate(5, matrix(1:(6*27), ncol = 6, byrow = TRUE), FALSE) > dim(my.list[[1]]) [1] 27 6 > dim(do.call(rbind.data.frame, my.list)) [1] 135 6 > dim(do.call(cbind.data.frame, my.list)) [1] 27 30
Sarah On Mon, Sep 14, 2015 at 7:07 AM, Luigi Marongiu <marongiu.lu...@gmail.com> wrote: > Dear all, > i would like to convert a list onto a data frame object. Is there an > easy way of doing it? I know I should use unlist() but I am not sure > about the implementation for the addition of the row numbers; or I > could extract one member at the time with something like x <- > my.list[[i]] but then how to append the results to an object? > Thank you. > Best regards > Luigi > >>>> > my.list <- replicate(5, matrix(1:(6*27), ncol = 6, byrow = TRUE), FALSE) > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
