Re: [R] categorization

2009-11-09 Thread Ista Zahn
I don't know if it's "the fastest" way, but you can get there with as.character(factor(exData$Condition, levels=c("c20", "c10", "c9", "c5"), labels=c("AA", "BB", "CC", "DD"))) -Ista On Mon, Nov 9, 2009 at 2:06 PM, phoebe kong wrote: > Hi All, > > I have a dataset with a column named "Condition"

[R] categorization

2009-11-09 Thread phoebe kong
Hi All, I have a dataset with a column named "Condition", Sample Condition 1c20 2c20 3c10 4c10 5c9 6c9 7c5 8c5 9c20 10 c10 Could you let me know the fastest way to change c20->