I don't know if it's "the fastest" way, but you can get there with
as.character(factor(exData$Condition, levels=c("c20", "c10", "c9",
"c5"), labels=c("AA", "BB", "CC", "DD")))
-Ista
On Mon, Nov 9, 2009 at 2:06 PM, phoebe kong <sityeek...@gmail.com> wrote:
> Hi All,
>
> I have a dataset with a column named "Condition",
>
>
> Sample Condition
> 1 c20
> 2 c20
> 3 c10
> 4 c10
> 5 c9
> 6 c9
> 7 c5
> 8 c5
> 9 c20
> 10 c10
>
> Could you let me know the fastest way to change c20->"AA", c20->"BB",
> c9->"CC", c5->"DD" without using for loop?
>
> Thanks
> phoebe
>
> [[alternative HTML version deleted]]
>
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--
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org
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