Thanks, for suggestions (To define p before).
I thought it and I put this line of code inside the loop:
p[i] <- y[i] / n[i]
but I received a RUNTIME ERROR and:
(Attempt to redefine node p[1]).
Thanks
Massimiliano
Il giorno mar 1 giu 2021 alle ore 17:22 Bert Gunter
ha scritto:
> Where is p defin
Unless you have got reason not to, always reply to the list (included in
this response). I cannot help, but someone else may be able to.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom Co
Where is p defined before it is used? (Is this part of what jags provides
somehow?)
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Jun 1, 2021 at 7:57 AM
Dear R users,
I'm trying to reproduce the example 6.5.1 (Dobson (1983)) in BUGS book in
linux using JAGS.
Below the code as
https://www.mrc-bsu.cam.ac.uk/software/bugs/the-bugs-project-the-bugs-book/bugs-book-examples/the-bugs-book-examples-chapter-6-6-5-1/
# By R code:
library('rjags')
jags <
Dear Rui,
Based on the rules given in the link below, I want to transform the binary
numbers into latitude and longitude coordinates (in degrees and minutes),
so that is basically what I am trying to accomplish. The first integer
gives the sign (positive or negative) of the number, and the rest n-
Please post in plain text format. Only you have the power to format your
email the way we will see it... using the default HTML format only leads
to odd wraparounds and weird characters that you don't know about when you
send but we have to wade through when we recieve it.
"Character" data is
Hi Fahman,
That error message usually means that there is no newline at the end
of the last line of the input file. Try adding a newline,
Jim
On Tue, Jun 14, 2016 at 1:17 AM, Fahman Khan via R-help
wrote:
> I have written a following piece of code.
>> binaryFile <- file("sampleBinary.dat", 'rb'
I have written a following piece of code.
> binaryFile <- file("sampleBinary.dat", 'rb')>readBin(binaryFile, character(),
> endian="little")
I'm getting a warning message that says
Warning message: In readBin(binaryFile, chracter(), endian="little") :
incomplete string at end of file has been
Hi All,
For Binary Classification / Logistic Regression Models, Is there a specific
preference or standard of what metric to be used for comparison of 2 models,
especially when the model types are different - e.g logistic regression vs svd
vs gbm vs neural networks?
As I understand AUC is the
rawConnection did it!!
Thank you very much!!!
From: Prof Brian Ripley [rip...@stats.ox.ac.uk]
Sent: Wednesday, July 30, 2014 4:14 PM
To: Ramiro Barrantes; r-help@r-project.org
Subject: Re: [R] binary to R object
What type actually is 'binary'
What type actually is 'binary' here? We cannot tell, as writeBin will
handle many types.
If 'binary' means a raw vector, two ways:
1) Use load() on a raw connection (see ?rawConnection).
2) Make use of the information in ?readRDS. You can read the header
from save() format by skipping the f
Hello,
I have stored R objects as hexadecimals in a mysql database, I then usually
transform them to binary and then save it into a file. E.g.
hex <- getBlob #gets blob from database as hexadecimal
binary <- transformToBinary(hex) #moves from hex to binary
I would usually save them into
Hi,
You could try:
Either:
dat1 <- read.table("Test.txt",header=TRUE)
dim(dat1)
#[1] 4735 4735
dat2 <- read.table("1991res.txt",header=TRUE)
dim(dat2)
#[1] 574 574
m1 <- as.matrix(dat1)
m2 <- as.matrix(dat2)
library(data.table)
d1 <-
data.table(Name1=as.vector(outer(rownames(m1),colnames(m1),past
Hi Elio,
Use ?write.table()
write.table(res,"Eliores.txt",quote=FALSE)
#and as read the file
mat1<- as.matrix(read.table("Eliores.txt",header=TRUE))
#or even this should work
mat1<- as.matrix(read.table("Eliores.txt"))
#If you have very big matrix, you may try:
library(tseries)
write(res,"Elior
Hi Arun,
I get the following error when I enter the command:
library(reshape2)
Error in library(reshape2) : there is no package called âreshape2â
Any ideas?
Thanks again.
On Fri, Sep 20, 2013 at 3:09 PM, arun kirshna [via R] <
ml-node+s789695n4676569...@n4.nabble.com> wrote:
> Hi Eli
Hi Elio,
Try this:
library(stringr)
lines1<-str_trim(gsub("\t"," ",readLines("elio.txt")))
lst1<-lapply(split(lines1,cumsum(lines1=="")),function(x) x[x!=""])
lst2<- lapply(lst1[lapply(lst1,length)>0],function(x)
as.matrix(read.table(text=x,row.names=1)))
names(lst2)<- paste0("m",seq_along(lst
Hi Arun,
Worked perfectly, one last question how to read the matrices which have the
dollar sign?
Thanks again.
On Thu, Sep 19, 2013 at 3:46 PM, arun kirshna [via R] <
ml-node+s789695n4676510...@n4.nabble.com> wrote:
> Hi Elio,
> Try this:
> library(stringr)
> lines1<-str_trim(gsub("\t"," ",r
Hi Elio,
Try this:
library(stringr)
lines1<-str_trim(gsub("\t"," ",readLines("elio.txt")))
lst1<-lapply(split(lines1,cumsum(lines2=="")),function(x) x[x!=""])
lst2<- lapply(lst1[lapply(lst1,length)>0],function(x)
as.matrix(read.table(text=x,row.names=1)))
names(lst2)<- paste0("m",seq_along(lst2
Hi,
I have another question related to the same problem. I have a text file
with about 350 matrices each separated by a blank row. My question is how
to make R believe each matrix is separate and has a specific name m1,
m2,m350. Below is an example:
aa5 aa10 b253 b254 aa5 0 1 1 1 aa10 1 0
Hi Elio,
Try this:
Assuming that there is a single blank row separating the matrices:
lines1<- readLines(textConnection("aa5 aa10 b253 b254
aa5 0 1 1 1
aa10 1 0 1 1
b253 1 1 0 1
b254 1 1 1 0
aa5 aa9 b27
HI,
No problem. Suppose you have many matrices and you want to sum up the repeated
variables, may be this helps:
#Creating one more matrix which has some repeated variables.
m6<- as.matrix(read.table(text="y1 e5 s2
y1 0 1 1
e5 1 0 1
s2 1 1 0",sep="",header=TRUE))
#m1:m5 same as previous
dat
Hi,
May be this helps:
m1<- as.matrix(read.table(text="
y1 g24
y1 0 1
g24 1 0
",sep="",header=TRUE))
m2<-as.matrix(read.table(text="y1 c1 c2 l17
y1 0 1 1 1
c1 1 0 1 1
c2 1 1 0 1
l17 1 1 1 0",sep="",header=TRUE))
m3<- as.matrix(read.table(text="y1 h4 s2 s30
y1 0 1 1 1
h4 1 0 1 1
s2 1
HI,
No problem.
I think you didn't run the `vecOut` after adding the new matrix. `lst1` is
based on `vecOut`
For example:
m5<- as.matrix(read.table(text="y1 e6 l16
y1 0 1 1
e6 1 0 1
l16 1 1 0",sep="",header=TRUE))
names1<-unique(c(colnames(m1),colnames(m2),colnames(m3),colnames(m4),
colnames(m5
Also, some of the steps could be reduced by:
names1<-unique(c(colnames(m1),colnames(m2),colnames(m3),colnames(m4)))
Out3<-matrix(0,length(names1),length(names1),dimnames=list(names1,names1))
lst1<-sapply(paste0("m",1:4),function(x) {x1<- get(x);
x2<-paste0(colnames(x1)[col(x1)],rownames(x1)[row(x
9:56 AM
To: r-help@r-project.org
Subject: [R] binary distance measure of the "dist" function in
the "stats" package
Dear all:
I want to ask question about "binary" distance measure. As
far as I
know, there are many binary distance measures,eg, binary
Jarcad distan
Dear all:
I want to ask question about "binary" distance measure. As far as I
know, there are many binary distance measures,eg, binary Jarcad distance,
binary euclidean distance, and binary Bray-Curtis distance,etc. It is even
more confusing because many have more than one name. So , I wan to k
Re-posting, particularly without referencing your earlier post, is bad
mailing-list etiquette. Posting in HTML is particularly frowned upon here also.
Nor is this a statistical methods support forum... it is about R. I for one am
finding your question very jargonish and obscure. If your question
Dear R Users,
I have always used ASReml, MTDFREML, SAS, etc. to estimate genetic correlation
(Rg) between two continuous quantitative traits (also continuous and binary
trait) but I have never used R package to estimate Rg. However, I use R package
for many of my other statistical analysis needs
Dear R Users,
I have always used ASReml, MTDFREML, SAS, etc. to estimate genetic correlation
(Rg) between two continuous quantitative traits (also continuous and binary
trait) but never used R to estimate Rg. However, I use R for many of my other
statistical analysis needs; the R package is a gr
or of Anthropology
Texas A&M University
College Station, TX 77843-4352
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Juan Fernández Tajes
> Sent: Tuesday, September 04, 2012 3:19 AM
> To: r-help@r-project.org
&g
Dear list,
Hello to everybody, I´m interested in finding a package for statistical
analysis of binary data, I have a matrix with the following structure:
Case1 Case2 Case 3 ... CaseX Control1 Control2 Control3 ... ControlY
Pep1 1 0 1 1 0 0 0 1
Pep2 1 1 1 1 1 0 0 1
Pep3 0 1 1 1 1 0
Hi Bert,
I won't post any more messages on this thread as problem has shifted from
Optimization in R to Graph Algorithms.
Rest fine
Khris.
On Aug 2, 2012, at 9:13 PM, Bert Gunter [via R] wrote:
> This discussion needs to be taken off (this) list, as it appears to
> have nothing to do with R.
Thanks for the response Petr
On Aug 2, 2012, at 11:11 PM, Petr Savicky [via R] wrote:
> On Thu, Aug 02, 2012 at 02:27:43AM -0700, khris wrote:
>
> >
> > On Aug 2, 2012, at 12:39 PM, Petr Savicky [via R] wrote:
> >
> > > On Wed, Aug 01, 2012 at 04:55:30AM -0700, khris wrote:
> > > > Hi Petr,
On Thu, Aug 02, 2012 at 02:27:43AM -0700, khris wrote:
>
> On Aug 2, 2012, at 12:39 PM, Petr Savicky [via R] wrote:
>
> > On Wed, Aug 01, 2012 at 04:55:30AM -0700, khris wrote:
> > > Hi Petr,
> > >
> > > It been sometime since I wrote. But here are the latest developments.
> > >
> > > When I
This discussion needs to be taken off (this) list, as it appears to
have nothing to do with R.
-- Bert
On Thu, Aug 2, 2012 at 2:27 AM, khris wrote:
>
> On Aug 2, 2012, at 12:39 PM, Petr Savicky [via R] wrote:
>
>> On Wed, Aug 01, 2012 at 04:55:30AM -0700, khris wrote:
>> > Hi Petr,
>> >
>> > It
On Aug 2, 2012, at 12:39 PM, Petr Savicky [via R] wrote:
> On Wed, Aug 01, 2012 at 04:55:30AM -0700, khris wrote:
> > Hi Petr,
> >
> > It been sometime since I wrote. But here are the latest developments.
> >
> > When I give the binary linear opt problem to lpSolve optimizer than for
> > sm
On Wed, Aug 01, 2012 at 04:55:30AM -0700, khris wrote:
> Hi Petr,
>
> It been sometime since I wrote. But here are the latest developments.
>
> When I give the binary linear opt problem to lpSolve optimizer than for small
> instance it gives correct answer but when size of nodes increase let's
Hi Petr,
It been sometime since I wrote. But here are the latest developments.
When I give the binary linear opt problem to lpSolve optimizer than for small
instance it gives correct answer but when size of nodes increase let's say 16
then there are about 2000 binary variables and lpSolve just
Thanks Petr for the reply.
Let me do implementation and see how how goes.
Enjoy your vacation.
Rest fine
Khris
On Jul 4, 2012, at 8:25 PM, Petr Savicky [via R] wrote:
> On Mon, Jul 02, 2012 at 06:11:37AM -0700, khris wrote:
>
> > Hi, Petr,
> >
> > >
> > > Hi Khris:
> > >
> > > If i unders
On Mon, Jul 02, 2012 at 06:11:37AM -0700, khris wrote:
> Hi, Petr,
>
> >
> > Hi Khris:
> >
> > If i understand the problem correctly, you have a list of (x,y)
> > coordinates, where
> > some sensor is located, but you do not know, which sensor is there. The
> > database
> > contains data fo
Hi, Petr,
>
> Hi Khris:
>
> If i understand the problem correctly, you have a list of (x,y) coordinates,
> where
> some sensor is located, but you do not know, which sensor is there. The
> database
> contains data for each sensor identified in some way, but you do not know the
> mapping be
On 6/27/2012 3:20 AM, Peppino wrote:
Hi I am new with R
I Have to build a binary tree with R. I'm very confused was wondering if
anyone had any R sample code they would share.
Any bady can help me?
You might want to look at the R Task view for phylogenetics:
http://cran.r-project.org/web/views
Hi Menkes,
Thanks for the reply but just academically free license won't work for me. GNU
or more is reqd.
Rest fine
Khris.
On Jun 30, 2012, at 7:21 PM, menkes [via R] wrote:
> Hi Khris,
>
> If all your variables are binary then you may want to check CPLEX and/or
> Gurobi (both provide a
Hi Khris,
If all your variables are binary then you may want to check CPLEX and/or
Gurobi (both provide a free academic license).
http://www-01.ibm.com/software/integration/optimization/cplex-optimizer/
http://www.gurobi.com/products/additional-products-using-gurobi/r
The algorithms that CPLEX a
On Tue, Jun 26, 2012 at 11:52:15PM -0700, khris wrote:
> Hi Petr,
>
> Appreciate your feedback and sorry for the delay in responding. The
> following is the description of problem from start:-
>
> We have a set of sensors in XY plane arranged in more or less a rectangular
> grid and we know thei
Hi I am new with R
I Have to build a binary tree with R. I'm very confused was wondering if
anyone had any R sample code they would share.
Any bady can help me?
Bye
Giuseppe
--
View this message in context:
http://r.789695.n4.nabble.com/binary-tree-tp4634593.html
Sent from the R help mailin
Hi Petr,
Appreciate your feedback and sorry for the delay in responding. The
following is the description of problem from start:-
We have a set of sensors in XY plane arranged in more or less a rectangular
grid and we know their (x,y) co-ordinate. Now these sensors send data and
from that data
On Thu, Jun 21, 2012 at 02:46:10AM -0700, khris wrote:
> Hi Petr,
>
> Thanks for the reply. Your reply answers the question perfect.
> Unfortunately converting the problem to linear opt would increase the number
> of variable making it non solvable. I guess a general approach will be
> unfeasible
Hi Petr,
Thanks for the reply. Your reply answers the question perfect.
Unfortunately converting the problem to linear opt would increase the number
of variable making it non solvable. I guess a general approach will be
unfeasible so need to look for specific approach.
Appreciate if you have any
On Jun 20, 2012, at 5:18 PM, Anthony Damico wrote:
Thanks Michael,
I was hoping to complete this in one step (since I use these a lot).
Setting the class of the vectors seems like more typing than just
doing %>F% ...
Unfortunately, my knowledge of classes, methods, and the like is
pretty sha
On 12-06-20 4:44 PM, Anthony Damico wrote:
Hi, I work with data sets with lots of missing values. We often need
to conduct logical tests on numeric vectors containing missing values.
I've searched around for material and conversations on this topic,
but I'm having a hard time finding anything.
Hello, again.
I have two apologies, to the list for having forgotten to cc my previous
reply to this thread, and to you for not having understood that you
wanted it solved in one step. My solution would need two steps.
Now revised.
no.na <- function(x, value=FALSE){x[is.na(x)] <- value; x}
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Anthony Damico
> Sent: Wednesday, June 20, 2012 2:19 PM
> To: R. Michael Weylandt
> Cc: r-help@r-project.org
> Subject: Re: [R] binary operators th
On Wed, Jun 20, 2012 at 4:18 PM, Anthony Damico wrote:
> Thanks Michael,
>
> I was hoping to complete this in one step (since I use these a lot).
> Setting the class of the vectors seems like more typing than just
> doing %>F% ...
Hmmm. my way save you 3 characters (and three shifts!) per
co
Thanks Michael,
I was hoping to complete this in one step (since I use these a lot).
Setting the class of the vectors seems like more typing than just
doing %>F% ...
Unfortunately, my knowledge of classes, methods, and the like is
pretty shaky. Is it possible to *create* another set of operator
Hi Anthony,
No, I don't believe this exists on CRAN already (happy to be proven
wrong though) but I might suggest you approach things a different way:
instead of defining this operator by operator with infix notation, why
not go after `+`, `>` directly? If you put a class on your vectors,
you can
I'm not sure I got the question but is this something like what you want?
x[is.na(x) ] <- "FALSE"
x
John Kane
Kingston ON Canada
> -Original Message-
> From: ajdam...@gmail.com
> Sent: Wed, 20 Jun 2012 16:44:25 -0400
> To: r-help@r-project.org
&
Hi, I work with data sets with lots of missing values. We often need
to conduct logical tests on numeric vectors containing missing values.
I've searched around for material and conversations on this topic,
but I'm having a hard time finding anything. Has anyone written a
package that deals with
On Fri, Jun 15, 2012 at 05:17:36PM +0530, Anup Bhatkar wrote:
> Hello,
>
> I have to solve Binary Quadratic Optimization problem i.e the objective
> function is quadratic, constraints are linear and variable are binary. I
> checked the "quadprog" package but it does not seem to be right choice f
Hello,
I have to solve Binary Quadratic Optimization problem i.e the objective
function is quadratic, constraints are linear and variable are binary. I
checked the "quadprog" package but it does not seem to be right choice for the
problem.
Can any one suggest what would be the best package to
Ey R-people
Trying to do a binary logistic regression with only
categorical(age,ballot) and binary predictors for a binary response
variable. I can model them at least at least i treat the binary
predictors as categorical with the use of as.factor(etc) and use glm
with binomial distribution
http://r.789695.n4.nabble.com/file/n4040429/model.jpg
Hi All
I need some help about construct MLE logit for Binary Autogressive Moving
Average model.
Please see the model in the PDF attach file.
This is what i did.
y<-c(0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1) # y
is
Michael Haenlein escpeurope.eu> writes:
> Dear all,
>
> I would like to solve a problem similar to a multiple knapsack problem and
> am looking for a function in R that can help me.
>
> Specifically, my situation is as follows: I have a list of n items which I
> would like to allocate to m grou
Dear all,
I would like to solve a problem similar to a multiple knapsack problem and
am looking for a function in R that can help me.
Specifically, my situation is as follows: I have a list of n items which I
would like to allocate to m groups with fixed size. Each item has a certain
profit v
try this:
> x <- c(36, 40, 10, 4)
> x.m <- matrix(as.integer(intToBits(x)), byrow = TRUE, ncol = 32)[, 1:20]
> x.m <- data.frame(x.m) # convert to data.frame
> x.m
X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12 X13 X14 X15 X16 X17 X18 X19 X20
1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0
Happy weekend helpeRs!
As usual, I'm stumped by R...
My plan was to take an integer number, convert it to binary and wind
up with a data.frame where each column is either 1 or 0 so I can see
which bits are changing:
bb<-function(i) ifelse(i, paste(bb(i %/% 2), i %% 2, sep=""), "")
my.dat<-c(36,4
Jürg.
It's not that nobody knows the answer, necessarily, it's that your
inquiry is so vague we don't know what the *question* is, let alone
the answer.
We don't know anything about your data, your intended function and
model, anything.
A toy reproducible example with clear explanation would be
Does really nobody has a coment to this question?
Dear R-help members
I would like to use the R package goalprog, weighted and lexicographical goal
programming and optimization to optimize a location problem.
In my model I need a "yes" or "no" decision - in this case, whether to select a
site
Dear R-help members
I would like to use the R package goalprog, weighted and lexicographical goal
programming and optimization to optimize a location problem.
In my model I need a "yes" or "no" decision - in this case, whether to select a
site or not - are represented by 1 and 0.
Does somebody
Hi Josh,
Thank you for your reply.
The reason I thank "Y" (0 and 1) here as p is because I think each
observation is just a bernulli trial, so in this case the binomial n=1. And
yet R still fits it (with the logit link) . I know the expression for the
logit link, so I assumed I can take y here as
Hi,
Y is not the same as P. P is the conditional probability given the
data matrix. So theoretically, P can take on any value in [0, 1],
which means the odds can be anywhere from [0, +infty], not just 0 or
undefined. In logistic regression, the logit link is pretty standard,
so I do not think y
Hi all,
I have a problem with binary response data in GLM fitting.
The problem is that the "y" take only 1 or 0, and if I use logit link, it is
the log of the odds ratio, which is p/(1-p). In my situation, think "y" is
"p", so sometimes the odds is 0, sometimes it is "1/0", which is (should be)
un
Rob,
If 'sex' is indeed an exogenous variable (ie. predictor only), you can
simply code it as (1=male, 2=female) and use it as a covariate in any sem
model. In lavaan, you can explicitly use the argument 'fixed.x=TRUE', which
will regard all exogenous covariates as fixed variables. Their
means/var
Dear posters,
I have a question concerning binary data analysis. I have presence absence
data of 5 sampling sessions within 3 years, of 12 fields. Each field had 12
traps. I would like to analyse the data with a Generalized Estimating
Equations (GEE) Model in R. For the abundance data I used a gls
Hello all
I'm trying to run some path analysis in either sem or lavaan (preferably lavaan
because I find its interface easier to use). Most of my variables are
continuously distributed and fairly well-behaved but I have a single exogenous
variable (sex) which is not continuously distributed. Pr
On Tue, Oct 05, 2010 at 06:13:04PM -0400, Mike Marchywka wrote:
> I guess it wouldn't be too far a field to discuss benefits
> of data stucture exploration in R vs cpp or java- Especially
> for something like this where you may want to time it in a multithreaded
> setting- you can always instrume
inary_tree
> From: marchy...@hotmail.com
> To: matl...@cs.ucdavis.edu; r-help@r-project.org
> > Date: Tue, 5 Oct 2010 14:57:40 -0700
> > From: matl...@cs.ucdavis.edu
> > To: r-help@r-project.org
> > Subject: Re: [R] binary tree
> Date: Tue, 5 Oct 2010 14:57:40 -0700
> From: matl...@cs.ucdavis.edu
> To: r-help@r-project.org
> Subject: Re: [R] binary tree construction in R
>
> MK wrote:
>
> > Hi all,
> >
> > I'm very new to R a
MK wrote:
> Hi all,
>
> I'm very new to R and I'm trying to construct a threaded binary tree using
> recursive functions.
>
> I'm very confused was wondering if anyone had any R sample code they would
> share. I've come across a lot of C++ code(nothing in R) and this is not
> helping.
>
> best,
Hi all,
I'm very new to R and I'm trying to construct a threaded binary tree using
recursive functions.
I'm very confused was wondering if anyone had any R sample code they would
share. I've come across a lot of C++ code(nothing in R) and this is not
helping.
best,
MK
--
View this message
You have to build a *source* package under Linux in order to install it
under Windows afterwards. A Linux binary package cannot be used under
Windows.
Best,
Uwe Ligges
On 31.08.2010 09:59, raje...@cse.iitm.ac.in wrote:
Hi,
I built a package in linux and generated its binary using R CM
Hi,
I built a package in linux and generated its binary using R CMD build --binary
testpack. This generated testpack.tar.gz.
I tried to install this package in windows using R CMD INSTALL package.tar.gz
and I got the error
*installing to library 'H:/R-2.11.1/library'
*installing *bina
The bootcov function for models fit using lrm in the rms package might also
be an option
hth
--
View this message in context:
http://r.789695.n4.nabble.com/binary-logistic-regression-taking-account-clustering-tp2122255p2122311.html
Sent from the R help mailing list archive at Nabble.com.
_
See
help(lmer, package="lme4")
for a mixed-effects model approach. See
help(geeglm, package="geepack")
for a GEE approach.
-tgs
On Sat, May 1, 2010 at 1:52 PM, kende jan wrote:
> Hello
>
> I would like to perform with R, a binary logistic regression analysis
> taking account clustering
>
Hello
I would like to perform with R, a binary logistic regression analysis taking
account clustering
(A randomized trial into 2 groups, patients within 50 hospitals):
y (0,1) is the outcome
x1, x2 indivifdualâs characteristics
x3,x4 hospitalsâ characteristics.
Thanks in advance
Jan
I am using PROC LOGISTIC to model binary outcomes.
I have observed Y (1 or 0) from original data.
I also have got predicted probability for each observation (i.e. predicted
probability of event Y=1) from PROC LOGISTIC. Let us call it - p_hat.
for example, I would have two columns -
Y p_hat
Val wrote:
Hi all
Assume I have a data set xx;
Group: 1=group1 , 2=group2
IQ: 1= High, 0 =low
fit <- glm(IQ ~group, data = xx, family = binomial())
summary(fit)
Results
Estimate Std. Error z value Pr(>|z|)
(Intercept) -2.554560.210 -12.273 < 5e-16 ***
group
Thanks for your response.
Do you mean that both the log-odds and odd ratio have the same meaning?
My question is that the log-odd estimate 0.3618 is it for group1 or group2?
normally 1vs2, glm takes 2 as reference, in the group1 the IQ increase
by 0.3618compared to group 2
What does
Hi val,
Val a écrit :
Hi all
Assume I have a data set xx;
Group: 1=group1 , 2=group2
IQ: 1= High, 0 =low
fit <- glm(IQ ~group, data = xx, family = binomial())
summary(fit)
Results
Estimate Std. Error z value Pr(>|z|)
(Intercept) -2.554560.210 -12.273 < 5e-16 **
Hi all
Assume I have a data set xx;
Group: 1=group1 , 2=group2
IQ: 1= High, 0 =low
fit <- glm(IQ ~group, data = xx, family = binomial())
summary(fit)
Results
Estimate Std. Error z value Pr(>|z|)
(Intercept) -2.55456 0.210 -12.273 < 5e-16 ***
group 0.36180
Hi,
I'm trying to make a package defining a new (S3?) class. Part of this
involves a custom version of a binary operator. e.g. "*.foo", so I can
do obj.foo * bar, or things like that.
Now, I think to makes this work with a NAMESPACE, I can do
S3method("*", foo)
in the NAMESPACE file, right? The
karuna m wrote:
>
> hi,
> I am trying to calculate distance matrices for binary data frame. I am
> using dist.binary in 'ade4' package. This is the code i run and get error
> message as 'missing value where True/False needed:
> clss <- as.data.frame(cls)
> dist.binary(clss, method = 1, diag = F
hi,
I am trying to calculate distance matrices for binary data frame. I am using
dist.binary in 'ade4' package. This is the code i run and get error message as
'missing value where True/False needed:
clss <- as.data.frame(cls)
dist.binary(clss, method = 1, diag = FALSE, upper = FALSE)
Also, if i
On Tue, 10 Nov 2009, Gavin Simpson wrote:
On Mon, 2009-11-09 at 19:31 -0600, Peng Yu wrote:
On Sun, Nov 8, 2009 at 7:32 PM, John Fox wrote:
Dear Peng,
I'm tempted to try to get an entry in the fortunes package but will instead
try to answer your questions directly:
I can not install 'fortu
Hello,
I was wondering if anyonw knows any reference or package about binary quantile
regression with IV.
I know that Kordas post "S-plus" package in his website. But I don't have
S-plus.
Furthermore, my friends told mw that his package is not recognized by S-plus 8.
Hence, I
- Original Message -
From: "Peter Dalgaard"
To: "Steven Rytina, Prof."
Cc:
Sent: Sunday, August 09, 2009 6:35 AM
Subject: Re: [R] binary operators that implement row and column sweeps of
matrices by vectors
Steven Rytina wrote:
Submitted
Steven Rytina wrote:
Submitted for perusal, comment, improvements, and/or critique.
The presentation is in 3 sections: motivation, code, and comment.
Motivation:
As a new-comer to R from matrix oriented Gauss and Mata, I miss the
tools for using a vector
Submitted for perusal, comment, improvements, and/or critique.
The presentation is in 3 sections: motivation, code, and comment.
Motivation:
As a new-comer to R from matrix oriented Gauss and Mata, I miss the
tools for using a vector (and operator) to sweep
Does R has package for providing work for binary digit: arithmetic
operation, convert to/from decimal digit, etc? I not found it, but think
that CRAN contain it.
[[alternative HTML version deleted]]
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;s my first attempt to
> build it myself, and I have downloaded the binaries and installed it
> previously.
>
>
> --- On Wed, 4/8/09, stephen sefick wrote:
>
>> From: stephen sefick
>> Subject: Re: [R] binary version of R 2.8.x
>> To: tomkur2006-takeh...@y
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