Happy weekend helpeRs! As usual, I'm stumped by R...
My plan was to take an integer number, convert it to binary and wind up with a data.frame where each column is either 1 or 0 so I can see which bits are changing: bb<-function(i) ifelse(i, paste(bb(i %/% 2), i %% 2, sep=""), "") my.dat<-c(36,40,10,4) my.binary.dat<-bb(my.dat) my.list<-strsplit(my.binary.dat,'') max.len<-max(ldply(my.list,length)) len<-length(my.list) my.df<-data.frame(two=rep(0,len),four=rep(0,len),eight=rep(0,len),sixteen=rep(0,len),thirtytwo=rep(0,len),sixtyfour=rep(0,len)) for(i in 1:length(my.list)){ for(j in 1:length(my.list[[i]])){ my.df[i,max.len-length(my.list[[i]])+j]<-my.list[[i]][j] } } But this isn't exactly feasable on a million+ rows where some binary numbers are 20 digits... I know theres a way without loops I just know it! Ideally, I can do this to multiple columns of a data.frame and have them named accordingly (V1.two,V1.four... V2.two,V2.four, etc.) Thanks, Justin ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.