Hi,
Try this,
df.sort<-apply(df,2,sort)
> df.sort
x
A 1
D 2
I 2
B 3
J 8
G 12
H 33
E 34
F 44
C 51
df.sort<-as.data.frame(df.sort)
A.K.
- Original Message -
From: Johannes Radinger
To: R-help@r-project.org
Cc:
Sent: Friday, June 8, 2012 3:22 AM
Subject: [R] Sort
Hi Achim,
thank you for your good explanation and the solution to my
question...
cheers,
/j
Original-Nachricht
> Datum: Fri, 8 Jun 2012 09:30:42 +0200 (CEST)
> Von: Achim Zeileis
> An: Johannes Radinger
> CC: R-help@r-project.org
> Betreff: Re: [R] Sort 1-c
Hi Johannes,
You need to add the drop=FALSE argument in order to keep the structure:
df.sort <- df[order(df[,"x"]), , drop=FALSE] ## don't forget the extra
comma
See ?"[" for details
HTH,
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000
On Fri, 8 Jun 2012, Johannes Radinger wrote:
Hi,
I have a 1-column dataframe with rownames and I want to sort it
based on the single column. The typical procedure that is recommended
in diverse posts is to use order in the index. But that "destroys" my
dataframe structure. Probabaly it is a ver
Hi,
I have a 1-column dataframe with rownames and I want to sort it
based on the single column. The typical procedure that is recommended
in diverse posts is to use order in the index. But that "destroys" my
dataframe structure. Probabaly it is a very simple solution. Here is a
short reproducable
5 matches
Mail list logo
