Hi Johannes,
You need to add the drop=FALSE argument in order to keep the structure:
df.sort <- df[order(df[,"x"]), , drop=FALSE] ## don't forget the extra
comma
See ?"[" for details
HTH,
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
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ivan.calan...@u-bourgogne.fr
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Le 08/06/12 09:22, Johannes Radinger a écrit :
Hi,
I have a 1-column dataframe with rownames and I want to sort it
based on the single column. The typical procedure that is recommended
in diverse posts is to use order in the index. But that "destroys" my
dataframe structure. Probabaly it is a very simple solution. Here is a
short reproducable example:
x<- c(1,3,51,2,34,44,12,33,2,8)
df<- data.frame(x)
rownames(df)<- c("A","B","C","D","E","F","G","H","I","J")
df.sort<- df[order(df[,"x"]),]
/Johannes
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