> I think that I need to
> draw a Hypercube sample for each age class (i.e., for 0, 1, 2, 3, 4, 5, 6, 7)
> in a
> given simulation (i.e., N = 1) and the LHS values for all age classes should
> be
> like the observed cumulative distribution (see attached figure).
> output of randomLHS should be a
Thanks for your answer.
I have attached the plot for representing the variable. I think that I need to
draw a Hypercube sample for each age class (i.e., for 0, 1, 2, 3, 4, 5, 6, 7)
in a given simulation (i.e., N = 1) and the LHS values for all age classes
should be like the observed cumulative
> However, my variable is simulated from the cumulative distribution function
> of the Poisson distribution.
Then I am afraid I don't know what you're trying to achieve.
Or why.
However, the principle holds; write a function that maps [0,1] to the 'pattern'
you want, do that and apply it to the
Thanks for your answer.
However, my variable is simulated from the cumulative distribution function of
the Poisson distribution. So, the pattern obtained from the function "qpois" is
not the same as the observed pattern (i.e., obtained from the function "ppois")
set.seed(5)
mortality_probabili
> How can I draw a Hypercube sample for the variable mortality_probability so
> that this variable exhibits the same pattern as the observed distribution?
One simple way is to use the uniform random output of randomLHS as input to the
quantile function for your desired distribution(s).
For exa
Hello,
I am performing a sensitivity analysis using a Latin Hypercube sampling.
However, I have difficulty to draw a Hypercube sample for one variable. I�ve
generated this variable from a Poisson distribution as follows:
set.seed(5)
mortality_probability <- round(ppois(seq(0, 7, by = 1), lambda
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