On 31-12-2012, at 03:24, meng wrote:
>
> I type:
> dat*rep(z,rach=nrow(dat))
> "rach" is "each" indeed,but I type "rach" mistakenly.
> What's strange to me is :No error reply appears,but show me the result:
>> dat*rep(z,rach=nrow(dat))
> x1x2x3
> 1 0.1 0.4 0.7
> 2 20.0 50.0
(dat))
# x1 x2 x3
#1 0.1 40 700
#2 0.2 50 800
#3 0.3 60 900
A.K.
- Original Message -
From: meng
To: Andrius Druzinis
Cc: R help
Sent: Sunday, December 30, 2012 9:24 PM
Subject: Re: [R] How to multiple the vector and variables from dataframe
Hi Andrius:
Thanks for your reply.
Your
>
>
>- Original Message -----
>From: meng
>To: Andrius Druzinis
>Cc: R help
>Sent: Sunday, December 30, 2012 9:24 PM
>Subject: Re: [R] How to multiple the vector and variables from dataframe
>
>Hi Andrius:
>Thanks for your reply.
>Your answer: dat*rep(z,each=n
,z,"*"))
>#'data.frame':3 obs. of 3 variables:
># $ x1: num 2 5 8
># $ x2: num 120 200 300
># $ x3: num 2500 5000 6200
>A.K.
>
>
>
>
>
>
>
>From: meng
>To: arun
>Cc: R help
>Sent: Sunday, De
$ x3: num 2500 5000 6200
A.K.
From: meng
To: arun
Cc: R help
Sent: Sunday, December 30, 2012 9:40 PM
Subject: Re:Re: [R] How to multiple the vector and variables from dataframe
Hi,arun:
Yes,your answer is what I want.
A little different is :
data.frame(t(t(dat)*z))
Becau
s 100, which is confusing.
> t(t(dat)*z)
>#x1 x2 x3
>#[1,] 2 120 2500
>#[2,] 5 200 5000
>#[3,] 8 300 6200
>
>A.K.
>
>
>
>
>
>
>
>- Original Message -----
>From: meng
>To: R help
>Cc:
>Sent: Sunday, December 30, 2012 5:26 AM
>
Hi Berend:
Thanks for your reply.
dat<-data.frame(x1=1:3,x2=4:6,x3=7:9)
z<-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
Option2 is similar as "dat*rep(z,each=length(z))",and the latter is simpler
than Option2 in expression.
At 2012-12-31 00:31:42,"Berend Hasselman" wrote:
>
>On 30-12-20
The following is also work:
data.frame(t(t(dat)*z))
At 2012-12-31 00:40:24,"Neal H. Walfield" wrote:
>At Sun, 30 Dec 2012 16:28:44 +,
>Andrius Druzinis wrote:
>>
>> Hi Neal,
>>
>> Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
>> multiplied by column. This is
Hi Neal,
Thanks for your reply.
dat<-data.frame(x1=1:3,x2=4:6,x3=7:9)
z<-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
According to your answer:
> as.matrix(dat)*z
x1x2x3
[1,] 0.1 0.4 0.7
[2,] 20.0 50.0 80.0
[3,] 300.0 600.0 900.0
The above is not what I want.
What I want i
Hi Andrius:
Thanks for your reply.
Your answer: dat*rep(z,each=nrow(dat)) works well.
But a strange thing happened:
dat<-data.frame(x1=1:3,x2=4:6,x3=7:9)
z<-c(0.1,10,100)
#I wanna 0.1*x1,10*x2,100*x3
I type:
dat*rep(z,rach=nrow(dat))
"rach" is "each" indeed,but I type "rach" mistakenly.
What's s
d element in your z is 100, which is confusing.
t(t(dat)*z)
# x1 x2 x3
#[1,] 2 120 2500
#[2,] 5 200 5000
#[3,] 8 300 6200
A.K.
- Original Message -
From: meng
To: R help
Cc:
Sent: Sunday, December 30, 2012 5:26 AM
Subject: [R] How to multiple the vector and variables from dataf
Hi Neal,
Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
multiplied by column. This is not the same as multiplying each column by
the respective element in vector c(2, 3).
Andrius
2012/12/30 Neal H. Walfield
> At Sun, 30 Dec 2012 18:26:45 +0800 (CST),
> meng wrote:
> >
>
Hi Meng,
A one-liner would be
dat*rep(z, each=nrow(dat))
Cheers,
Andrius
2012/12/30 meng
> hi all:
> Here's a dataframe(dat) and a vector(z):
>
> dat:
> x1 x2x3
> 0.2 1.2 2.5
> 0.5 2 5
> 0.8 3 6.2
>
> > z
> [1] 10 100 100
>
> I wanna do the following:
> 10*x1,100*x2
At Sun, 30 Dec 2012 16:28:44 +,
Andrius Druzinis wrote:
>
> Hi Neal,
>
> Notice that c(2, 3) gets replicated into c(2, 3, 2, 3, 2, 3) and then
> multiplied by column. This is not the same as multiplying each column by
> the respective element in vector c(2, 3).
I think you mean multiplied by
On 30-12-2012, at 11:26, meng wrote:
> hi all:
> Here's a dataframe(dat) and a vector(z):
>
> dat:
> x1 x2x3
> 0.2 1.2 2.5
> 0.5 2 5
> 0.8 3 6.2
>
>> z
> [1] 10 100 100
>
> I wanna do the following:
> 10*x1,100*x2,1000*x3
>
> My solution is using the loop for z and
At Sun, 30 Dec 2012 18:26:45 +0800 (CST),
meng wrote:
>
> hi all:
> Here's a dataframe(dat) and a vector(z):
>
> dat:
> x1 x2x3
> 0.2 1.2 2.5
> 0.5 2 5
> 0.8 3 6.2
>
> > z
> [1] 10 100 100
>
> I wanna do the following:
> 10*x1,100*x2,1000*x3
>
> My solution is us
hi all:
Here's a dataframe(dat) and a vector(z):
dat:
x1 x2x3
0.2 1.2 2.5
0.5 2 5
0.8 3 6.2
> z
[1] 10 100 100
I wanna do the following:
10*x1,100*x2,1000*x3
My solution is using the loop for z and dat(since the length of z is the same
as ncol of dat),which is t
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