Hi Meng, A one-liner would be dat*rep(z, each=nrow(dat))
Cheers, Andrius 2012/12/30 meng <laomen...@163.com> > hi all: > Here's a dataframe(dat) and a vector(z): > > dat: > x1 x2 x3 > 0.2 1.2 2.5 > 0.5 2 5 > 0.8 3 6.2 > > > z > [1] 10 100 100 > > I wanna do the following: > 10*x1,100*x2,1000*x3 > > My solution is using the loop for z and dat(since the length of z is the > same as ncol of dat),which is tedious. > I wanna an efficient solution to do it . > > Any help? > > Many thanks! > > My best > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
