I see that others have already responded, but will add my point of
view. You indicated that you wanted to take the difference between
pairs of columns and did not specify exactly how many there were; in
your example there were 4 columns (2 pairs). If there were only two,
then the solution from De
Thanks. It helped me a lot.
Ramya
On Mon, Jan 31, 2011 at 6:56 AM, djmuseR [via R] <
ml-node+3248651-1296211736-40...@n4.nabble.com
> wrote:
> Hi:
>
> I won't speak for Jim, as he's more than capable of responding to this
> himself, but I'll give it a shot:
>
> (1) It's not just the 'double per
Hi:
I won't speak for Jim, as he's more than capable of responding to this
himself, but I'll give it a shot:
(1) It's not just the 'double percent sign', it's that slash in between
them, too. Certain operators in R happen to be enclosed between two percent
signs.
%/% is the integer division oper
Try this:
aggregate(t(x), list(gl(2, 2)), FUN = 'diff')
On Sun, Jan 30, 2011 at 11:32 PM, Ramya wrote:
>
> Hi,
>
> I have a Dataframe.
>
> A B C D
> 0.10.7 0.9 0.8
> 0.20 0.60 0.80 0.70
> 0.40 0.80 0.70 0.76
>
> I need a resultant dataframe
>
> (A-B) (C-D)
> -0.6
Hi:
This also works on your example data. Using the 'x' data frame from Jim
Holtman's post,
subset(transform(x, diffAB = A - B, diffCD = C - D), select = c('diffAB',
'diffCD'))
diffAB diffCD
1 -0.6 0.10
2 -0.4 0.10
3 -0.4 -0.06
transform() allows you to do the subtractions in one li
Hi jholtman,
Thanks a ton it just worked. if you dont mind can you explain the code it a
little
sapply(seq(from = 1, by = 2, length = ncol(x) %/% 2), function(a){
+ x[[a]] - x[[a + 1]]
+ })
wat is the purpose of double percent sign and is the sapply the function we
generally use for the Da
try this:
> x
A B CD
1 0.1 0.7 0.9 0.80
2 0.2 0.6 0.8 0.70
3 0.4 0.8 0.7 0.76
> source('clipboard')
> x <- read.table(textConnection("A B C D
+ 0.10.7 0.9 0.8
+ 0.20 0.60 0.80 0.70
+ 0.40 0.80 0.70 0.76"), header = TRUE)
> closeAllConnections()
> sapply(seq
Please take a look at the introduction to R too ...
> df <- read.delim(textConnection(Lines),sep="")
> df
A B CD
1 0.1 0.7 0.9 0.80
2 0.2 0.6 0.8 0.70
3 0.4 0.8 0.7 0.76
> d['A-B'] <- with(df, A-B)
Error in d["A-B"] <- with(df, A - B) : object 'd' not found
> d$v1 <- with(df, A-B)
Erro
Hi,
I have a Dataframe.
A B C D
0.10.7 0.9 0.8
0.20 0.60 0.80 0.70
0.40 0.80 0.70 0.76
I need a resultant dataframe
(A-B) (C-D)
-0.6 0.1
-0.400.1
-0.40 -0.06
Any suggestion would be of a great help
Thanks
Ramya
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