try this:
> x
A B C D
1 0.1 0.7 0.9 0.80
2 0.2 0.6 0.8 0.70
3 0.4 0.8 0.7 0.76
> source('clipboard')
> x <- read.table(textConnection("A B C D
+ 0.1 0.7 0.9 0.8
+ 0.20 0.60 0.80 0.70
+ 0.40 0.80 0.70 0.76"), header = TRUE)
> closeAllConnections()
> sapply(seq(from = 1, by = 2, length = ncol(x) %/% 2), function(a){
+ x[[a]] - x[[a + 1]]
+ })
[,1] [,2]
[1,] -0.6 0.10
[2,] -0.4 0.10
[3,] -0.4 -0.06
>
>
On Sun, Jan 30, 2011 at 8:32 PM, Ramya <ramya.vict...@gmail.com> wrote:
>
> Hi,
>
> I have a Dataframe.
>
> A B C D
> 0.1 0.7 0.9 0.8
> 0.20 0.60 0.80 0.70
> 0.40 0.80 0.70 0.76
>
> I need a resultant dataframe
>
> (A-B) (C-D)
> -0.6 0.1
> -0.40 0.1
> -0.40 -0.06
>
> Any suggestion would be of a great help
>
> Thanks
> Ramya
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Finding-a-Diff-within-a-Dataframe-columns-tp3247943p3247943.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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