tware
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Bert Gunter
> Sent: Thursday, April 25, 2013 7:54 AM
> To: ted.hard...@wlandres.net
> Cc: R mailing list
> Subject: Re: [R] Dec
Well...
WIth the same list,l,as before:
> system.time(x3 <- simplify2array(l))
user system elapsed
2.110.052.20
> system.time(x2 <- f2(l)) ## the matrix(unlist(...)) one
user system elapsed
0.110.000.11
> identical(x2,x3)
[1] TRUE
So kind of a big difference if you
On Apr 25, 2013, at 7:53 AM, Bert Gunter wrote:
> Well, what you really want to do is convert the list to a matrix, and
> it can be done directly and considerably faster than with the
> (implicit) looping of sapply:
>
> f1 <- function(l)sapply(l,"[",1)
> f2 <- function(l)matrix(unlist(l),nr=2)
>
Well, what you really want to do is convert the list to a matrix, and
it can be done directly and considerably faster than with the
(implicit) looping of sapply:
f1 <- function(l)sapply(l,"[",1)
f2 <- function(l)matrix(unlist(l),nr=2)
l <-
strsplit(paste(sample(LETTERS,1e6,rep=TRUE),sample(1:10,1
ary(stringr)
word(sapply(L,paste,collapse=" "),1)
#[1] "A1" "A2" "A3"
A.K.
- Original Message -
From: "ted.hard...@wlandres.net"
To: r-help@r-project.org
Cc:
Sent: Thursday, April 25, 2013 6:16 AM
Subject: [R] Decomposing a List
Greetings!
Thanks, Jorge, that seems to work beautifully!
(Now to try to understand why ... but that's for later).
Ted.
On 25-Apr-2013 10:21:29 Jorge I Velez wrote:
> Dear Dr. Harding,
>
> Try
>
> sapply(L, "[", 1)
> sapply(L, "[", 2)
>
> HTH,
> Jorge.-
>
>
>
> On Thu, Apr 25, 2013 at 8:16 PM, Ted Hard
Dear Dr. Harding,
Try
sapply(L, "[", 1)
sapply(L, "[", 2)
HTH,
Jorge.-
On Thu, Apr 25, 2013 at 8:16 PM, Ted Harding wrote:
> Greetings!
> For some reason I am not managing to work out how to do this
> (in principle) simple task!
>
> As a result of applying strsplit() to a vector of character
Greetings!
For some reason I am not managing to work out how to do this
(in principle) simple task!
As a result of applying strsplit() to a vector of character strings,
I have a long list L (N elements), where each element is a vector
of two character strings, like:
L[1] = c("A1","B1")
L[2] =
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