Hi,
May be this helps.
L<- list(c("A1","B1"),c("A2","B2"),c("A3","B3"))
simplify2array(L)[1,]
#[1] "A1" "A2" "A3"
simplify2array(L)[2,]
#[1] "B1" "B2" "B3"
#or
library(stringr)
word(sapply(L,paste,collapse=" "),1)
#[1] "A1" "A2" "A3"
A.K.
----- Original Message -----
From: "ted.hard...@wlandres.net" <ted.hard...@wlandres.net>
To: r-help@r-project.org
Cc:
Sent: Thursday, April 25, 2013 6:16 AM
Subject: [R] Decomposing a List
Greetings!
For some reason I am not managing to work out how to do this
(in principle) simple task!
As a result of applying strsplit() to a vector of character strings,
I have a long list L (N elements), where each element is a vector
of two character strings, like:
L[1] = c("A1","B1")
L[2] = c("A2","B2")
L[3] = c("A3","B3")
[etc.]
>From L, I wish to obtain (as directly as possible, e.g. avoiding
a loop) two vectors each of length N where one contains the strings
that are first in the pair, and the other contains the strings
which are second, i.e. from L (as above) I would want to extract:
V1 = c("A1","A2","A3",...)
V2 = c("B1","B2","B3",...)
Suggestions?
With thanks,
Ted.
-------------------------------------------------
E-Mail: (Ted Harding) <ted.hard...@wlandres.net>
Date: 25-Apr-2013 Time: 11:16:46
This message was sent by XFMail
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