Re: [R] Correlated variables

2017-03-15 Thread David L Carlson
1 > rbinom(5, 1, prob=prb) [1] 1 0 1 0 1 - David L Carlson Department of Anthropology Texas A&M University College Station, TX 77840-4352 From: Art U [mailto:art.tem...@gmail.com] Sent: Wednesday, March 15, 2017 1:14 PM To: David L Carlson Subject: Re: [R] Correlated variables I h

Re: [R] Correlated variables

2017-03-15 Thread Jim Lemon
Hi Ariel, It all depends upon n: n<-2 x1=rnorm(n,0,1); x2=rnorm(n,0,1); x3=rnorm(n,0,1); if(x1+x2-x3>0.25){ t=rbinom(1, 1, prob=0.25) }else{ t=rbinom(1, 1, prob=0.5) } n<-1 x1=rnorm(n,0,1); x2=rnorm(n,0,1); x3=rnorm(n,0,1); if(x1+x2-x3>0.25){ t=rbinom(1, 1, prob=0.25) }else{ t=rbinom(1, 1,

Re: [R] Correlated variables

2017-03-15 Thread David L Carlson
day, March 15, 2017 9:56 AM To: r-help@r-project.org Subject: [R] Correlated variables Hi, I'm trying to create binary variable which distribution conditioned on other variables. That is what I did, x1=rnorm(n,0,1); x2=rnorm(n,0,1); x3=rnorm(n,0,1); if(x1+x2-x3>0.25){ t=rbinom(1, 1, prob

[R] Correlated variables

2017-03-15 Thread Art U
Hi, I'm trying to create binary variable which distribution conditioned on other variables. That is what I did, x1=rnorm(n,0,1); x2=rnorm(n,0,1); x3=rnorm(n,0,1); if(x1+x2-x3>0.25){ t=rbinom(1, 1, prob=0.25) }else{ t=rbinom(1, 1, prob=0.5) } But I always get this the warning: Warning messag