Hi Ariel,
It all depends upon n:
n<-2
x1=rnorm(n,0,1);
x2=rnorm(n,0,1);
x3=rnorm(n,0,1);
if(x1+x2-x3>0.25){
t=rbinom(1, 1, prob=0.25)
}else{
t=rbinom(1, 1, prob=0.5)
}
n<-1
x1=rnorm(n,0,1);
x2=rnorm(n,0,1);
x3=rnorm(n,0,1);
if(x1+x2-x3>0.25){
t=rbinom(1, 1, prob=0.25)
}else{
t=rbinom(1, 1, prob=0.5)
}
Jim
On Thu, Mar 16, 2017 at 1:56 AM, Art U <art.tem...@gmail.com> wrote:
> Hi,
>
> I'm trying to create binary variable which distribution conditioned on
> other variables. That is what I did,
>
> x1=rnorm(n,0,1);
> x2=rnorm(n,0,1);
> x3=rnorm(n,0,1);
> if(x1+x2-x3>0.25){
> t=rbinom(1, 1, prob=0.25)
> }else{
> t=rbinom(1, 1, prob=0.5)
> }
>
> But I always get this the warning:
>
> Warning message:In if (x1 + x2 - x3 > 0.5) { :
> the condition has length > 1 and only the first element will be used
>
>
> Can I do this without using function "for"?
>
> Thank you in advance.
> Ariel
> --
> *I like to pretend I'm alone*. *Completely alone*. *Maybe post-apocalypse
> or plague*... *Whatever*. *No-one left to act normal for. No need to hide
> who I really am. It would be... freeing*. *...*
>
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>
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