Thanks for the clarifcation, Duncan.
Best,
B
On Nov 22, 2007, at 8:32 PM, Duncan Murdoch <[EMAIL PROTECTED]>
wrote:
> On 22/11/2007 8:11 PM, Benilton Carvalho wrote:
>> well,
>> choose(n, k) should actually return:
>> factorial(n)/(factorial(n-k)*factorial(k))
>
> That's not how the docs defi
On 22/11/2007 8:11 PM, Benilton Carvalho wrote:
> well,
>
> choose(n, k) should actually return:
>
> factorial(n)/(factorial(n-k)*factorial(k))
That's not how the docs define it. They say
Note that 'choose(n,k)' is defined for all
real numbers n and integer k. For k >= 1 as n(n-1)...(n-
On 22/11/2007 8:04 PM, Luis Salasar wrote:
> Hi,
>
> I have used the function choose(n, k) sometimes, and i realized that it
> doesn't work properly for n < 0. For example, if one tries choose(-1, 3), it
> should be returned the value (-1)^3 = -1, since choose (-1, 3) =
> (-1)*(-2)*(-3)/3!
well,
choose(n, k) should actually return:
factorial(n)/(factorial(n-k)*factorial(k))
R-2.6.0 works just fine for me so does R-2.5.1 so does
R-2.4.1
b
On Nov 22, 2007, at 8:04 PM, Luis Salasar wrote:
> Hi,
>
> I have used the function choose(n, k) sometimes, and i realized
>
Hi,
I have used the function choose(n, k) sometimes, and i realized that it
doesn't work properly for n < 0. For example, if one tries choose(-1, 3), it
should be returned the value (-1)^3 = -1, since choose (-1, 3) =
(-1)*(-2)*(-3)/3! = (-1)^3, but indeed R returns the value 0. I am using
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