On 22/11/2007 8:11 PM, Benilton Carvalho wrote:
> well,
>
> choose(n, k) should actually return:
>
> factorial(n)/(factorial(n-k)*factorial(k))
That's not how the docs define it. They say
Note that 'choose(n,k)' is defined for all
real numbers n and integer k. For k >= 1 as n(n-1)...(n-k+1) /
k!, as 1 for k = 0 and as 0 for negative k.
which agrees with your definition only for 0 <= k <= n.
Duncan Murdoch
>
> R-2.6.0 works just fine for me.... so does R-2.5.1.... so does
> R-2.4.1....
>
> b
>
> On Nov 22, 2007, at 8:04 PM, Luis Salasar wrote:
>
>> Hi,
>>
>> I have used the function choose(n, k) sometimes, and i realized
>> that it doesn't work properly for n < 0. For example, if one tries
>> choose(-1, 3), it should be returned the value (-1)^3 = -1, since
>> choose (-1, 3) = (-1)*(-2)*(-3)/3! = (-1)^3, but indeed R returns
>> the value 0. I am using R version 2.5.1, it don't know if this
>> little bug has already been solved in the new version. Thanks,
>>
>> Luis Ernesto.
>>
>>
>> ---------------------------------
>>
>> [[alternative HTML version deleted]]
>>
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>
> ______________________________________________
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