If the input is "gdfsa-sdhchc99-88" then
assuming you only want "88" but not
"99" then if s is the vector of words
that we already computed:
s[regexpr("^[0-9]+", s) > 0]
or that could be combined with the strapply solution
into one line:
> strapply("gdfsa-sdhchc99-88", "\\w+", ~ if (regexpr("^[0
RON70 wrote:
> Thanks for these suggestions. However I have one more question. Is there any
> way to extract only numbers? For example I want to extract only "88" in my
> example.
>
if you have just one integer number represented in a single string,
here's one way go:
strings = c('foo 1',
Thanks for these suggestions. However I have one more question. Is there any
way to extract only numbers? For example I want to extract only "88" in my
example.
Regards,
MUHC-Research wrote:
>
> Hi Ron,
>
> Look up the grep() function.
>
> Cheers,
>
> --
> *Luc Villandré*
> /Biostatistician
Hi Ron,
Look up the grep() function.
Cheers,
--
*Luc Villandré*
/Biostatistician
McGill University Health Center -
Montreal Children's Hospital Research Institute/
RON70 wrote:
Hi all, is there any function to find some words in a character-string? For
example suppose the string is : "gdfsa-s
The following is TRUE if the indicated string is found:
regexpr("sdhch", "gdfsa-sdhchc-88") > 0
See ?regexpr
Either of the next two will break up a string into words. The
first needs to know the delimiters whereas the second
needs to know the contents:
> strsplit("gdfsa-sdhchc-88", "\\W+")[[1]]
On 5/11/2009 10:07 AM, RON70 wrote:
Hi all, is there any function to find some words in a character-string? For
example suppose the string is : "gdfsa-sdhchc-88", now I want to find
whether this string contains "sdhch". Is there any R function to do that?
See ?grep. There are several functions
Hi all, is there any function to find some words in a character-string? For
example suppose the string is : "gdfsa-sdhchc-88", now I want to find
whether this string contains "sdhch". Is there any R function to do that?
Regards,
--
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