If the input is "gdfsa-sdhchc99-88" then
assuming you only want "88" but not
"99" then if s is the vector of words
that we already computed:
s[regexpr("^[0-9]+", s) > 0]
or that could be combined with the strapply solution
into one line:
> strapply("gdfsa-sdhchc99-88", "\\w+", ~ if (regexpr("^[0-9]*$", x) > 0)
> x)[[1]]
[1] "88"
That picks out words and then tests them as before.
On Thu, May 14, 2009 at 2:58 AM, RON70 <ron_michae...@yahoo.com> wrote:
>
> Thanks for these suggestions. However I have one more question. Is there any
> way to extract only numbers? For example I want to extract only "88" in my
> example.
>
> Regards,
>
> MUHC-Research wrote:
>>
>> Hi Ron,
>>
>> Look up the grep() function.
>>
>> Cheers,
>>
>> --
>> *Luc Villandré*
>> /Biostatistician
>> McGill University Health Center -
>> Montreal Children's Hospital Research Institute/
>>
>> RON70 wrote:
>>> Hi all, is there any function to find some words in a character-string?
>>> For
>>> example suppose the string is : "gdfsa-sdhchc-88", now I want to find
>>> whether this string contains "sdhch". Is there any R function to do that?
>>>
>>> Regards,
>>>
>> //
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
> --
> View this message in context:
> http://www.nabble.com/Searching-within-a-ch.-string-tp23484010p23535406.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
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>
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