> Sent: Friday, April 06, 2018 at 1:44 PM
> From: "Jeff Newmiller"
>
> You did not try my suggestion. You tried David's, which has a leftover
> mistake from your guesses about what the argument to coef should be.
Yes, sorry for the mistake.
coef(graphmodeld)
(Intercept) graphdata[, 1]
4.
> Sent: Friday, April 06, 2018 at 5:55 AM
> From: "David Winsemius"
>
>
> Not correct. You already have `predict`. It is capale of using the `newdata`
> values to do interpolation with the values of the coefficients in the model.
> See:
>
> ?predict
>
The ยง details did not mention interpola
> Sent: Friday, April 06, 2018 at 4:53 AM
> From: "Jeff Newmiller"
> To: "g l"
> coef( graphmodeld )
>
coef(graphmodelp)
Error: $ operator is invalid for atomic vectors
A quick search engine query revealed primarily references to the dollar sign
($) opera
> Sent: Thursday, April 05, 2018 at 4:40 PM
> From: "Jeff Newmiller"
>
> the coef function.
>
For the benefit of other novices, used the following command to read the
documentation:
?coef
Then tried and obtained:
> cvalue100<-coef(graphmodelp~100)
> cvalue100
NULL
Then looked at the model
Readers,
Data set:
t,c
0,100
40,78
80,59
120,38
160,25
200,21
240,16
280,12
320,10
360,9
400,7
graphdata<-read.csv('~/tmp/data.csv')
graphmodeld<-lm(log(graphdata[,2])~graphdata[,1])
graphmodelp<-exp(predict(graphmodeld))
plot(graphdata[,2]~graphdata[,1])
lines(graphdata[,1],graphmodelp)
Please
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