> Sent: Friday, April 06, 2018 at 1:44 PM > From: "Jeff Newmiller" <jdnew...@dcn.davis.ca.us> > > You did not try my suggestion. You tried David's, which has a leftover > mistake from your guesses about what the argument to coef should be.
Yes, sorry for the mistake. coef(graphmodeld) (Intercept) graphdata[, 1] 4.513544204 -0.006820623 This corresponds to the linear model but it is still not understood how this helps to determine gradients at specific points for the exponential model. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
