ess" seems unfortunate.
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MS Windows: error: the opera
> * Bert Gunter [2015-08-17 10:27:58 -0700]:
>
>> qbinom(.025,1000,.001,lower=FALSE)
I don't think this is what I need.
I am looking for an inverse of binom.confint.
Sorry that my question was not clear.
--
Sam Steingold (http://sds.podval.org/) on darwin Ns 10.3.1348
http:/
-cut here---end--->8---
I thought that it should be identical to this:
--8<---cut here---start->8---
> strsplit(c("a,b;c","d;e,f"),"[,;]")
[[1]]
[1] "a" "b" "c"
[[2
> * Sam Steingold [2013-07-03 11:33:47 -0400]:
>
> Hi, I asked this question on SO but got no answers:
> http://stackoverflow.com/questions/17310825/r-promise-already-under-evaluation
Backlin explained on SO that the errors are to be expected: "..." is a
formal argument
[promise already under evaluation]] error?
What is the right way to pass threshold and exclude from
show.large.objects.stack to show.large.objects?
Thanks!
PS. I would prefer an answer on SO, but please feel free to reply using any
venue you like and I will copy your explanation to the other venue
le' objects, and thus `data.frame' objects too.
the igraph function graph.data.frame accepts data.frame as the first argument.
the igraph maintainers say that "it is not coming from igraph".
thanks.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.10 (quantal) X 11.0.11
-8<---cut here---end--->8---
pausing for tens of seconds to print each factor variable which have a
lot of levels.
Why?
(R version 2.15.3 (2013-03-01) -- "Security Blanket"
Platform: x86_64-pc-linux-gnu (64-bit))
--
Sam Steingold (http://sds.podval.org/)
> * Bert Gunter [2013-03-17 20:30:56 -0700]:
>
> I also think it fair to say that all (??) languages have these sorts
> of malapropisms due to operator precedence.
Except for those languages which do _not_ have "operator precedence".
Like, e.g., Lisp.
--
Sam Steingold
for their answers (to this
question, my many previous questions, and, I hope, my future questions
in advance)!
> On Sat, Jan 19, 2013 at 9:41 PM, Sam Steingold wrote:
>>> * Rui Barradas [2013-01-18 21:02:20 +]:
>>>
>>> Try the following.
>>>
>
> * Rui Barradas [2013-01-18 21:02:20 +]:
>
> Try the following.
>
> complete.cases(f) & apply(f, 1, function(x) all(x == x[1]))
thanks, this works, but is horribly slow (dim(f) is 766,950x2)
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Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X
I can do
Reduce("==",f[complete.cases(f),])
but that creates an intermediate data frame which I would love to avoid
(to save memory).
> * Sam Steingold [2013-01-18 15:53:21 -0500]:
>
> I have a data frame with several columns.
> I want to select the rows with no NAs (
b c
1 1 1 1
2 NA NA NA
3 NA 3 5
4 4 40 40
--8<---cut here---end--->8---
I want the vector TRUE,FALSE,FALSE,FALSE selecting just the first
row because there all 3 columns are the same and none is NA.
thanks!
--
Sam Steingold (http://sds.podval.
8---
however, this approach allocates and discards 2 vectors: a logical
vector of length=length(x) and an integer vector in which.
is there a cheaper alternative?
Thanks!
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Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http:
>8---
however, the global d is not modified, apparently update modifies the
local copy.
so,
1. is there a way for a function to modify a global variable?
2. how would you vectorize this loop?
thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
ht
Jonas,
I think f2si(0) should be "0", not "" as it is now.
Thanks.
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> axis(1, pos, lbl)
> axis(2, pos, lbl)
That's what I meant when I said "too much control".
I am happy with the way R selects positions.
All I want is a say in the way R formats those positions.
Think in terms of 100 being a variable.
To use axis, I will need to write a map
control for
this simple task.
thanks.
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Why do we want intelligent terminals w
t but that appears to be ignored too.
so, how do I tell lattice::xyplot to write charts in png files?
thanks!
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http://www.childpsy.net/ http://honestreporting.com
http://jihadwatch.org http://think-israel.org http:
ot attached):
> [1] R.methodsS3_1.4.2 tools_2.15.0
> A.K.
>
>
>
>
> - Original Message -
> From: Sam Steingold
> To: r-help@r-project.org; Richard M. Heiberger
> Cc:
> Sent: Monday, December 10, 2012 2:13 PM
> Subject: Re: [R] the value of the last express
ength 3 with content
--8<---cut here---start->8---
6 = 1+2+3
30 = 4+5+6+7+8
19 = 9+10
--8<---cut here---end--->8---
Obviously, I could write a loop, but I would rather have a vectorized
version.
Thanks!
--
Sam Steingold (htt
piler::compilePKGS(1)
--8<---cut here---end------->8---
> On Thu, Feb 9, 2012 at 9:44 PM, Sam Steingold wrote:
>
>> Is there an analogue of common lisp "*" variable which contains the
>> value of the last expression?
>> E.g., in lisp:
&g
[1,] Numeric,2
[2,] Numeric,2
[3,] Numeric,2
[4,] Numeric,2
[5,] Numeric,2
[6,] Numeric,2
[7,] Numeric,2
[8,] Numeric,2
[9,] Numeric,2
--8<---cut here---end--->8---
thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 1
> * Steve Lianoglou [2012-11-27 12:53:23
> -0500]:
> On Tue, Nov 27, 2012 at 11:29 AM, Sam Steingold wrote:
>>> * Steve Lianoglou [2012-11-26 19:47:25
>>> -0500]:
> [snip]
>>> It just occurred to me that this is even better:
>>>
>>>
> * Steve Lianoglou [2012-11-26 19:47:25
> -0500]:
>
> On Monday, November 26, 2012, Sam Steingold wrote:
> [snip]
>
>>
>> there is precisely one country for each id.
>> i.e., unique(country) is the same as country[1].
>> thanks a lot for the suggest
e, TIBCO Software
> wdunlap tibco.com
>
>
>> -Original Message-----
>> From: Sam Steingold [mailto:sam.steing...@gmail.com] On Behalf Of Sam
>> Steingold
>> Sent: Monday, November 26, 2012 4:09 PM
>> To: William Dunlap
>> Cc: r-help@r-project.
gt; Mean :3 Mean :2012-11-28
> 3rd Qu.:4 3rd Qu.:2012-11-29
> Max. :5 Max. :2012-11-30
>> summary(d$Delta)
> Min.Med.Max
> 1 days... 4 days...16 days
>
> My summary.difftime inherits from difftime so the format method is not really
>
ant the same min and max values to be replicated as
> many times as there are unique "country"s?
there is precisely one country for each id.
i.e., unique(country) is the same as country[1].
thanks a lot for the suggestion!
> R> result <- f[, list(min=min(delay), max=max(delay),
&g
> * David Winsemius [2012-11-26 08:46:35 -0800]:
>
> On Nov 26, 2012, at 7:14 AM, Sam Steingold wrote:
>
>> summary(infl), where infl$delay is a difftime vector, prints
>>
>> ...
>>
>>delay
>> string:c("492.00 ms", "18.08 min&qu
hi Steve,
> * Steve Lianoglou [2012-11-26 16:08:59
> -0500]:
> On Mon, Nov 26, 2012 at 3:13 PM, Sam Steingold wrote:
>>> * Steve Lianoglou [2012-11-19 13:30:03
>>> -0800]:
>>>
>>> For instance, if you want the min and max of `delay` within ea
ield in the original table infl which only depends
on share.id, how do I add this unique value to the summary?
it appears that "count=unique(country)" in list() does what I need, but
it slows down the process.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise)
instead of something like
delay
Min.:492 ms
1st Qu.: 18.08 min
&c
so, how do I arrange for a proper printing of difftime summary as a part
of the data frame summary?
> * David Winsemius [2012-11-25 00:50:51 -0800]:
>
> On Nov 24, 2012, at 7:48 PM
-start->8---
> a <- summary(infl)
Error in summary.difftime(X[[22L]], ...) :
unused argument(s) (maxsum = 7, digits = 12)
--8<---cut here---end------->8---
I guess I should somehow accept a list of options in summary.difftim
R-FAQ.html#How-should-I-write-summary-methods_003f
what are the requirements on the class summary.foo?
does it have to inherit from some other class?
how do I define a class?
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.chi
efault', 'table'" as I assume summary must return.
if these are not valid issues, then I wonder why my function should not
be the system default method.
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http://www.childpsy.net/ http://memri.org ht
string secs
Min.500.00 ms 0.5
1st Qu. 17.12 min 1027.0
Median 99.48 min 5969.0
Mean 8.30 hrs 29870.0
3rd Qu. 8.05 hrs 28970.0
Max.6.98 days 603100.0
--8<---cut here---end--->8---
--
Sam Steingold (http://sds.podval.o
x < 6000) return(sprintf("%.2f min",x/60))
if (x < 108000) return(sprintf("%.2f hrs",x/3600))
if (x < 400*24*3600) return(sprintf("%.2f days",x/(24*3600)))
sprintf("%.2f years",x/(365.25*24*3600))
}
--8<---cut here
t; On Fri, Sep 14, 2012 at 3:26 PM, Sam Steingold wrote:
>> I have a large data.frame Z (2,424,185,944 bytes, 10,256,441 rows, 17
>> columns).
>> I want to get the result of
>> table(aggregate(Z$V1, FUN = length, by = list(id=Z$V2))$x)
>> alas, aggregate has been
> $ foo: num 10
>>
I am sorry, how is this different from my second snippet (except that
you use "x" and I use "z" and you use single quotes in paste and I use
double quotes)?
>
> On Mon, Nov 19, 2012 at 1:07 PM, Sam Steingold wrote:
>> How can I cr
ere---start->8---
> z <- list(10)
> names(z) <- paste("f","oo",sep="")
> z
$foo
[1] 10
--8<---cut here---end--->8---
thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.
2. I find the num->char->num conversion repugnant and unacceptable.
--
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What was
ariables:
$ a : Factor w/ 3 levels "a1","a2","a3": 1 2 3
$ b.x: num 1 2 3
$ b.y: num 1 4 9
$ c.x: num 1 8 27
$ c.y: num 1 64 729
--8<---cut here---end--->8---
thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubu
Hi,
> * Thibault Helleputte [2012-11-09
> 09:22:11 +0100]:
>
> The next release of LiblineaR should offer the possibility of using
> sparse matrices. However, the next release date is not fixed yet...
thanks.
> On Thu, Nov 8, 2012 at 10:07 PM, Sam Steingold wrote:
>>
> * Ben Bolker [2012-11-07 21:51:07 +]:
>
> Sam Steingold gnu.org> writes:
>
>> It would be nice if LiblineaR() accepted data in the form of a sparse
>> matrix (it does not accept whatever e1071::read.matrix.csr returns).
>>
>> It would also be nic
provides at least the input code.
Thanks!
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Sex is like air. It's only a big
uot;=tab[1])
nons seed.0 ## don't want ".0"!
1 2344600
> c("nons"=1, "seed"=tab[2])
nons seed.1 ## don't want ".1"!
1 6843
> tab
0 1
23446006843
--8<---cut he
> * Martin Maechler [2012-11-07 10:10:51 +0100]:
>
>>>>>> "Sam" == Sam Steingold
>>>>>> on Tue, 6 Nov 2012 13:08:30 -0500 writes:
>
> Sam> The question is even more pressing for me now given that I no longer
> can
>
ints to what libsvm can read.
> There is certainly a way to speed this up, but I am not likely to do
> this in the near future.
too bad.
> On 2012-11-06 19:15, Sam Steingold wrote:
>> David,
>> thanks for adding the feature.
>>
>> read.matrix.csr and, es
t;
> On 2012-08-27 21:15, Sam Steingold wrote:
>>> * jim holtman [2012-08-27 14:55:08 -0400]:
>>>
>>> Most likely when 'y' is converted to a dataframe (not sure what the
>>> function 'write.matrix.csr' does since you did not say where you go
is small enough).
> * Sam Steingold [2012-08-27 14:58:47 -0400]:
>
> When a sparse matrix is multiplied by a regular one, the result is
> usually not sparse. However, when matrix.csr is multiplied by a regular
> matrix in R, a matrix.csr is produced.
> Is there a way to av
earch/sparse/sparse.html
Packaged: 2012-03-18 19:39:05 UTC; root
Repository: CRAN
Date/Publication: 2012-03-18 20:55:08
Built: R 2.15.2; x86_64-pc-linux-gnu; 2012-11-05 17:46:36
UTC; unix
> * Sam Steingold [2012-11-05 12:40:25 -0500]:
>
> all
vector
what has happened?
how do I scale the matrix.csr object (to be written to a file)?
PS. write.matrix.csr is very slow: it takes
user system elapsed
1137.058 510.615 1649.925
to write the matrix "z" above.
thanks!
--
Sam Steingold (http://sds.podval.org/) o
> * Marc Schwartz [2012-11-04 12:33:20 -0600]:
>
> On Nov 4, 2012, at 12:22 PM, Sam Steingold wrote:
>
>>> * Bert Gunter [2012-11-04 09:48:58 -0800]:
>>>
>>> ?update.packages
>>
>> It is not obvious to me that this is the answer to my q
es() will
_not_ try to update it, but, apparently, at least for some packages, I
do need to rebuild them against the new R version 2.15.2.
Thanks.
> On Sun, Nov 4, 2012 at 7:01 AM, Sam Steingold wrote:
>> I have some packages installed using install.packages().
>> Do I need to reinsta
ching your R installation. In other
words: One way to fix your problem is to re install the Matrix
package in the version of R you are using.
So, will the bug reappear now?
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do what I need.
I see that
identical(levels(concatenate.factors(a,b)),levels(a))
==> TRUE
DIUC that concatenate.factors does NOT create an intermediate vector and
then re-factor it?
Thank you very much for your insight!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.1110300
> * Jeff Newmiller [2012-10-18 07:53:24 -0700]:
>
> If you HAVE defined your factors using explicit levels definitions, you
> should have no trouble combining them.
http://article.gmane.org/gmane.comp.lang.r.general:277719
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04
> * R. Michael Weylandt [2012-10-18 16:01:37
> +0100]:
>
> On Thursday, October 18, 2012, Sam Steingold wrote:
>
>> > * Bert Gunter [2012-10-17 23:21:44 -0700]:
>> >
>> > However, Is level "5" in 'a' the same as level "5&
pped to a
character vector via letters, which is converted back to integers
(==factors).
IIUC, a factor is an integer vector which knows that the integers refer
to levels.
c(a,b) creates such an integer vector.
How do I tell it that it is a factor?
--
Sam Steingold (http://
> * Bert Gunter [2012-10-17 23:21:44 -0700]:
>
> However, Is level "5" in 'a' the same as level "5" in 'b' ?
yes, of course.
would anyone want to _different_ factors with identical string representations?!
--
Sam Steingold (http://sds.podval.org
9 levels "1","2","3","4",..: 5 4 3 2 1 9 8 7 6 5 ...
--8<---cut here---end--->8---
so, unlist(list()) works.
is there a better way or is this how this is supposed to be done?
Thanks!
--
Sam Steingold (
> * Sam Steingold [2012-10-16 11:03:27 -0400]:
>
> I need an analogue of "uniq -c" for a data frame.
Summary of options:
1. William:
isFirstInRun <- function(x) UseMethod("isFirstInRun")
isFirstInRun.default <- function(x) c(TRUE, x[-1] != x[-length(x)])
is
> * Duncan Murdoch [2012-10-16 14:22:51 -0400]:
>
> On 16/10/2012 1:46 PM, Sam Steingold wrote:
>> > * Duncan Murdoch [2012-10-16 12:47:36 -0400]:
>> >
>> > On 16/10/2012 12:29 PM, Sam Steingold wrote:
>> >> x is sorted.
>> > spars
> * Duncan Murdoch [2012-10-16 12:47:36 -0400]:
> sparseby(data=x, INDICES=x, FUN=nrow)
Error in `[<-.data.frame`(`*tmp*`, index, , value = list(user = c(2L, :
missing values are not allowed in subscripted assignments of data frames
--
Sam Steingold (http://sds.podval.org/)
e"' into a data.frame
it seems that
rle.df <- data.frame(values=rle$values,length=rle$length)
works and DTRT.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
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http://www.PetitionOnline.co
> * Duncan Murdoch [2012-10-16 12:47:36 -0400]:
>
> On 16/10/2012 12:29 PM, Sam Steingold wrote:
>> x is sorted.
> sparseby(data=x, INDICES=x, FUN=nrow)
this takes forever; apparently, it does not use the fact that x is
sorted (even then - it should not take more than a few mi
t;8---
>>> x <- data.frame(a=1:32,b=1:32,c=1:32,d=1:32,e=1:32)
>>> system.time(subset(as.data.frame(xtabs( ~. , x )), Freq != 0 ))
>>user system elapsed
>> 12.788 4.288 17.224
>> --8<---cut here---end------->8
"CO", "CO", "CO", "US",
"MM", "MM", "US", "US", "IN", "IN", "IN", "IN", "CA", "CA", "CA",
"CA", "US", "DE", "DE",
The Rgraphviz package index says nothing about reading "dot" files.
(it has "toFile" to write them but no fromFile).
How do I create an Ragraph object?
(either by reading a dot file or from a list of edges with weights and
vertices with names and other attributes).
--
t be installed in a
quite unorthodox way (source("http://bioconductor.org/biocLite.R";);
biocLite("Rgraphviz")); and then it is not clear how to turn an IGRAPH
graph object into an Ragraph object which Rgraphviz can handle.
So, what/how do people use/recommend?
Thanks!
> * Prof Brian Ripley [2012-10-08 06:37:07 +0100]:
>
> On 08/10/2012 02:57, Peter Ehlers wrote:
>> On 2012-10-07 14:44, Sam Steingold wrote:
>>>> * Peter Ehlers [2012-10-07 10:03:42 -0700]:
>>>>
>>>> On 2012-10-07 08:34, Sam Steingold wrote:
> * Peter Ehlers [2012-10-07 10:03:42 -0700]:
>
> On 2012-10-07 08:34, Sam Steingold wrote:
>> I know it does not look very good - using the same column names to mean
>> different things in different data frames, but here you go:
>> --8<---cut here-
duplicated in the result
--8<---cut here---end--->8---
why is the suffixes argument ignored?
I mean, I expected that the second "a" to be "a.y".
(when I omit suffixes, the result is the same).
Thanks.
--
Sam Steingold (http://sds.
why does summary report max 27600 and not 27603?
> x <- c(27603, 1)
> max(x)
[1] 27603
> summary(x)
Min. 1st Qu. MedianMean 3rd Qu.Max.
16902 13800 13800 20700 27600
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.1
NA 2 y 2
> #2 30 1 c 1 NA 1 z 1
> # a2.num2
> #0 1
> #1 NA
> #2 NA
> #It is not an elegant way!
>
>
> A.K.
>
>
>
> - Original Message -
> From: Sam Steingold
>
])
})
id id a1 a2
1 10 3 3 3
2 20 2 2 2
3 30 1 1 1
Warning message:
In format.data.frame(x, digits = digits, na.encode = FALSE) :
corrupt data frame: columns will be truncated or padded with NAs
--8<---cut here---end--->8---
Thanks!
--
Sam Steingold
ocals <- z[z$country == mycountry,]
>>> length(which(is.na(locals$language)))
>> [1] 229
>> --8<---cut here---end--->8---
>> where are those locals without the language coming from?!
>>
>> --
>> Sam Steingold (http://sds.podva
turn.
However, it does not do what I want: it does not result in the right
name for the returned table.
Thanks a lot for your insight!
>
>> -Original Message-
>> From: Sam Steingold [mailto:sam.steing...@gmail.com] On Behalf Of Sam
>> Steingold
>> Sent: Wednes
t; locals <- subset(z, country == mycountry)
>
> Sarah
>
> On Wed, Sep 19, 2012 at 1:50 PM, Sam Steingold wrote:
>> I see this:
>> --8<---cut here---start->8---
>>> length(which(is.na(z$language)))
>> [1] 0
>&g
-
where are those locals without the language coming from?!
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I don't like cats! -- Com
> 9 4 3 2 1 1
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
>> Behalf
>> Of Sam Steingold
>> Sent: Wednesday, September 19
nts "vec" instead of the name of its
argument:
--8<---cut here---start->8---
> sorted.table(foo$bar)
vec
A B
10 3
--8<---cut here---end--->8---
how do I pass all arguments of sorted.table() on to ta
uot; (and maybe even sort?) can be effected by
some magic argument to table() which I fail to discover in the docs?
Obviously, I could use droplevels() to avoid 0 counts in the first
place, but I do not want to drop the levels in the data.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12
were 0
tab2 <- table(z$s)
stopifnot(length(tab2) == nrow(z)) # yes
stopifnot(sum(tab1) == nrow(z)) ### no!
sum(tab1)
728587
length(tab1)
503374
length(tab2)
2112951
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http://think-
nd--->8---
factor(z$a,levels=union(z$a,z$b))
is factor(z$a,levels=union(z$a,z$b)) the right way to handle this?
maybe there is a better way to extract levels than union()?
(bear in mind that I have ~10M rows and ~1M levels, so performance is an
issue).
Thanks!
--
Sam Steingold (http:
factors).
Is there anything I could do to speed this up?
Thanks.
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http://www.PetitionOnline.com/tap12009/
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WinWord 6.0 UNinstall
canonicalize.language <- function (s) {
> # s <- tolower(s)
> long <- nchar(s) == 5
> s[long] <- sub("^([[:alpha:]]{2})[-_][[:alpha:]]{2}$","\\1",s[long])
> s[nchar(s) != 2 & s != "c"] <- "unknown"
> s
> }
but it
t;c"] <- "unknown"
s
}
--8<-------cut here---end--->8---
was even slower (6.4 sec).
My two concerns are:
1. avoid allocating many small objects which are never collected
2. run fast
Which would be the best implementation?
Thanks a lot f
ada NA Adangme adangme
6 ady NAAdyghe; Adygei adygh
note that the first non-ASCII character terminates the input.
so, I still cannot read the data from the URL.
I can read the file though - with quote="" (thanks
sage:
In readLines("ISO-639-2_utf-8.csv", encoding = "utf-8") :
incomplete final line found on 'ISO-639-2_utf-8.csv'
> l[108:110]
[1] "dgr|||Dogrib|dogrib"
[2] "din|||Dinka|dinka"
[3] &q
h column?
the 3rd ("score") column.
Meanwhile I realised that the fastest way is actuall shell:
sort+cut+paste produced the csv file which can be loaded into R much
faster than the individual score files, so this issue is now purely
academic. However, I appreciate the replies I got so far
> * David Winsemius [2012-09-05 21:02:16 -0700]:
>
> On Sep 5, 2012, at 8:51 PM, Sam Steingold wrote:
>
>> I have a list of data frames:
>>
>>> str(data)
>> List of 4
>> $ :'data.frame': 700773 obs. of 3 variables:
>&g
, Recall(dfs[-1]), all = TRUE, sort = FALSE,
:
formal argument "all" matched by multiple actual arguments
> data.1 <- merge_all(data,by="V1",sort=TRUE)
Error in merge.data.frame(dfs[[1]], Recall(dfs[-1]), all = TRUE, sort = FALSE,
:
formal argument "sort"
> * William Dunlap [2012-08-31 18:38:52 +]:
>
> Is the following something like what you are doing?
yes, absolutely, thanks a lot!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http://pmw.org.il http://dhimmi
"0"
$ c :List of 2
..$ : chr "10"
..$ : chr "10"
I guess the easiest way is to replace c(...list()...) with c(...) but
that would mean converting num1,num2,num3 to string and back which I
want to avoid for aesthetic reasons. Any better suggestions?
ke
c(1,2,"a") ==> "1" "2" "a" =[as.numeric]=> 1 2 "a"
--
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http://www.childpsy.net/ http://openvotingconsortium.org http://www.memritv.org
http://ffii.org http://
tion, so they slowness is not surprising)
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
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http://truepeace.org http://openvotingconsortium.org http://ffii.org
The best propaganda of ath
> * Sam Steingold [2012-08-30 08:56:17 -0400]:
>
> Is there a way for an apply-type function to return a data frame?
> the closest thing I think of is
>
> foo <- as.data.frame(t(sapply(...)))
> names(foo) <- c()
alas, this has a problem of creating a "ho
Is there a way for an apply-type function to return a data frame?
the closest thing I think of is
foo <- as.data.frame(sapply(...))
names(foo) <- c()
is there a more "elegant" way?
Thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11
> * Duncan Murdoch [2012-08-29 10:30:10 -0400]:
>
> On 29/08/2012 12:50 AM, Sam Steingold wrote:
>> > * Duncan Murdoch [2012-08-28 21:06:33 -0400]:
>> >
>> > On 12-08-28 5:55 PM, Sam Steingold wrote:
>> >>
>> >> my observation i
> * Duncan Murdoch [2012-08-28 21:06:33 -0400]:
>
> On 12-08-28 5:55 PM, Sam Steingold wrote:
>>> * R. Michael Weylandt [2012-08-28 13:45:35
>>> -0500]:
>>>
>>>> always you shouldn't need manual garbage collection.
>>
>> my obser
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