The following code:
--8<---------------cut here---------------start------------->8---
> myfun <- function (x) list(x=x,y=x*x)
> z <- as.data.frame(do.call(rbind,lapply(1:3,function(x)
> c(a=paste("a",x,sep=""),as.list(unlist(list(b=myfun(x),c=myfun(x*x*x))))))))
> z
a b.x b.y c.x c.y
1 a1 1 1 1 1
2 a2 2 4 8 64
3 a3 3 9 27 729
--8<---------------cut here---------------end--------------->8---
the appearance of z is good, but str() and summary betray some weirdness:
--8<---------------cut here---------------start------------->8---
> str(z)
'data.frame': 3 obs. of 5 variables:
$ a :List of 3
..$ : chr "a1"
..$ : chr "a2"
..$ : chr "a3"
$ b.x:List of 3
..$ : int 1
..$ : int 2
..$ : int 3
$ b.y:List of 3
..$ : int 1
..$ : int 4
..$ : int 9
$ c.x:List of 3
..$ : int 1
..$ : int 8
..$ : int 27
$ c.y:List of 3
..$ : int 1
..$ : int 64
..$ : int 729
--8<---------------cut here---------------end--------------->8---
how do I ensure that the columns of z are vectors, as in
--8<---------------cut here---------------start------------->8---
> z <-
> data.frame(a=c("a1","a2","a3"),b.x=c(1,2,3),b.y=c(1,4,9),c.x=c(1,8,27),c.y=c(1,64,729))
> z
a b.x b.y c.x c.y
1 a1 1 1 1 1
2 a2 2 4 8 64
3 a3 3 9 27 729
> str(z)
'data.frame': 3 obs. of 5 variables:
$ a : Factor w/ 3 levels "a1","a2","a3": 1 2 3
$ b.x: num 1 2 3
$ b.y: num 1 4 9
$ c.x: num 1 8 27
$ c.y: num 1 64 729
--8<---------------cut here---------------end--------------->8---
thanks!
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
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