[R] Format utils::bibentry with a 'corporate name'

nexpected END_OF_INPUT 'The Data Org. #> ' #> #> People D (2021). _The Thing_. The Data Org. #> #> A BibTeX entry for LaTeX users is #> #> @Manual{, #> title = {The Thing}, #> author = {{The Data People}}, #> organization = {The Data Org}, #&g

[R] Using multiroot for root solution for a matrix based function

I have a function which is actually an output of another function and I therefore cannot change it. I am trying to use *multiroot * from package *rootSolve * to compute the roots of the function but its not working at all. Is there something I am not seeing or is there another alternative that is

Re: [R] [External] Re: read.csv fails in R console in Ubuntu terminal but works in RStudio after R 3.6.3 upgrade to R 4.0.2?

This issue was now solved in TTR::stockSymbols() by package author https://github.com/joshuaulrich/TTR/commit/98dec2b5aa68c3cee750397c7d11b164895e0140 Thanks for all the help and ideas. Best, Sam On Fri, Jul 17, 2020, 13:54 Sam H wrote: > Hello, > > Thank you very much to you all to

Re: [R] [External] Re: read.csv fails in R console in Ubuntu terminal but works in RStudio after R 3.6.3 upgrade to R 4.0.2?

of read.csv I am now using data.table::fread() which properly (without failing) downloads the file and reads it. Best, Sam On Fri, Jul 17, 2020 at 4:30 AM ruipbarradas wrote: > Hello, > > Yes, I thought it's a site policy issue too. But the file can be accessed > and read/downlo

[R] read.csv fails in R console in Ubuntu terminal but works in RStudio after R 3.6.3 upgrade to R 4.0.2?

] compiler_4.0.2> I also asked this question here https://stackoverflow.com/questions/62898008/why-read-csv-fails-in-r-console-in-ubuntu-terminal-but-works-in-rstudio-after-r . Since there was no answer on stackoverflow I sent this question also to this list. Best regards, Sam [[alternativ

[R] Obtain One Row From ggcorr() Matrix

s a much nice and prettier looking correlation plot but does it for all variables. I have tried putting mtcars$mpg and mtcars[,1] to only return the one row, but neither seem to work. Any ideas on how to do it using ggcorr()? Thanks, Sam __ R-hel

[R] A simple string alienation question.

data in with a simple read.csv statement:   calc <- read.csv("Fight.csv", stringsAsFactors = F, header = F)  str(x)  Output: > str(calc)'data.frame': 38765 obs. of  1 variable: $ V1: chr  "tropical fruit\"" "whole milk\"" "pi

Re: [R] file.access returning -1 for a file on remote Windows drive.

Thanks Jeff. And for future readers head here: https://github.com/eddelbuettel/digest/issues/49 and here: https://github.com/eddelbuettel/digest/issues/13 Sam On Fri, Feb 28, 2020 at 3:40 PM Jeff Newmiller wrote: > > Read the closed issues in his digest Github repo first... this disc

Re: [R] file.access returning -1 for a file on remote Windows drive.

t? You can use tryCatch to deal with problems > opening or > reading the file. > > Bill Dunlap > TIBCO Software > wdunlap tibco.com > > > On Fri, Feb 28, 2020 at 2:54 PM Sam Albers wrote: >> >> Thanks Jeff. I am probably not explaining myself very well but my &g

Re: [R] file.access returning -1 for a file on remote Windows drive.

in both of these functions? On Fri, Feb 28, 2020 at 2:37 PM Jeff Newmiller wrote: > > Dunno. They agree for me. Maybe look closer at all permissions via Windows > File Manager? > > On February 28, 2020 2:06:34 PM PST, Sam Albers > wrote: > >Some additional follow-up: >

Re: [R] file.access returning -1 for a file on remote Windows drive.

-1 Can anyone think why file.access and file would be contradicting each other? Sam On Fri, Feb 28, 2020 at 10:47 AM Sam Albers wrote: > > Hi there, > > Looking for some help in diagnosing or developing a work around to a > problem I am having on a Windows machine. I am

[R] file.access returning -1 for a file on remote Windows drive.

se file.access is failing. Any thoughts on how I can get file.access to return 0 for the remote.R file? Any ideas? Thanks in advance, Sam __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-he

[R] Data Frame Organization

There is some issue with the plain text vs. HTML - please find the answer again. If illegible kindly see the attached pic. Best Wishes. s. x <- c('A', 'B', 'C', 'A', 'B', 'C') y <- c(10, 5, 9, 5, 15, 20) df <- data.frame(x,y) df f <- reshape(df, v.names = "y", idvar = "x", timevar = "y", directi

Re: [R] Data frame organization

Dear Arnaud, I just played around with your data a bit and found this to be useful. But kindly note that I am NO expert like the other people in the group. My answer to you is purely for help purposes. My knowledge in R too is limited. I used the reshape function and arrived at something. I am 

Re: [R] Help with numeric and character separation

help. 'regexr' is still something I am digging into... sam.  ** On Sunday, 16 June 2019, 10:28:17 pm GMT+5:30, Bert Gunter wrote: 1. Post in **plain text** not  html, please. 2. This looks like a vector, not a data frame. 3. Use ?strsplit: &g

Re: [R] Help with a third ggplot error

Thanks a lot Boris, I tried out your worked out solution and it works just perfectly fine. No doubt I need a lot of practice with regexr and the pattern  stated by you - I will do that now. Thanks a lot for pointing me in the right direction. Appreciate it a lot. Sam.  On Monday, 17 June

[R] Help with numeric and character separation

e a  separator and I am not being able to figure this out. Kindly please help me with this.  Many Thanks in advance for your help. This is my first  question ever to the community so apologies if I have made a mist

Re: [R] Help with a third ggplot error

I am  not being able to figure this out. Kindly please help resolve this.  Many Thanks in advance for your help. This is my first  question ever to the community so apologies if I have made a mistake in sending it to the wrong group - kindly direct if that is the case.  sam. 

[R] (no subject)

ild it myself. Similarly confusing is the lack of a . in the package name indicative of anything? Does anyone have any idea what's going on here? Am I missing something obvious? Thanks in advance, Sam __ R-help@r-project.org mailing list -- To UNSUBS

[R] Unable to return gmtoff from as.POSIXlt without converting date string to as.POSIXct first

<- "2017-01-01 12:00:00" foo <- as.POSIXlt(datestring, tz = "America/Moncton") foo [1] "2017-01-01 12:00:00 AST" foo$gmtoff [1] NA bar <- as.POSIXlt(as.POSIXct(datestring, tz = "America/Moncton")) bar [1] "2017-01-01 12:00:

[R] Calling r-scripts with arguments from other scripts, or possibly R programming conventions/style guide

othing occurs (there is no output file created, but also no error) When I use RunningScript.R { commandArgs <- c(0.6,0.4,132) source("Arg Script.R') } I don't get any args passed into the file. Instead getting the error Not enough arguments, please supply 3, [% dbl

[R] [R-pkgs] New package: tidyhydat

short vignette outlining tidyhydat's usage can be found here: https://cran.r-project.org/web/packages/tidyhydat/vignettes/tidyhydat_an_introduction.html The project page can be found here: https://github.com/ropensci/tidyhydat Best, Sam ___ R-packag

Re: [R] [R-pkgs] Release of ess 0.0.1

ess" seems unfortunate. -- Sam Steingold (http://sds.podval.org/) on darwin Ns 10.3.1504 http://steingoldpsychology.com http://www.childpsy.net http://iris.org.il http://mideasttruth.com http://thereligionofpeace.com https://jihadwatch.org MS Windows: error: the opera

[R] [R-pkgs] revengc CRAN package

Dear R community,   I am happy to announce the publication on CRAN of the revengc package: https://cran.r-project.org/web/packages/revengc/index.html The statistical package revengc was designed to reverse engineer censored, decoupledcensus data into a likely hhs x area uncensored contingency

[R] getOption() versus Sys.getenv

ecommend users store the path as an option or as an environmental variable? If I am storing credentials in an .Renviron file then maybe I should store the path there as well? More generally the question is can anyone recommend some good discussion/documentation on this topic? Th

[R] [R-pkgs] Introducing the rsoi package

South Pacific Ocean. Suggestions and contributions are very much welcome at the rsoi github page: https://github.com/boshek/rsoi -Sam ___ R-packages mailing list r-packa...@r-project.org https://stat.ethz.ch/mailman/listinfo/r-packages

[R] R implementation of the Split and Merge Algorithm

to check first to see if someone has already accomplished this. I know this is a stretch but I thought it wouldn't hurt to ask. Thanks in advance. Sam __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman

[R] Extract an number from a character

example? I had also tried substr() but that fall apart with the 2.5 x 2.5 net. Thanks in advance! Sam Example: ##dataframe df<-data.frame(x=rnorm(10), y=c("7 x 3","7 x 3","7 x 3","7 x 3","7 x 3","2.5 x 2.5","2.5 x 2

Re: [R] Choosing columns by number

Thierry's answer of: data.frame( seq_along(iris), colnames(iris) ) is exactly what I was looking for. Apologies for vagueness and HTML. It was unintended. Sam On Tue, Aug 25, 2015 at 8:32 AM, stephen sefick wrote: > ?grep > > I think this will do what you want. > >

[R] Choosing columns by number

can do something like this: iris[,c(2,4)] I feel like there must be a better way to do this so I wanted to ask the collective wisdom here what people do to accomplish this. Obviously this is a trivial example, but the issue really becomes problematic when you hav

Re: [R] help with binom.power

> * Bert Gunter [2015-08-17 10:27:58 -0700]: > >> qbinom(.025,1000,.001,lower=FALSE) I don't think this is what I need. I am looking for an inverse of binom.confint. Sorry that my question was not clear. -- Sam Steingold (http://sds.podval.org/) on darwin Ns 10.3.1348 http:/

[R] Automatically updating a plot from a regularly updated data file

ge of R's functionality. Thanks in advance. Sam [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide ht

[R] Working with < and > is data sets

numeric results is a slew of NA values zp$valuefactor<-as.numeric(as.character(zp$value)) ## At this point I am unsure how to proceed. zp ### So I am just wondering how folks deal with this type of data. Any advice would be much appreciated as I am looking for something that will reliably wo

[R] Negative values on output

Good afternoon, I am completed a linear regression model which I personally am happy with the output and residual charts (although they are a bit bunched). I have been using visreg() to visualise my data, and although I have logged the dependent variable (as it is cost data), on one of the

[R] Weighted Logistic Regression in R: Can R do what SAS PROC LOGISTIC does?

I wonder if anyone has written some additional R code to perform weighted logistic regression in the way of SAS PROC LGOISTIC WEIGHT statement. I want to weight the sample using a vector of probabilities generated from Dirichlet distribution. It is known that the R function glm has a WEIGHT op

Re: [R] < symbols in a data frame

4", "163", "165", "169", "178", "2.3", "2.4", "22", "24", "244", "27.2", "274", "3", "3.1", "40.2", "43", "50", "516", "53.3

[R] < symbols in a data frame

ols making it difficult to deal with the numbers is a useful way. So in sum any ideas on how I could subset the example below for only whole numbers? Thanks in advance! Sam #code metals <- structure(list(Parameter = structure(c(1L, 2L, 3L, 4L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 15L, 16

[R] Vol calculations

Hi all, I've been struggling along with this for a while, so your help would be greatly appreciated. Using an array of prices from a T-SQL database for a number of stocks I wish to calculate the volatility of returns for these stocks, which will then be multiplied by the weight of that stock in a

[R] strsplit with a vector split argument

-cut here---end--->8--- I thought that it should be identical to this: --8<---cut here---start->8--- > strsplit(c("a,b;c","d;e,f"),"[,;]") [[1]] [1] "a" "b" "c" [[2

Re: [R] promise already under evaluation

> * Sam Steingold [2013-07-03 11:33:47 -0400]: > > Hi, I asked this question on SO but got no answers: > http://stackoverflow.com/questions/17310825/r-promise-already-under-evaluation Backlin explained on SO that the errors are to be expected: "..." is a formal argument

[R] promise already under evaluation

[promise already under evaluation]] error? What is the right way to pass threshold and exclude from show.large.objects.stack to show.large.objects? Thanks! PS. I would prefer an answer on SO, but please feel free to reply using any venue you like and I will copy your explanation to the other venue

[R] Dunnett's T3 test (DTK package) problem

Hello, I would like to ask a question about using DTK.test() to do the T3 test. The data file is downloadable here: http://ubuntuone.com/0zBl8QgUg1lAG6iK1CUicD My question is: in the result of T3 test, is it possible for the following three statements to hold without conflict? 1. m_a and m_b to

[R] cedta decided 'igraph' wasn't data.table aware

le' objects, and thus `data.frame' objects too. the igraph function graph.data.frame accepts data.frame as the first argument. the igraph maintainers say that "it is not coming from igraph". thanks. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.10 (quantal) X 11.0.11

[R] need help with R

hey there can i email questions to this address to get help with using R thanks sam [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http

[R] str on large data.frame is slow on factors with many levels

-8<---cut here---end--->8--- pausing for tens of seconds to print each factor variable which have a lot of levels. Why? (R version 2.15.3 (2013-03-01) -- "Security Blanket" Platform: x86_64-pc-linux-gnu (64-bit)) -- Sam Steingold (http://sds.podval.org/)

Re: [R] !0 + !0 == !0 - !0

> * Bert Gunter [2013-03-17 20:30:56 -0700]: > > I also think it fair to say that all (??) languages have these sorts > of malapropisms due to operator precedence. Except for those languages which do _not_ have "operator precedence". Like, e.g., Lisp. -- Sam Steingold

[R] help with population matrix

;s needed here. Any insight is welcome here, including a different way of modelling this population. Many thanks, Sam. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read

Re: [R] select rows with identical columns from a data frame

for their answers (to this question, my many previous questions, and, I hope, my future questions in advance)! > On Sat, Jan 19, 2013 at 9:41 PM, Sam Steingold wrote: >>> * Rui Barradas [2013-01-18 21:02:20 +]: >>> >>> Try the following. >>> >

Re: [R] select rows with identical columns from a data frame

> * Rui Barradas [2013-01-18 21:02:20 +]: > > Try the following. > > complete.cases(f) & apply(f, 1, function(x) all(x == x[1])) thanks, this works, but is horribly slow (dim(f) is 766,950x2) -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X

Re: [R] select rows with identical columns from a data frame

I can do Reduce("==",f[complete.cases(f),]) but that creates an intermediate data frame which I would love to avoid (to save memory). > * Sam Steingold [2013-01-18 15:53:21 -0500]: > > I have a data frame with several columns. > I want to select the rows with no NAs (

[R] select rows with identical columns from a data frame

b c 1 1 1 1 2 NA NA NA 3 NA 3 5 4 4 40 40 --8<---cut here---end--->8--- I want the vector TRUE,FALSE,FALSE,FALSE selecting just the first row because there all 3 columns are the same and none is NA. thanks! -- Sam Steingold (http://sds.podval.

[R] non-consing count

8--- however, this approach allocates and discards 2 vectors: a logical vector of length=length(x) and an integer vector in which. is there a cheaper alternative? Thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http:

[R] vectorization & modifying globals in functions

>8--- however, the global d is not modified, apparently update modifies the local copy. so, 1. is there a way for a function to modify a global variable? 2. how would you vectorize this loop? thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 ht

[R] sitools: bug: f2si(0)=>""

Jonas, I think f2si(0) should be "0", not "" as it is now. Thanks. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://ffii.org http://mideasttruth.com http://thereligionofpeace.com http://iris.org.il http://truep

Re: [R] axes labeling

> axis(1, pos, lbl) > axis(2, pos, lbl) That's what I meant when I said "too much control". I am happy with the way R selects positions. All I want is a say in the way R formats those positions. Think in terms of 100 being a variable. To use axis, I will need to write a map

[R] axes labeling

control for this simple task. thanks. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://www.memritv.org http://jihadwatch.org http://pmw.org.il http://americancensorship.org http://think-israel.org Why do we want intelligent terminals w

[R] lattice::xyplot & file output

t but that appears to be ignored too. so, how do I tell lattice::xyplot to write charts in png files? thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://honestreporting.com http://jihadwatch.org http://think-israel.org http:

Re: [R] the value of the last expression

ot attached): > [1] R.methodsS3_1.4.2 tools_2.15.0 > A.K. > > > > > - Original Message - > From: Sam Steingold > To: r-help@r-project.org; Richard M. Heiberger > Cc: > Sent: Monday, December 10, 2012 2:13 PM > Subject: Re: [R] the value of the last express

[R] sum portions of a vector

ength 3 with content --8<---cut here---start->8--- 6 = 1+2+3 30 = 4+5+6+7+8 19 = 9+10 --8<---cut here---end--->8--- Obviously, I could write a loop, but I would rather have a vectorized version. Thanks! -- Sam Steingold (htt

Re: [R] the value of the last expression

piler::compilePKGS(1) --8<---cut here---end------->8--- > On Thu, Feb 9, 2012 at 9:44 PM, Sam Steingold wrote: > >> Is there an analogue of common lisp "*" variable which contains the >> value of the last expression? >> E.g., in lisp: &g

[R] list to matrix?

[1,] Numeric,2 [2,] Numeric,2 [3,] Numeric,2 [4,] Numeric,2 [5,] Numeric,2 [6,] Numeric,2 [7,] Numeric,2 [8,] Numeric,2 [9,] Numeric,2 --8<---cut here---end--->8--- thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 1

Re: [R] aggregate() runs out of memory

> * Steve Lianoglou [2012-11-27 12:53:23 > -0500]: > On Tue, Nov 27, 2012 at 11:29 AM, Sam Steingold wrote: >>> * Steve Lianoglou [2012-11-26 19:47:25 >>> -0500]: > [snip] >>> It just occurred to me that this is even better: >>> >>>

Re: [R] aggregate() runs out of memory

> * Steve Lianoglou [2012-11-26 19:47:25 > -0500]: > > On Monday, November 26, 2012, Sam Steingold wrote: > [snip] > >> >> there is precisely one country for each id. >> i.e., unique(country) is the same as country[1]. >> thanks a lot for the suggest

Re: [R] printing difftime summary

e, TIBCO Software > wdunlap tibco.com > > >> -Original Message- >> From: Sam Steingold [mailto:sam.steing...@gmail.com] On Behalf Of Sam >> Steingold >> Sent: Monday, November 26, 2012 4:09 PM >> To: William Dunlap >> Cc: r-help@r-project.

Re: [R] printing difftime summary

gt; Mean :3 Mean :2012-11-28 > 3rd Qu.:4 3rd Qu.:2012-11-29 > Max. :5 Max. :2012-11-30 >> summary(d$Delta) > Min.Med.Max > 1 days... 4 days...16 days > > My summary.difftime inherits from difftime so the format method is not really >

Re: [R] aggregate() runs out of memory

ant the same min and max values to be replicated as > many times as there are unique "country"s? there is precisely one country for each id. i.e., unique(country) is the same as country[1]. thanks a lot for the suggestion! > R> result <- f[, list(min=min(delay), max=max(delay), &g

Re: [R] printing difftime summary

> * David Winsemius [2012-11-26 08:46:35 -0800]: > > On Nov 26, 2012, at 7:14 AM, Sam Steingold wrote: > >> summary(infl), where infl$delay is a difftime vector, prints >> >> ... >> >>delay >> string:c("492.00 ms", "18.08 min&qu

Re: [R] aggregate() runs out of memory

hi Steve, > * Steve Lianoglou [2012-11-26 16:08:59 > -0500]: > On Mon, Nov 26, 2012 at 3:13 PM, Sam Steingold wrote: >>> * Steve Lianoglou [2012-11-19 13:30:03 >>> -0800]: >>> >>> For instance, if you want the min and max of `delay` within ea

Re: [R] aggregate() runs out of memory

ield in the original table infl which only depends on share.id, how do I add this unique value to the summary? it appears that "count=unique(country)" in list() does what I need, but it slows down the process. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise)

Re: [R] printing difftime summary

instead of something like delay Min.:492 ms 1st Qu.: 18.08 min &c so, how do I arrange for a proper printing of difftime summary as a part of the data frame summary? > * David Winsemius [2012-11-25 00:50:51 -0800]: > > On Nov 24, 2012, at 7:48 PM

Re: [R] printing difftime summary

-start->8--- > a <- summary(infl) Error in summary.difftime(X[[22L]], ...) : unused argument(s) (maxsum = 7, digits = 12) --8<---cut here---end--->8--- I guess I should somehow accept a list of options in summary.difftim

Re: [R] printing difftime summary

R-FAQ.html#How-should-I-write-summary-methods_003f what are the requirements on the class summary.foo? does it have to inherit from some other class? how do I define a class? -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.chi

Re: [R] printing difftime summary

efault', 'table'" as I assume summary must return. if these are not valid issues, then I wonder why my function should not be the system default method. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://memri.org ht

Re: [R] printing difftime summary

string secs Min.500.00 ms 0.5 1st Qu. 17.12 min 1027.0 Median 99.48 min 5969.0 Mean 8.30 hrs 29870.0 3rd Qu. 8.05 hrs 28970.0 Max.6.98 days 603100.0 --8<---cut here---end--->8--- -- Sam Steingold (http://sds.podval.o

[R] printing difftime summary

x < 6000) return(sprintf("%.2f min",x/60)) if (x < 108000) return(sprintf("%.2f hrs",x/3600)) if (x < 400*24*3600) return(sprintf("%.2f days",x/(24*3600))) sprintf("%.2f years",x/(365.25*24*3600)) } --8<---cut here

Re: [R] aggregate() runs out of memory

Thanks Steve, what is the analogue of .N for min and max? i.e., what is the data.table's version of aggregate(infl$delay,by=list(infl$share.id),FUN=min) aggregate(infl$delay,by=list(infl$share.id),FUN=max) thanks! Sam. On Fri, Sep 14, 2012 at 3:40 PM, Steve Lianoglou wrote: > Hi, > &g

Re: [R] generated list element names

> $ foo: num 10 >> I am sorry, how is this different from my second snippet (except that you use "x" and I use "z" and you use single quotes in paste and I use double quotes)? > > On Mon, Nov 19, 2012 at 1:07 PM, Sam Steingold wrote: >> How can I cr

[R] generated list element names

ere---start->8--- > z <- list(10) > names(z) <- paste("f","oo",sep="") > z $foo [1] 10 --8<---cut here---end--->8--- thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.

Re: [R] Optimizing

all combinations of 6 people as rows. Then, for each row, make a vector that is just all the types of the people in that row, a vector for the sum of the values, and a vector for the sum of the wages. Then, keep only those rows which have the correct types and wages under the max. Then, sort by th

[R] Optimizing

ion isn't very interesting, but the answer would be something like person C, D, E, F, G, and I (I didn't check to see that those prices sum to less than $20). How can I write a program that will do this? Can I just use the optimize command? Do I have to transform my dataset into some

Re: [R] as.data.frame(do.call(rbind, lapply)) produces something weird

2. I find the num->char->num conversion repugnant and unacceptable. -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://www.PetitionOnline.com/tap12009/ http://truepeace.org http://honestreporting.com http://ffii.org What was

[R] as.data.frame(do.call(rbind,lapply)) produces something weird

ariables: $ a : Factor w/ 3 levels "a1","a2","a3": 1 2 3 $ b.x: num 1 2 3 $ b.y: num 1 4 9 $ c.x: num 1 8 27 $ c.y: num 1 64 729 --8<---cut here---end--->8--- thanks! -- Sam Steingold (http://sds.podval.org/) on Ubu

Re: [R] LiblineaR: accept sparse matrices

Hi, > * Thibault Helleputte [2012-11-09 > 09:22:11 +0100]: > > The next release of LiblineaR should offer the possibility of using > sparse matrices. However, the next release date is not fixed yet... thanks. > On Thu, Nov 8, 2012 at 10:07 PM, Sam Steingold wrote: >>

Re: [R] LiblineaR: accept sparse matrices

> * Ben Bolker [2012-11-07 21:51:07 +]: > > Sam Steingold gnu.org> writes: > >> It would be nice if LiblineaR() accepted data in the form of a sparse >> matrix (it does not accept whatever e1071::read.matrix.csr returns). >> >> It would also be nic

[R] LiblineaR: accept sparse matrices

provides at least the input code. Thanks! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://iris.org.il http://pmw.org.il http://ffii.org http://dhimmi.com http://www.PetitionOnline.com/tap12009/ Sex is like air. It's only a big

[R] c weirdness

uot;=tab[1]) nons seed.0 ## don't want ".0"! 1 2344600 > c("nons"=1, "seed"=tab[2]) nons seed.1 ## don't want ".1"! 1 6843 > tab 0 1 23446006843 --8<---cut he

Re: [R] matrix.csr %*% matrix --> matrix

> * Martin Maechler [2012-11-07 10:10:51 +0100]: > >>>>>> "Sam" == Sam Steingold >>>>>> on Tue, 6 Nov 2012 13:08:30 -0500 writes: > > Sam> The question is even more pressing for me now given that I no longer > can >

Re: [R] write.matrix.csr data conversion

ints to what libsvm can read. > There is certainly a way to speed this up, but I am not likely to do > this in the near future. too bad. > On 2012-11-06 19:15, Sam Steingold wrote: >> David, >> thanks for adding the feature. >> >> read.matrix.csr and, es

Re: [R] write.matrix.csr data conversion

t; > On 2012-08-27 21:15, Sam Steingold wrote: >>> * jim holtman [2012-08-27 14:55:08 -0400]: >>> >>> Most likely when 'y' is converted to a dataframe (not sure what the >>> function 'write.matrix.csr' does since you did not say where you go

Re: [R] matrix.csr %*% matrix --> matrix

is small enough). > * Sam Steingold [2012-08-27 14:58:47 -0400]: > > When a sparse matrix is multiplied by a regular one, the result is > usually not sparse. However, when matrix.csr is multiplied by a regular > matrix in R, a matrix.csr is produced. > Is there a way to av

Re: [R] no method for coercing this S4 class to a vector

earch/sparse/sparse.html Packaged: 2012-03-18 19:39:05 UTC; root Repository: CRAN Date/Publication: 2012-03-18 20:55:08 Built: R 2.15.2; x86_64-pc-linux-gnu; 2012-11-05 17:46:36 UTC; unix > * Sam Steingold [2012-11-05 12:40:25 -0500]: > > all

[R] no method for coercing this S4 class to a vector

vector what has happened? how do I scale the matrix.csr object (to be written to a file)? PS. write.matrix.csr is very slow: it takes user system elapsed 1137.058 510.615 1649.925 to write the matrix "z" above. thanks! -- Sam Steingold (http://sds.podval.org/) o

Re: [R] R 2.15.2 is released

> * Marc Schwartz [2012-11-04 12:33:20 -0600]: > > On Nov 4, 2012, at 12:22 PM, Sam Steingold wrote: > >>> * Bert Gunter [2012-11-04 09:48:58 -0800]: >>> >>> ?update.packages >> >> It is not obvious to me that this is the answer to my q

Re: [R] R 2.15.2 is released

es() will _not_ try to update it, but, apparently, at least for some packages, I do need to rebuild them against the new R version 2.15.2. Thanks. > On Sun, Nov 4, 2012 at 7:01 AM, Sam Steingold wrote: >> I have some packages installed using install.packages(). >> Do I need to reinsta

Re: [R] R 2.15.2 is released

ching your R installation. In other words: One way to fix your problem is to re install the Matrix package in the version of R you are using. So, will the bug reappear now? -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000 http://www.childpsy.net/ http://openvotingco

Re: [R] how to concatenate factor vectors?

do what I need. I see that identical(levels(concatenate.factors(a,b)),levels(a)) ==> TRUE DIUC that concatenate.factors does NOT create an intermediate vector and then re-factor it? Thank you very much for your insight! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.1110300

Re: [R] how to concatenate factor vectors?

> * Jeff Newmiller [2012-10-18 07:53:24 -0700]: > > If you HAVE defined your factors using explicit levels definitions, you > should have no trouble combining them. http://article.gmane.org/gmane.comp.lang.r.general:277719 -- Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04

Re: [R] how to concatenate factor vectors?

> * R. Michael Weylandt [2012-10-18 16:01:37 > +0100]: > > On Thursday, October 18, 2012, Sam Steingold wrote: > >> > * Bert Gunter [2012-10-17 23:21:44 -0700]: >> > >> > However, Is level "5" in 'a' the same as level "5&

Re: [R] how to concatenate factor vectors?

pped to a character vector via letters, which is converted back to integers (==factors). IIUC, a factor is an integer vector which knows that the integers refer to levels. c(a,b) creates such an integer vector. How do I tell it that it is a factor? -- Sam Steingold (http://

Re: [R] how to concatenate factor vectors?

> * Bert Gunter [2012-10-17 23:21:44 -0700]: > > However, Is level "5" in 'a' the same as level "5" in 'b' ? yes, of course. would anyone want to _different_ factors with identical string representations?! -- Sam Steingold (http://sds.podval.org

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