Re: [R] problem with abline and lines

Hi! You forgot to invert the slope: a perpendicular of 1/sqrt(2) should be -sqrt(2). Also, you should add asp=1 in the plot command to lock the aspect ratio, otherwise the scale of both X and Y may be different according to the size of the window: plot(x=c(-1, 1), y=c(-1, 1),asp=1); abline(a=0, b=

Re: [R] remove substring from each string vector component

Hi! It's just this easy: x=gsub("\t","",x) For more complex things, it's worth learning some regular expressions syntax. Miguel On Tue, Mar 16, 2010 at 2:50 PM, arnaud chozo wrote: > Hi all, > > I have a string vector like that: x=c("1\t\t", "2", "3\t\t\t") > I need to remove all the occurrenc

Re: [R] Time in minutes

Hi! That should do it: yourtime$min+yourtime$hour*60 In case your object is of class POSIXlt. Otherwise, convert it with as.POSIXlt first. Miguel On Mon, Mar 15, 2010 at 3:57 PM, Carlos Nader wrote: > Hi there! > > I have some data in POSIXlt format: > > 2009-07-18 5:53:00 > 2008-11-23 7:27:0

Re: [R] storing matrix(variables) in loop

Yeah, that sounds inefficient to me also. I think you'd be better off using multidimensional arrays instead of lists, since all your values are numeric. See ?array. Miguel 2010/3/15 Márcio Resende > > Hello R-helpers, > I have the following code that works well, > > b <-list() > for (i in 1:3)

Re: [R] storing matrix(variables) in loop

Just in case... b=array(NA,c(3,3,3,4))# that means b[matrix-row,matrix-col,i,j] for (i in 1:3){ for (j in 1:4){ b[,,i,j]=matrix(runif(1),3,3) } } b (I think there are better ways to do this anyway...) Miguel [[alternative HTML version deleted]] __

Re: [R] for() loop

Sorry, I missed the [,4] : aggregate(datjan[,4],by=list(datjan[,4]),sum) Miguel [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R

Re: [R] for() loop

Hi, I usually use aggregate() for this: aggregate(datjan,list(datjan[,4]),sum) with the advantage that you can use any other aggregation function (mean, var and so on...). See help. Miguel On Sun, Mar 14, 2010 at 8:49 PM, Schmidt Martin wrote: > Hello > > I'm working with R since a few month

Re: [R] Return one value, print another

Yeah that's right; in that case implementing the print.myclass as you say would be the best option. Miguel On Fri, Mar 12, 2010 at 2:17 PM, Dieter Menne wrote: > > > Miguel Porto wrote: > > > > Hmm... do something like that, no need to change the global option (I >

Re: [R] Return one value, print another

Hmm... do something like that, no need to change the global option (I used a named vector instead of a list, it's more convenient): eg <- function(x, digits=4) { xbar <- mean(x) sdx <- sd(x) value <- c(xbar, sdx) names(value) <- c("Mean of X", "SD of X") print(round(value,digits)); return(invisibl

Re: [R] Creating named lists

Hi See if this function works for you (I didn't properly test it...): nlist=function(...) { a=list(...); names(a)=as.character(match.call()[2:(length(a)+1)]) return(a); } Ex: > a=1:3 > b=matrix(1:10,nc=2) > nlist(a,b) $a [1] 1 2 3 $b [,1] [,2] [1,]16 [2,]27 [3,]

Re: [R] Can't convert list to matrix properly

see for yourself - AFAIK it'll just concatenate eveverything which is "atomic" into a vector, thus losing all the structure associated. Miguel On Thu, Mar 11, 2010 at 4:14 PM, anna wrote: > > Yes, definitely! so unlist() turns the list components into a vector? What > if > the component are vec

Re: [R] Can't convert list to matrix properly

Hi, Is this what you want? matrix(unlist(myList),nr=1) Miguel On Thu, Mar 11, 2010 at 4:03 PM, anna wrote: > > Hi guys, here is a list of names that I have: > > MyList: > > myList<-list("A", "B","C","D") > > myList > [[1]] > [1] "A" > > [[2]] > [1] "B" > > [[3]] > [1] "C" > > [[4]] > [1] "D" >

Re: [R] Comparing matrices

Also look at ?any and ?all Very handy functions. Miguel On Thu, Mar 11, 2010 at 12:37 PM, Esmail wrote: > Hello all, > > I have two matrices, pop and pop2, each the same number of rows and > columns that I want to compare for equality. I am concerned about > efficiency in this operation. >

Re: [R] Joining elements of an array into a single element

Hello, If you do this after the for loop, you'll get what you want: paste(tre,collapse="") (you can use whatever separator you want in the collapse argument) But you don't even need the for loop, just do this instead of the for loop: paste("con(",p," == ",c,", ",zest,", ",sep="",collapse="") B

Re: [R] (box-) plot annotation: italic within paste?

Hello, Try this way (not sure if it's the best way, but it works): boxplot(x[,i], main=substitute(expression(paste(a," ",italic(b)," ",c)),list(a=mainlabel1,b=predictor[i],c=mainlabel2)), ylab=paste(ylabel),cex.lab=cexalabel,cex.main=cexmlabel,cex.axis=1.5) Best, Miguel On Mon, Mar 8, 2010 at