MKclass::perfMeasures(predict_testing, truth = testing$case, namePos = 1)
should also work and computes 80 performance measures.
Best Matthias
Am 25.10.22 um 06:42 schrieb Jin Li:
Hi Greg,
This can be done by:
spm::pred.acc(testing$case, predict_testing)
It will return both sensitivity and
Response to 1You need the log version e.g. in maximum likelihood, otherwise the
product of the densities and probabilities can become very small.
Ursprüngliche Nachricht Von: r-help-requ...@r-project.org
Datum: 04.08.21 12:01 (GMT+01:00) An: r-help@r-project.org Betreff: R-help
.
Best wishes,
Matthias
PS. Sorry for the HTML email. I’ve given up trying to fix such behavior.
Von: Martin Maechler
Gesendet: Dienstag, 13. Juli 2021 09:09
An: Matthias Gondan
Cc: r-help@r-project.org
Betreff: Re: [R] density with weights missing values
>>>>> Matthias Gonda
You're right, of course. Extrapolating your argument a bit, the whole practice
of na.rm is questionable, since there's always a reason for missingness (that
is not in x and rarely elsewhere in the data)Best wishes Matthias
Ursprüngliche Nachricht Von: Jeff Newmill
thing?
Ursprüngliche Nachricht Von: Bert Gunter
Datum: 12.07.21 16:25 (GMT+01:00) An: Matthias
Gondan Cc: r-help@r-project.org Betreff: Re: [R]
density with weights missing values The behavior is as documented
AFAICS.na.rmlogical; if TRUE, missing values are removed from x. If FALSE
anymissing v
a.rm=TRUE)
[1] 2
Von: Richard O'Keefe
Gesendet: Montag, 12. Juli 2021 13:18
An: Matthias Gondan
Betreff: Re: [R] density with weights missing values
Does your copy of R say that the weights must add up to 1?
?density doesn't say that in mine. But it does check.
On Mon, 12 Jul 2021
weights,
the check for sum(weights) == 1 might trigger false positive warnings since the
weights might not add up to 1 anymore
Best wishes,
Matthias
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substitute, or should I choose another
solution? Having said this, it may be a good idea to expose a function
Rf_R_initialized that performs such a test.
Thank you for your consideration.
Best regards,
Matthias
*The use case is an R library that connects to swi-prolog and allows the
„embedded“
you could try:
library(MKinfer)
meanDiffCI(a, b, boot = TRUE)
Best
Matthias
Am 04.08.20 um 16:08 schrieb varin sacha via R-help:
Dear R-experts,
Using the bootES package I can easily calculate the bootstrap confidence
intervals of the means like in the toy example here below. Now, I am
should have added: dim(x)[2L] -> length(x)
Am 31.03.20 um 16:21 schrieb Prof. Dr. Matthias Kohl:
Dear Ivan,
if I enter ncol in the console, I get
function (x)
dim(x)[2L]
indicating that function dim is called. Function dim has a method for
data.frame; see methods("dim").
T
Hence, it calls length on the provided data.frame. In addition, some
"magic" with .row_names_info is performed, where
base:::.row_names_info
function (x, type = 1L)
.Internal(shortRowNames(x, type))
Best
Matthias
Am 31.03.20 um 16:10 schrieb Ivan Calandra:
Thanks Ivan for the answer
Have a look at Bioconductor package genefilter, especially functions
colttests and colFtests.
Best Matthias
Am 10.02.19 um 10:35 schrieb AbouEl-Makarim Aboueissa:
Dear All: good morning
*Re:* How to rum Multiple ANOVA and Multiple T-test between the same groups.
Your help will be
happen? [it’s documented
behavior, but still…]
So, I’ll stick with R. Still 25 years or so until retirement, but I’ll survive,
even without crossreferenced default arguments.
Best wishes,
Matthias
Von: S Ellison
Gesendet: Dienstag, 5. September 2017 16:17
An: Matthias Gondan; r-help@r-project.
mu=0.53, sigma2=4.3^2) # instead of l=u
And maybe also „in-place“ changes of values…
Best regards,
Matthias
Von: William Dunlap
Gesendet: Samstag, 2. September 2017 19:41
An: Rui Barradas
Cc: Matthias Gondan; r-help@r-project.org
Betreff: Re: [R] Strange lazy evaluation of default argume
er place, and L is divided twice by 4.3.
Is this behavior intended? It seems strange that the result depends on a
debugging message.
Best wishes,
Matthias
> sessionInfo()
R version 3.4.1 (2017-06-30)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows >= 8 x64 (build 9200)
... Thanks for the help
r <- as.vector(lw)
count=0
for (i in r) {
if(i == 0.990956) {
break
}
print(i)
}
Best
Matthias
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, not the variables themselves.
Best
Matthias
Am 06.04.2017 um 18:32 schrieb Joel Gagnon:
Dear all,
It is my first time posting on this list so forgive me for any rookie
mistakes I could make.
I want to conduct t-tests on a dataset that has been imputed using the mice
package:
imput_pps <- mi
could be 1 if the data is from ordered categories.
- Or both.
It is probably a little thing to fix, but I lack the skills to do this myself.
Best wishes,
Matthias
Von: Bert Gunter
Gesendet: Dienstag, 14. März 2017 21:34
An: matthias-gon...@gmx.de
Cc: r-help@r-project.org
Betreff: Re: [R] Quantiles
an elegant workaround?
Thank you.
Best wishes,
Matthias
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Hello together,
is it possible, to summing up a matrix?
I have the following matrix at the moment:
[,1] [,2] [,3][,4]
[,5] [,6]
2016-1120200100 50 100
30
2016-12
Andre,
you need to make sure you got a C/C++ compiler as well as a Fortran compiler to
compile a package from source that makes use of these language. Many R packages
use one of those languages under the hood to speed things up.
gcc / gfortran are common and free choices for such compilers. D
Hello togehter,
i have short question, maybe anyone can help me.
I have a data.frame like this one:
NO ORDER
1 1530 for Mr. Muller (10.0 -> 11.2)
2 1799 for Mr Giulani
3 1888 for Mr. Marius (11.2 -> 12)
I need a solution, which only contains the values in br
Hello togehter,
maybe anyone can help me with a little problem.
I have the following column in an data.frame (called TEST)
VERSION
1abc (9.2 -> 10.0)
2def (10.2 -> 11.0)
3ghi (7.4 -> 8.4)
4jkl (10.2 -> 10.4)
5mno (8.1 -> 9.0)
I now need the code for the following resul
ependently). Thank you for the help!!
If you need to create the plots you can simply change the
"runmean_10yr_Nino_3_Index_17th_century" to any other vector.
Best Matthias
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htt
Matthias
aa <- OHC_d[40:70]
bb <- OHC_d[50:80]
cc <- OHC_d[173:203]
dd <- OHC_d[205:235]
ee <- OHC_d[273:303]
ff <- OHC_d[292:322]
gg <- OHC_d[302:332]
hh <- OHC_d[370:400]
ii <- OHC_d[381:411]
s3 <- data.frame(aa,bb,cc,dd,ee,ff,gg,hh,ii)
y2 <- ggplot(s3,aes(x=time2,y=
osting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Prof. Dr. Matthias Kohl
www.stamats.de
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https://stat.e
ing heat content.
The error I got was the following:
Error: unexpected symbol in "Trend <- function(x,y,z) { lm x"
Thanks a lot for the help!
Best Matthias
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Dear list-eners,
I run into the following problem when I want to get contrasts from a coxme
model using the lsmeans package: A call to lsmeans on the coxme model
throws the following error:
Error in if (adjustSigma && object$method == "ML") V = V *
object$dims$N/(object$dims$N - :
missing valu
t regards.
Mat
-Ursprüngliche Nachricht-
Von: David L Carlson [mailto:dcarl...@tamu.edu]
Gesendet: Montag, 9. März 2015 16:08
An: Matthias Weber; r-help@r-project.org
Betreff: RE: calculate value in dependence of target value
It is very hard to figure out what you are trying to do.
1. Al
Hello together,
i have a litte problem. Maybe anyone can help me.
I have to calculate a new column in dependence of a target value.
As a example: My target value is 100.000
At the moment I have a data.frame with the following values.
IDVALUE
1 111
2 125
3 1330
Hello together,
i have a data.frame with date-values. What I want is a data.frame with a
several lines for each date.
My current data.frame looks like this one:
ID FROM TOREASON
1 2015-02-27 2015-02-28Holiday
1 2015-03-15 2015-03-20Illness
2
Hello togehter,
i have a little problem. Maybe anyone can help me.
I have 2 data.frames, which look like as follows:
First:
NAMEMONTH BONUS
1 Andy 2014-10 100
2 Pete 2014-10200
3 Marc2014-10300
4 Andy2014-11400
Se
Hello togehter,
i have a little problem, maybe anyone can help me.
I have a data.frame, which look like this one:
ID Members
1 1 ; abc; def; ghi
2 2 ; abc;
3 3 ;def;
How can I create another column for each value between 2 semicolons?
The resul
a lot.
Best regards.
Mat
-Ursprüngliche Nachricht-
Von: Jim Lemon [mailto:j...@bitwrit.com.au]
Gesendet: Montag, 27. Oktober 2014 09:47
An: Matthias Weber
Cc: r-help@r-project.org
Betreff: Re: AW: [R] dotplot with library lattice
On Mon, 27 Oct 2014 08:53:51 AM Matthias Weber wrote
-
Von: Jim Lemon [mailto:j...@bitwrit.com.au]
Gesendet: Samstag, 25. Oktober 2014 03:27
An: Matthias Weber
Cc: r-help@r-project.org
Betreff: Re: AW: [R] dotplot with library lattice
On Fri, 24 Oct 2014 12:49:39 PM Matthias Weber wrote:
>
> I want always to see the "Process" of the
Jim Lemon [mailto:j...@bitwrit.com.au]
Gesendet: Freitag, 24. Oktober 2014 11:29
An: r-help@r-project.org
Cc: Matthias Weber
Betreff: Re: [R] dotplot with library lattice
On Thu, 23 Oct 2014 05:57:27 PM Matthias Weber wrote:
> Hello together,
>
> i have a short question. Maybe anyone can help m
Hello together,
i have a short question. Maybe anyone can help me to create a barplot in R with
the package lattice.
I have the following data as ouput values and the following code:
Data (d):
KOST BudgetIST
1060 -2.18 0
1080 9
Hello together,
i have a little problem. Maybe anyone can help me.
I have a data. frame which look like this one:
1000 1001 10021003
15 6 1211
24 3 81
What i need is a data.frame, which looks like this one. The Column na
I had a strange behavior of a function written a few days ago. I
pointed the problem down to the following minimal example.
can anyone explain why the following comparisons don't reply the
same"correct" answer?
Thanks for your reply!
Matthias
R version 3.1.1 (2014-07-10) --
Dear list.
I am stuck with an "subscript out of bounds" error when I play with an
nlme-example from the yellow Pinheiro/Bates book. It is about using
nlme() using the formula interface for non-linear mixed models.
The following code snippet is inspired by the book (in section 8.2),
using the Oran
.
This is a pretty nice applied course that uses R for illustration:
https://stat.ethz.ch/education/semesters/ss2012/atsa
apart from this course, I think Prof. Rob Hyndman (who also has a blog) has a
lot of useful stuff to say when it comes time series analysis with R
best
Matthias Bannert
KOF
d like to do (in addition):
restrict the matching in way that only allows for matches within the same year,
so that only propensity scores within the same year are considered for a
respective match. Note that I don't what to estimate the years separately.
Is there a way to do so?
best r
g/v59/i04/ (will appear
soon) resp. a previous version at http://arxiv.org/abs/1006.0764
hth
Matthias
Am 11.08.2014 um 10:17 schrieb pari hesabi:
Hello everybody,
Can anybody help me to write a program for the CDF of sum of two independent
gamma random variables ( covolution of two gamma dist
you could use package distrEx:
library(distrEx)
GLIntegrate(function(x) x^2, lower = -1, upper = 1, order = 50)
hth
Matthias
On 01.05.2014 09:43, pari hesabi wrote:
Hello everybody
I need to approximate the amount of integral by using
legendre quadrature. I have written a program which
t;- 3*x1 + 2*x2
plot(x4)
For more details on the computations see http://arxiv.org/abs/1006.0764
hth,
Matthias
On 22.04.2014 13:11, Ms khulood aljehani wrote:
Hello
i have two independent variablesx1 from normal (0,1)x2 from bernoulli (o.75)
i need the density estimation of(b1*x1) + (b2*x2)
whe
ot in Linux. So this seems to be a problem related
to Windows.
Kind regards
Matthias
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von David McPearson
Gesendet: Sonntag, 6. April 2014 12:19
An: r-help@r-project.org
Betreff: R
quot;2038" "2039" "2040" "2041"
"2042" "2043" "2044" "2045" "2046" "2047" "2048" "2049"
[91] "2050" "2051" "2052" "2053" "2054&qu
. I would be
thankful if you could help me with that.
All the best,
Matthias
//
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Hi
I have managed to install MPICH2 and Rmpi on my Windows 7 machine. I can
also run the following code
> library(Rmpi)
> mpi.spawn.Rslaves()
4 slaves are spawned successfully. 0 failed.
master (rank 0, comm 1) of size 5 is running on: MyMaster
slave1 (rank 1, comm 1) of size 5 is runnin
Hi
I have managed to install MPICH2 and Rmpi on my Windows 7 machine. I can
also run the following code
> library(Rmpi)
> mpi.spawn.Rslaves()
4 slaves are spawned successfully. 0 failed.
master (rank 0, comm 1) of size 5 is running on: MyMaster
slave1 (rank 1, comm 1) of size 5
see function SMOTE in package DMwR
hth
Matthias
On 31.03.2013 10:46, Nicolás Sánchez wrote:
I have a question about data mining. I have a dataset of 70 instances with
14 features that belong to 4 classes. As the number of each class is not
enough to obtain a good accuracy using some classifiers
1 0
2 1 02
Thanks for your help
Von: John Kane [mailto:jrkrid...@inbox.com]
Gesendet: Freitag, 8. März 2013 16:29
An: Matthias Weber
Betreff: RE: AW: [R] create bar chart with different totals in a bar
The image did not come
use pmin instead of min.
hth
Matthias
On 12.02.2013 16:41, dan wang wrote:
Hi All,
Can any one help to explain why min and max function couldn't work in the
integrate function directly.
For example, if issue following into R:
integrand <- function(x) {min(1-x, x^2)}
integrate(i
+ 1:2
at the command prompt to see what type of unintended things happen.
Actually, 1:4 + 1:2 is running silently.
Best wishes,
Matthias
Am 17.11.2012 19:56, schrieb Rui Barradas:
Hello,
First of all, that's not an error message, it's a warning.
As for your condition, it's t
On 15/11/12 21:22, David Winsemius wrote:
On Nov 15, 2012, at 5:38 AM, Matthias Ziehm wrote:
Hi all,
Sorry if this has been answered already, but I couldn't find it in the archives
or general internet.
A Markmail/Rhelp search on: gompertz survreg ...brings this link to a reply
by
Same questions for the gompertz-makeham distribution.
Many thanks!
Matthias
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and provide commente
..
Matthias.
On Mon, Oct 29, 2012 at 10:42 PM, asafwe wrote:
> Hi there,
>
> I am looking to fit a two-way random effects model to an *unblalanced*
> layout,
>
> y_ijk = mu + a_i + b_j + eps_ijk,
> i=1,...,R, j=1,...,C, k=1,...,K_ij.
>
> I
lim=c(-Inf, Inf)[as a replacement for NULL/
autoselection] and ylim=c(Inf, -Inf)[autoselection, reversed y axis] should be
handled correctly.
I would find such a feature useful. Do you think it would interfere with other
functions?
Thank you for your consideration.
Best wishes,
Matth
you might to do something like
library(SuppDists)
t = runif(100, 100, 500) # original RT
t_IG = qinvGauss(ecdf(t)(t)-0.5/length(t), 1, 16)
plot(density(t_IG))
but what is the purpose of it? Usually reaction times are thought to
follow a certain kind of distribution (e.g. an inverse Gaussian
dis
Hey everyone,
I am an R-newby... so sorry for bothering you with simple-to-solve
questions;) I have the following issue: trying to add labels to my
scatterplots (with geom_dl in ggplot2). Everything works fine, but after
checking every resource I do not find a way to change the font size of my
lab
My vote:
1. Symbolic function arguments:
fn = function(a, b)
{
a/b
}
fn(b=10, a=2)
2. Names for elements of a vector and matrices
v = c(a=1, b=2)
v['a'] = v['a'] * 2
same for matrices
3. about 10,000 user-contributed packages on CRAN
4. weird things like
a = numeric(10)
a[1:10] = 1:2
take a look at the distr package
library(distr)
U <- Unif()
U2 <- U + U
# or
U2 <- convpow(U, 2)
plot(U2)
# or
curve(d(U2)(x), from = 0, to = 2)
Best
Matthias
On 24.05.2012 08:29, c...@mail.tu-berlin.de wrote:
Hi,
I want to convolve 2 uniform distributed [0,1] variables, so that I
On 23.04.2012 20:55, Brian Diggs wrote:
> On 4/23/2012 9:24 AM, Matthias Rieber wrote:
>> Hello,
>>
>> I've some problem with the ggplot2. Here's a small example:
>>
>> [...]
>> Is it wrong to use geom_bar with that kind of data? I could avoid thi
you should also look at Bioconductor Package Biostrings
hth
Matthias
Am 19.04.2012 18:01, schrieb R. Michael Weylandt:
Though if you do decide to use Levenstein, it's implemented here in R:
http://finzi.psych.upenn.edu/R/library/RecordLinkage/html/strcmp.html
I'm pretty sure this is
try:
Sweave("sim_pi.Rnw", encoding = "utf8")
Best,
Matthias
On 15.04.2012 11:41, Philippe Grosjean wrote:
Hello,
Have you tried to put that command in a comment:
%\usepackage[utf8]{inputenc}
I haven't tested it in this particular case, but it works in some other
si
interaction.plot source:
legend(xleg, yleg, legend = ylabs, col = col, pch = if (type %in%
c("p", "b"))
pch, lty = if (type %in% c("l", "b"))
lty, bty = leg.bty, bg = leg.bg) <- here I woul
Dear R team, dear Prof. Therneau,
library(survival)
data(colon)
?colon
gives me only a very rudimentary source (only a name). Is there a
possibility to get a reference to the clinical trial these data
are taken from?
Many thanks in advance. With best wishes,
Matthias Gondan
Dear Gerhard,
you could also use package "distr"; e.g.
library(distr)
## use generating function "AbscontDistribution"
D <- AbscontDistribution(d = function(x) dbeta(x, 2, 6) + dbeta(x,6,2),
low = 0, up = 1, withStand = TRUE)
## quantiles
q(D)(seq(0,1,0.1))
Best
Mat
Hi Ben,
Thanks for clarifying this, I used a misleading word, "model" the
observation time
sounds as if observation time were the dependent variable - which it is
not, of course,
instead, in the scenario described, the parrot counts are modeled.
Best wishes,
Matthias
Am 30.12.
, your example seems
incorrect, because it is a predictor, not the dependent variable
tnoise_sqrt ~ lengthfeeding_log
Best wishes,
Matthias
Am 30.12.2011 16:29, schrieb Lucy Dablin:
> Great lists, I always find them useful, thank you to
> everyone who contributes to them.
>
>
>
,
Matthias
--
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"save as metafile" causes a segmentation fault.
Everything worked fine on 2.13.0
Best wishes,
Matthias
--
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Dear Eduardo,
try:
f <- function(x){}
s <- 0.2
body(f) <- substitute({x^2 + s}, list(s = s))
Best,
Matthias
On 15.02.2011 16:53, Eduardo de Oliveira Horta wrote:
Thanks... but I guess I didn't make myself clear. What I was trying to
do was precisely to "store" inside
Dear Gabriel,
it is possible. You can define a new class or just an object of an
already existing class.
Did you look at:
library(distr)
vignette("newDistributions")
as well as
?AbscontDistribution
?DiscreteDistribution
Please let me know if you have further questions!
Best
Ma
em with my installation? Has someone else noticed that issue?
Regards,
Matthias
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yrnorm(4))
[1] 0.2875775 0.7883051 0.4089769 0.8830174
Best wishes,
Matthias Gondan
--
GMX DSL Doppel-Flat ab 19,99 Euro/mtl.! Jetzt mit
gratis Handy-Flat! http://portal.gmx.net/de/go/dsl
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l/lib/libptf77blas.a
/usr/local/lib/libatlas.a -lpthread"
make
make install
Using your benchmark example, all CPUs seem to be used. It is now
working at such a high speed that I could not entirely be sure, "top"
refreshes only every 5 s.
Cheers
Matthias
Am 09.08.2010 11:51, schrieb
try this (package Rsolnp)
library(Rsolnp)
g<- function(x)
{
return(x[1]^2+x[2]^2)
} # constraint
f<- function(x)
{
return(x[1]+x[2])
} # objective function
x0 = c(1, 1)
solnp(x0, fun=f, eqfun=g, eqB=c(1))
Am 10.08.2010 14:59, schrieb Gildas Mazo:
Thanks, but I still cannot get to sol
try command solnp in package Rsolnp
Am 09.08.2010 18:56, schrieb Dwayne Blind:
Hi !
Why not constrOptim ?
Dwayne
2010/8/9 Gildas Mazo
Dear R users,
I'm looking for tools to perform optimization subject to constraints,
both linear and non-linear. I don't mind which algorithm may be used, m
be helpful.
Searching around the internet was not very encourageing. Some people
wrote that it is not so simple to have Atlas fully exploit a multicore
computer.
I hope this is not too unspecific.
Best wishes,
Matthias
--
Dr. rer. nat. Matthias Gondan
Institut für Psychologie
Universität Regensbu
/distr.pdf
Best,
Matthias
On 27.07.2010 10:37, Dennis Murphy wrote:
Hi:
On Mon, Jul 26, 2010 at 11:36 AM, xin wei wrote:
hi, this is more a statistical question than a R question. but I do want to
know how to implement this in R.
I have 10,000 data points. Is there any way to generate a empirical
clearly reduce computation time (as in the case of package RobLox)
are unfortunately not yet implemented.
So, if you are willing to accept these drawbacks I will be glad to give
you a hand to get our estimators to work for your data.
Best,
Matthias
On 06.06.2010 06:47, Alex Weslowsk
] 13888 14166 14188 14189 14189 ...
> result <- format(test.data, format="%G-%V")
Error: segfault from C stack overflow
>
this happens with a self compiled R version and the debian packages.
The same operation works with R 2.9.x and R 2.10.x
I've attached the backtrace.
kind rega
are some R scripts from Brunner et al. available on his website
http://www.ams.med.uni-goettingen.de/de/sof/ld/index.html
But they seem not to be working with current R versions.
Best regards,
Matthias Gondan
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jetzt koste
ter of taste, but I like the $ very much. Unfortunately,
vx$a is not
functional. Would it break existing compatibility if the $ would be
allowed to
access elements of a vector, as well?
Best regards,
Matthias
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sequence alignment.
To get a first impression try:
vignette("RFLPtools")
as well as
library(RFLPtools)
example("RFLPplot")
example("RFLPrefplot")
Best regards,
Fabienne
Alexandra
Matthias
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Dr. Matthias Kohl
www.stamats.de
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ce check time ...
- some minor corrections in ExamplesEstimation.R in folder scripts
Best
Peter
Matthias
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Dr. Matthias Kohl
www.stamats.de
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vignette:
* included an example with escape sequences in vignette
* included an example with framed code in vignette
Best
Peter
Matthias
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www.stamats.de
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range of lat/lon values.
If I run the above-mentioned, I just get the map of Europe, without the
contourplot.
When commenting the "map" statements I can see the contourplot.
So I am doing something wrong, but I really
Introduction to Metabolomics and biomarker research.
The course will take place in Innsbruck, 16th to 17th November 2009, and
will be held in German.
For more details see:
http://www.gdch.de/vas/fortbildung/kurse/fortbildung2009.htm#1175
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I think it should be
var(y[i-3:i-1,])
instead of
var(x[i-3:i-1,])
otherwise the values of the vector are overwritten
Best wishes,
Matthias
marlene marchena schrieb:
Dear R-user
Suppose I have the following data
y=c(2,1,5,8,11,3,1,7,50,21,33,7,60)
x=data.frame(y)
for(i in 4:nrow(x
4.6742 0.0309
In the original data set, denDF is >200 000.
Once again, how do I correctly account for pseudoreplication, avoiding
the artificially high number of df ?
Thank you,
Matthias
Matthias Gralle wrote:
Hello everybody,
it may be better to have sample data. I have provided
it is the wrong formula.
Can anybody give me some advice on this problem ? Or should I just stick
to reducing the data from each condition to a single parameter, as
explained in my first email below?
Thank you again!
Matthias Gralle wrote:
Hello everybody,
I have been trying for some weeks to
8-10-20) on Ubuntu 8.04 on a
linux 2.6.24-24-generic kernel on different Intel systems. I am using
the lme4 that came with R 2.8.0.
Thank you very much for your time!
-- Matthias Gralle, PhD
Dept. Evolutionary Genetics
Max Planck Institute for Evolutionary Anthropology
Deutscher Platz 6
04103
some t.
Best wishes,
Matthias
PS. This one would be ok, as well:
F(t) > G(t), for all t
null hypothesis: F(t) <= G(t), for some t.
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if your matrix has many rows you might want to consider rowMedians from
Bioconductor package Biobase.
hth,
Matthias
Greg Hirson schrieb:
Edward,
See ?apply
x = matrix(rnorm(100), ncol = 10)
apply(x, 1, median)
Hope this helps,
Greg
Edward Chen wrote:
Hi,
I tried looking through google
for teaching purposes I wrote a corresponding function; cf.
qbxp.stats (as well as qboxplot ...) in package MKmisc.
hth,
Matthias
Deepayan Sarkar schrieb:
On Tue, Jul 21, 2009 at 7:47 AM, Jun Shen wrote:
Uwe,
Thank you for your reply. I am still not very clear about the meanings of
the
m
optim(c(1,5), llik.nor, x=x, control = list(fnscale = -1))
hth,
Matthias
Anjali Sing schrieb:
Hello, I am having trouble using "optim".
I want to maximalise a function to its parameters [kind of like: univariate
maximum likelihood estimation, but i wrote the likelihood function mys
his is rather a quick and dirty solution and it would of
course be better to have a valid definition for r, d, p and q.
Best,
Matthias
guillaume.martin schrieb:
Dear Mathias,
That's pretty amazing, thanks a lot ! I'll have to look all this
through because I don't easily unders
Dear Guillaume,
thanks for your interest in the distrMod package.
Regarding your question I took up your example and put a file under:
http://www.stamats.de/distrModExample.R
Hope that helps ...
Don't hesitate to contact me if you have further questions!
Best,
Matthias
guillaume.m
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