Greetings,
Thanks Jeff. I appreciate your 'to the point' explanation. Will read into
it more.
Best,
Heramb Gadgil
2013/8/19 Jeff Newmiller
> 1. Keeping the number of variables down encourages you to structure your
> data, which allows you to re-use code more efficiently.
mpact
everything in minimum number of functions
4. The in-memory of R is just 10% of your total RAM (Correct me if wrong).
Make sure most of it is used for processing and not storing
Hope this will help. Kindly suggest if I have misunderstood anything.
Thanks and Regards,
Heramb Gadgil
2013/8/1
;- "B"
> > cvtest[[lambda.rule]]
> NULL
> > lambda.rule <- "Bozo"
> > cvtest[[lambda.rule]]
> [1] 2
> > lambda.rule <- "Joe's Test"
> > cvtest[[lambda.rule]]
> [1] 3
>
> Also, I find it hard to read code involv
est[[lambda.rule]] is
> much easier to read and understand than
> eval(parse(text=paste0("cvtest$",lambda.rule)))
>
>
> On 27.12.2012, at 11:44, Heramb Gadgil wrote:
>
> > I am not sure why "Never ever!"
> >
> > Can you please elaborate. What are the ne
I am not sure why "Never ever!"
Can you please elaborate. What are the negatives about the method
Warm Regards,
Heramb M. Gadgil
On Thu, Dec 27, 2012 at 3:50 PM, Uwe Ligges wrote:
>
>
> On 27.12.2012 08:09, Heramb Gadgil wrote:
>
>> eval(parse(text=paste0("**
eval(parse(text=paste0("cvtest$",lambda.rule)))
I hope this works.
On Wed, Dec 19, 2012 at 12:57 AM, Thomas Stewart
wrote:
> Soyeon-
>
> A possible solution:
>
> get(lambda.rule,envir=list2env(cvtest))
>
>
> On Tue, Dec 18, 2012 at 12:34 PM, Soyeon Kim wrote:
>
> > Dear my R friends,
> >
> > I
You can try this one too.
#Set the directory to a path where all the files to be read are stored
TabletoRead=list.files(pattern=".txt")
I_Step=unlist(lapply(TabletoRead,function(tab){
srno<<-ifelse(exists("srno"),(1+srno),1)
Temp=read.table(tab,header=T,s
try this:
colnames(df)<-df_names[1:ncol(df),"name"]
On Sun, Dec 23, 2012 at 8:41 PM, radhi wrote:
> Hi, I've got a dataframe having a code as column name. Addtionally I have
> another dataframe with a two columns (and lots of rows), the first
> containing the code and the second some Text (real
You can look for different versions of that package and try manually
installing the lower version.
On Fri, Sep 28, 2012 at 11:25 PM, Uwe Ligges <
lig...@statistik.tu-dortmund.de> wrote:
>
>
> On 28.09.2012 00:32, Duncan Murdoch wrote:
>
>> On 12-09-27 2:53 PM, Anju R wrote:
>>
>>> Sometimes when
We can have something like this;
*Data1<-data.frame(Site1=c(5,NA,4),Site2=c(3,2,4),Site3=c(NA,5,NA))
Data2<-data.frame(TraitType1=c(1,2,3),TraitType2=c(2,4,2),TraitType3=c(5,1,1))
*
*rownames(Data1)<-paste("Species",1:3)*
*rownames(Data2)<-paste("Species",1:3)*
*User_Defined=function(dat1,dat2
Try the following code.
It is basic but effective;
*setwd("/home/user2/Documents")*
*Test_matrix=read.csv("Trial.csv",header=T) # The 1st table that you have
considered
*
*Test_matrix=as.matrix(Test_matrix)*
*Writer=function(mat){u=unique(mat[,"Subject"])*
*l=length(u)*
*dummy=lapply(1:l,FUN
timing out, the odd part
> is that I can access to the link through a browser with no issues at all!!
> Any ideas why it keeps timing out? Also how can I keep the loop running
> after this error?
>
> Thanks again for your help!
>
>
> On Wed, Sep 19, 2012 at 11:36 P
I do not know about the packages that you mentioned. I am trying to answer
your query based on the term "socio-linguistic analytics".
There are packages like "OpenNLP","OpenNLP.en","tm (Text Mining)" that
might be of your interest.
Best,
Heramb
On Fri, Sep 21, 2012 at 1:04 AM, Trevor Jenkins wro
This is what I think;
Hive internally distributes the data. If you have set up Hive on single
core it will fetch the query results from that core. If you have multi-core
system on which you have setup the Hive, it will search all the cores for
the query submitted and results would be compiled toge
Hi,
Another way of doing may be like this;
a <- c("d", "d", "j", "f", "e", "g", "f", "f", "i", "g")
b <- c("a", "g", "d", "f", "g", "a", "f", "a", "b", "g")
ta <- table(a)
tb <- table(b)
Function<-function(Tab1,Tab2){elements=sort(unique(c(names(ta),names(tb
OP=lapply(1:length(elements),FUN
Try this;
help(anova)
I have used this in R-2.14.1
It has worked fine for me. Hope it works for you as well.
Best,
Heramb
On Thu, Sep 20, 2012 at 1:40 AM, Rui Barradas wrote:
> Hello,
>
> I had a problem seeing the help pages with R 2.14.(0 or 1? I don't
> remember) on Windows 7.
> Then I re
Try this,
library(RCurl)
library(XML)
site<-"
http://www.wateroffice.ec.gc.ca/graph/graph_e.html?mode=text&stn=05ND012&prm1=3&syr=2012&smo=09&sday=15&eyr=2012&emo=09&eday=18
"
URL<-getURL(site)
Text=htmlParse(URL,asText=T)
This will give you all the web dat in an HTML-Text format.
You can use
Hi All,
I have used windows R.
We can also write like this:
A <- read.csv("C:/Users/Anthi/Desktop/R/A.csv",header=TRUE)
On Wed, Sep 19, 2012 at 8:09 PM, Marc Schwartz wrote:
>
> On Sep 19, 2012, at 9:26 AM, Rui Barradas wrote:
>
> >
> > Em 19-09-2012 15:01, Sarah Goslee escreveu:
> >> On W
A<- get("a")
This will work fine
Best,
Heramb
On Mon, Sep 17, 2012 at 5:43 PM, Sri krishna Devarayalu Balanagu <
balanagudevaray...@gvkbio.com> wrote:
> a=c(1,2,3)
> b=c(23, 24, 25)
> x=c("a", "b")
> #if (length(x[1]) == 0) {cat("x[1] is having 3 elements")}
>
> Suppose I want to send the vect
If you have a data frame "df" with a column "JT"
Try this one:
str <- "df$JT == 12"
fun<-function(str){b<-eval(parse(text=str))
return(b)}
fun(str)
On Mon, Sep 17, 2012 at 11:57 AM, Christof Kluß wrote:
> Hi
>
> I would like to have something like
>
> str <- "df$JT == 12"
>
> fun <- function(d
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