11:11 AM Uwe Ligges <
> lig...@statistik.tu-dortmund.de> wrote:
>
>> For a data.frame d, I'd simply do
>>
>> d$cycle <- factor(d$dates, labels=1:3)
>>
>> but I have not idea about tibbles.
>>
>>
>> Best,
>> Uwe Ligges
>>
)
>
> # base R
> as.integer(factor(df1$dates))
> match(df1$dates, unique(sort(df1$dates)))
>
> # dplyr
> df1 %>% group_by(dates) %>% mutate(cycle = cur_group_id())
>
>
> My favorite is by far the 1st but that's a matter of opinion.
>
>
> Hope this
ay my
> respects to their Elders.
>
>
>
>
>
> On 22 Jul 2021, 1:47 PM +1000, N. F. Parsons ,
> wrote:
> > External email: Please exercise caution
> >
> > I am not averse to a factor-based solution, but I would still have to
> > manually enter that
levels is that
> you might have an awful lot of factors if you have a large enough
> dataset.
>
>
>
> Quoting "N. F. Parsons" :
>
> > Hi all,
> >
> > If I have a tibble as follows:
> >
> > tibble(dates = c(rep("2021-07-04", 2),
Hi all,
If I have a tibble as follows:
tibble(dates = c(rep("2021-07-04", 2), rep("2021-07-25", 3),
rep("2021-07-18", 4)))
how in the world do I add a column that evaluates each of those dates and
assigns it a categorical value such that
datescycle
2021-07-04
Thanks. What editor do you use? I'm working in a Mac, if that makes a
difference.
From: Gerrit Draisma
Date: Tuesday, February 9, 2021 at 5:10 PM
To: Parkhurst, David F.
Cc: r-help@r-project.org
Subject: Re: [R] Need help using lattice
Ha David,
I do not know.
It must be that your Apr
labels=AprToDec, ordered=TRUE))
I get + signs in front of monames and labels, again as expected, but then it
gives me another + sign. And if I try to add another ), it keeps giving me +
signs. What is happening here?
From: Gerrit Draisma
Date: Tuesday, February 9, 2021 at 6:14 AM
To: Park
Thank you.
From: Gerrit Draisma
Date: Tuesday, February 9, 2021 at 6:14 AM
To: Parkhurst, David F.
Cc: r-help@r-project.org
Subject: Re: [R] Need help using lattice
Ha David,
Thanks for your reply.
For your last question, you have to change month into an ordered factor
variable:
library
I have a dataframe comprising a vector of E. coli concentrations, a vector of
months when the samples were taken, and a vector of sampled sites. I�d like to
produce a lattice with sites along the horizontal axis, and months on the
vertical. Each site-month box would then contain concentrations
Oh, that's a nice option, too. Thanks!
-Original Message-
From: Richard M. Heiberger
Sent: Tuesday, September 17, 2019 6:54 PM
To: Sabatier, Jennifer F. (CDC/DDPHSIS/CGH/DGHP)
Cc: r-help@r-project.org
Subject: Re: [R] bi-directional bar chart with a central axis
I would us
Thanks, Jim (author of plotrix!), that's a real easy way to do it!
I'll play around with options.
Jen
-Original Message-
From: Jim Lemon
Sent: Tuesday, September 17, 2019 6:43 PM
To: Sabatier, Jennifer F. (CDC/DDPHSIS/CGH/DGHP) ; r-help mailing
list
Subject: Re: [R] bi-d
e plotrix link.
Jen
-Original Message-
From: David Winsemius
Sent: Tuesday, September 17, 2019 6:32 PM
To: Sabatier, Jennifer F. (CDC/DDPHSIS/CGH/DGHP) ;
r-help@r-project.org
Subject: Re: [R] bi-directional bar chart with a central axis
On 9/17/19 3:14 PM, Sabatier, Jennifer F. (CDC/DDPHSIS/
','B','C','D','E','F','G', 'H',
'I','J','K','L','M'),
c("Males", "Females"))
))
I want to make a graph tha
Hello Kind and Generous Volunteers,
I'm trying to use a scatter plot to visualize three variables: time, radius,
and intensity. I would like each point on the scatterplot to be colored
according to a gradient, in which red indicates an intensity less than 1, white
indicates an intensity of 1, a
Dear R group.
Does anyone have an idea how to utilize a latent variable in an ROC (AUC)
analysis? I want to create a latent variable, then use that latent construct as
a continuous variable in an ROC.
I understand both SEM and ROC analysis can be done in R, but how to use the
latent variable in
Dear R users,
I am pleased to announce that the package mfe (Meta-Feature Extractor) is
now
available on CRAN (https://cran.r-project.org/package=mfe).
The mfe package extracts meta-features from datasets to support the design
of
recommendation systems based on Meta-Learning. The meta-features, a
Hi David:
Thanks for your response and suggestions.
--Dennis
On 8/11/17 2:03 PM, David Winsemius wrote:
On Aug 11, 2017, at 7:56 AM, Dennis F. Kahlbaum wrote:
Hi Robert:
Thanks for your response, as well.
I'm sorry. As you've discovered, I made some capitalization errors when po
nce I don't have
SAS v6.12 anymore, I can't provide the so-called "correct results".
As for the R hang, your wording is correct: "R gets caught in a
processing loop that produces no errors or warnings", even after 15
minutes on an 8-core Mac Pro. As I recall, the SAS
Fisher
> The plural of anecdote is not data. ~ Roger Brinner
> The combination of some data and an aching desire for an answer does
> not ensure that a reasonable answer can be extracted from a given body
> of data. ~ John Tukey
>
> 2017-08-10 15:34 GMT+02:00 Dennis F. Kahlbaum &
I am trying to reproduce some old SAS PROC MIXED code using R and nlme.
The data consists of emission readings from vehicles and fuel
properties. All variables are real numbers except "study" and "vehicle",
which are character. Unfortunately, since the data are confidential, I'm
unable to provi
Hello, I'm Davide.
I'm using the package RANKS, in particular the functions do.GBA, do.RW,
do.RANKS. To the funcs are given 2 different Matrix. One is a a simmetryc
adjacency Matrix(called "M"), where rows and columns are protein, and the
other is an annotation Matrix(called "ann"), where protein a
Dear R users,
I am pleased to announce that the package mfe (Meta-Feature Extractor) is
now
available on CRAN (https://cran.r-project.org/package=mfe).
The mfe package extracts meta-features from datasets to support the design
of
recommendation systems based on Meta-Learning. The meta-features, a
Dear R users,
I am pleased to announce that the package mfe (Meta-Feature Extractor) is
now
available on CRAN (https://cran.r-project.org/package=mfe).
The mfe package extracts meta-features from datasets to support the design
of
recommendation systems based on Meta-Learning. The meta-features, a
Dear Achim,
Sorry to have disturbed you. I have encountered a problem when computing
Hausman test statistics (i.e. p values) in R to compare OLS and 2SLS models.
The problem is a discrepancy between the two p-value outputs from the "manual
approach (by hand)" and the " diagnostics argument" i
A better solution provide by Adriano Rivolli:
library(parallel)
models <- mclapply(1:10, function(i) {
model <- RWeka::J48(Species ~., iris[sample(nrow(iris))[1:100],])
rJava::.jcache(model$classifier)
model
});
2013-10-24 10:16 GMT-02:00 Luís Paulo F. Garcia :
> Dear
to the first
treatment in the order, which is "high dose". It is possible to rearrange the
order so that "placebo' is first, but this is inconvenient.
Thanks,
James F. Henson
[[alternative HTML version deleted]]
__
R-hel
I am a student from Sweden.
I would like to download and install R program to work on statistics.
If I want to download 2014 version, how I can do this.
Also, do I need to choose Sweden in Cran Mirrors list?
Regards,
Fatemeh
[[alternative HTML version deleted]]
_
Hi,
I think you want the {mitools} package.
http://cran.r-project.org/web/packages/mitools/mitools.pdf. Anthony
Damico's site, asdfree.com, has a lot of good code examples using various
government datasets.
Nate
On Mon, Jan 26, 2015 at 5:23 AM, hnlki wrote:
> Dear,
>
> My dataset consists out o
Dear all,
I've got a bit of a challenge on my hands. I've got survey data produced by
a government agency for which I want to use the person-weights in my
analyses. This is best accomplished by specifying weights in {survey} and
then calculating descriptive statistics/models through functions in th
I verify my output with the csv file but I get an error in my submission. I
am not sure I have the requirements understood.
ex: rankall("Heart attack",4) gives me the following for AZ (this is a
section of my output)
FLAGSTAFF MEDICAL CENTERAZ
SUMMIT HEALTHCARE REGIONAL MEDICAL CENTER
I got an incorrect for my Ass.3 part 2 submission. What does this part 2
test. I want to correct the problem but do not know what the problem was.
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mai
Hi
I submited the rankhospital project. All parts were correct except part 2.
I checked the outcome and it looks correct. I am afraid I am
misunderstanding the requirement. Please let me know why the outcome is not
correct.
*THE OUTCOMEMy test*
> source("rankhospital.R")
> d<-rankhospital("WA","
rectory,summerize=FALSE) {
xid<-toString(id)
xid<-paste("000",xid,sep="")
xid<-substr(xid, nchar(xid)-2,nchar(xid))
f<-sub(" ","",paste(xid,".csv",sep=""))
f<-sub(" ","",paste(directory, &q
11"
> intToBin(65535)
[1] ""
> intToBin(65536)
[1] "1"
Earl F Glynn
Principal Programmer/Analyst
Center for Health Insights • University of Missouri – Kansas City
__
R-help@r-project.o
r data and use sub/gsub or other tools to remove or alter
problem characters.
efg
Earl F Glynn
UMKC School of Medicine
Center for Health Insights
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PLEASE do read the posting
e, Oct 22, 2013 at 7:11 AM, Patrick Connolly <
p_conno...@slingshot.co.nz> wrote:
> On Thu, 17-Oct-2013 at 02:21PM -0300, Luís Paulo F. Garcia wrote:
>
> |> I work very mutch with the packages RWeka and multicore. If you try to
> run
> |> J48 or any tree o
I work very mutch with the packages RWeka and multicore. If you try to run
J48 or any tree of RWeka with multicore we hava some errors.
Example I:
library(RWeka);
library(multicore);
mclapply(1:100, function(i) {
J48(Species ~., iris);
});
Output: "Error in .jcall(o, \"Ljava/lang/Class;\"
Dear all,
I've found the html versions of
'An Introduction to R' [http://cran.r-project.org/doc/manuals/R-exts.html]
'Writing R Extensions' [http://cran.r-project.org/doc/manuals/R-intro.html
]
to be empty. Not sure if this intentional, some transitional state of sort
or if it is a genuine bug i
Dear all,
How do I obtain the number of countries that my panel models estimated by
pglm() and relogit() (the latter one is in the Zelig library) use? I
couldn't find any information on that in the help files.
Thank you very much in advance.
Best wishes
_
tober 11, 2012 10:33 AM
To: ROLL Josh F
Cc: R help
Subject: Re: [R] Sorting a data frame by specifying a vector
Hi,
In your dataset, it seems like it is already ordered in the way you wanted to.
df.. <- data.frame(Season=rep(c("Summer","Fall","Winter","Spring&
Dear All,
I would like to use the package "vars" to get a impulse response function of
a Structural VAR model.
However, I got a wrong message and cannot deal with it.
Here is my code:
>library(vars)
>
>data <- read.table("data.txt", header=T)
>y1<- data[,c("log_x1","log_x2","log_x3","log_x4"
This solution was the most elegant. Thanks everyone.
Josh
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Thursday, July 26, 2012 9:55 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] add leading zeros
Much easier than you think
;>
>>> Thank you so much!
>>>
>>> Tiago
>>>
>>> # code
>>>
>>> ## matrix to plot
>>> matI <- matrix(c(rep(1:3, 100), rep(4:6, 100), rep(7:9, 100)), nrow=3,
>>> byrow=T)
>>>
>>> ##
, 2012 1:14 PM
To: ROLL Josh F
Cc: R help
Subject: Re: [R] Using object as literal value in list vector
Hi,
You can try:
NewMeans<-split(matrix(unlist(MeanValues_)*0.80),1:nrow(matrix(unlist(MeanValues_)*0.80)))
names(NewMeans)<-names(MeanValues_)
NewMeans
$ACC
[1] 800
$RTL
[1] 1600
$
PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] Probably a good use for apply
Hi,
On Thu, May 31, 2012 at 1:08 PM, LCOG1 wrote:
> This is great thank you. I think I am getting the hang of some of the
> apply functions. I am stuck again however. I have list test_ below
&g
#sample words
words <- c("fixing","Dog","Carting","kite","running","playing")
#find words ending in 'ing'
result <- regexpr("^[a-zA-Z]+ing$",words)
result
[1] 1 -1 1 -1 1 1
attr(,"match.length")
[1] 6 -1 7 -1 7 7
attr(,"useBytes")
[1] TRUE
# you can use result to take out the offending wo
.
Thank you for your help,
Kate
"I am interested to calculate confidence interval for fitted values in general
for non-linear regressions. Lets say we have y=f(x1,x2,..xN) where f() is a
non-linear regression. I would like to calculate a confidence interval for new
prediction f(a1,..,aN).
ith-lowess
Which I cannot decipher it. Do you have any suggestion?
On 3/9/12 1:42 AM, "Pascal Oettli" wrote:
Hi Robert,
You can try ?lowess
Regards,
Pascal
- Mail original -
De : "Faryabi, Robert (NIH/NCI) [F]"
À : "r-help@r-project.org"
Cc :
Envoyé l
Hello All,
I just have a very simple question. I recently switching from Matlab to R, so
cannot figure out some of the easy tasks in the new environment.
Is there any weighted local regression smoothing in R? Basically, I want to
have weighted moving average. All the functions that I know of ne
Hi there,
Here is the scenario:
I have a measurement of some sort for two variables, I would like to figure out
a rough pattern between them. Let say if the values of the first variable are
low, middle, high, and extremely high, then what would be the corresponding
pattern of the second variab
Oh cool! I didn't realize you could assign a different value to a substring
like that.
Thanks!
Joy
From: Petr Savicky [savi...@cs.cas.cz]
Sent: Wednesday, February 08, 2012 3:26 PM
To: r-help@r-project.org
Subject: Re: [R] String position character replace
M
To: Yang, Joy (NIH/NHGRI) [F]
Cc: r-help@R-project.org
Subject: Re: [R] String position character replacement
And here's an alternative solution:
subchar <- function(string, pos, char="-") {
for(i in pos) {
string <- gsub(paste("^(.{&q
Hi,
Is there a way to efficiently replace specified indices in a string with
another character? For example, if I had a vector of strings such as
[1] "hellohowareyoudoing"
[2] "imgoodhowareyou"
[3] "goodandyou"
[4] "yesimgoodijusttoldyou"
[5] "ohyesthatsright"
and had a list of positions that I
Ah. That's the one. Thank you.
-Original Message-
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Monday, February 06, 2012 11:12 AM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] I bet apply has a solution
Hi Josh,
How about
apply(Data, 1, function(row) sd(row)
Thanks Ben,
I am tryin on simulated data, say 300 repondents, 8 choice per person, only
2 random parameters... so i think it should be well behaved... so I am
probably doing a mistake! :-)
Thank for poiting out the MCMCglmm package, ultimately I need to write my
own non-linear untility function,
Dunlap [mailto:wdun...@tibco.com]
Sent: Tuesday, December 06, 2011 11:42 AM
To: gleyne...@gmail.com; ROLL Josh F
Cc: r-help@r-project.org
Subject: RE: [R] To Try or to TryCatch, I have tried to long
Or, Google for 'R catching warnings' and third entry is the excellent
http://www.st
age of Dep Var.
276,0067
St Error Dep. Var
117,5827
Squared Sum of remainders
818,6362
Regression standar error
9,047852
R^2
0,995771
R^2 adj
0,994079
F(4, 10)
588,6040
p-value (de F)
8,09e-12
Log-likelihood
-51,28100
Akaike
112,5620
Schwarz
116,1023
Dear Mailing list,
I am trying to produce a simple xy plot but overlapping at the y-axis
the y-values of each point.
The problem is that I don't know the x-coordinate corresponding to the
y-axis to plot the y-points. For each plot I have manually
"calculated" the x-coordinate but was wondering wh
check this out
http://www.r-bloggers.com/pivot-tables-in-r/
--
View this message in context:
http://r.789695.n4.nabble.com/Aggregating-data-help-tp3923138p3923397.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mai
I've installed Rcmdr package and it doesn't run
Here is the error message:
R version 2.9.2 (2009-08-24)
[R.app GUI 1.29 (5464) powerpc-apple-darwin8.11.1]
[Workspace restored from /Users/jfc/Documents/TravauxFR/.RData]
Le chargement a nécessité le package : tcltk
Chargement de Tcl/Tk... termin
Dang Jim this looks to do the trick though I never heard of a data.table,
interesting, I will explore more. Thanks you very much.
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, September 01, 2011 11:20 AM
To: ROLL Josh F
Cc: r-help@r-project.org
Hello,
Is there a syntax to set the environment of a function when this function is
defined?
The best I could come up with so far is using a wrapper function:
foo_internals<- function(x) {"Code of the function"}
foo<- function(x) {
environment(foo_internals)<-as.environment(target_environme
Hello Denis,
> To borrow shamelessly from one of the prominent helpers on this list:
> "What is the problem you're trying to solve?" Â Â (attribution: Jim Holtman)
I'm trying to connect two sets of legacy R tools: the output of the
first one can be transformed in a data.frame without loss of
inf
Hello Duncan,
Here is a small example to illustrate what I am trying to do.
# Example data.frame
df=data.frame(A=c("a","a","b","b"), B=c("X","X","Y","Z"), C=c(1,2,3,4))
# A B C
# 1 a X 1
# 2 a X 2
# 3 b Y 3
# 4 b Z 4
### First way of getting the list structure (ls1) using imbricated lapply
Hello,
This is my first project in R, so I'm trying to work 'the R way', but it
still feels awkward sometimes.
The problem that I'm facing right now is that I need to convert a data.frame
into a structure of lists. The data.frame has columns in the order of tens
(I need to focus on only three of
I will take a look. In my real data I need to interpolate the 16 points into
64 points for each of the categories.
Thanks Marc
JR
-Original Message-
From: Marc Schwartz [mailto:marc_schwa...@me.com]
Sent: Tuesday, May 17, 2011 1:09 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Marc,
How could I also apply the spline function to each of the 'columns' found in
the result from
tapply(Df$Rate,list(Df$Bin,Df$Type),sum)
??
-Original Message-
From: Marc Schwartz [mailto:marc_schwa...@me.com]
Sent: Tuesday, May 17, 2011 12:42 PM
To: ROLL Josh F
1 if dealing with floating point numbers.
>
>--Erik
>
>
>Beale, Holly (NIH/NHGRI) [F] wrote:
>> Is there a less cryptic way to compare three or more values?
>>
>> allTheSame<-c("red","red","red","red")
>> notAllTheSam
Is there a less cryptic way to compare three or more values?
allTheSame<-c("red","red","red","red")
notAllTheSame<-c(132,132,132,999)
all.identical <- function(vectorToTest){
cIdentical=sum(vectorToTest %in% vectorToTest[1])
return(cIdentical==length(vectorToTest))
}
all.identical(al
n a 64 bit machine. I cant seem to locate a 64 bit counterpart.
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Tuesday, March 22, 2011 1:01 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] Loading mdb
I believe that you are misinterpreting
only tool to read in mdb's from MS Access? I feel
like it should be easier than this? Thoughts?
Thanks Phil
JR
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Tuesday, March 22, 2011 1:01 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: R
Motivation: during each iteration, my code needs to collect tabular data (and
use it only during that iteration), but the rows of data may vary. I thought I
would speed it up by preinitializing the matrix that collects the data with
zeros to what I know to be the maximum number of rows. I was su
try the code below,
if you use different upper and lower limits you might get different parameter
estimates
HTH, Victor
standard.curve<-data.frame(conc=c(50, 25, 12.5, 6.25, 3.125, 1.563, 0.781,50,
25, 12.5, 6.25, 3.125, 1.563, 0.781),absorb=c(1.918, 1.251, 1.104, 0.719,
0.403, 0.177, 0.083,1.9
4 is legal with your Fortran compiler:
http://gcc.gnu.org/onlinedocs/gfortran/Old_002dstyle-kind-specifications.html#Old_002dstyle-kind-specifications
efg
Earl F Glynn
Overland Park, KS
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int to change a data.frame.
> I want to split a column in more columns depending on the value of a other
> column.
> Thanks for the reaction,
> Andre
>
> Example:
>> dat
> x1 x2
> 1 1 a
> 2 1 b
> 3 1 c
> 4 2 d
> 5
I am trying to read some file names from an specific directory and such names
contains metacharacters.
The file names is like V4.35_T01-400720.csv
In total I have 14 files for which the value T01 goes up to T14. I need to read
the files into a string vector that looks like
>names"V4.35_T01-4007
although the code somehow didn't work on my Vista / R 2.8,
it did work perfectly on a XP machine / R 2.10
I've been trying to fix this for days,
Thank you very much for your help!
__
02/01/2011 19:30, David Winsemius < dwinsem
I guess you should specify x and y variables:
plot(x=PCECTPI$var1, y=PCECTPI$var2, axes = FALSE)
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PLEASE do read the posting guide http://www.R-project.org/posting-gui
Please, I wonder if someone knows how to add the
less than or equal to symbol in the plot generated by the code below:
var1<-c('age <= 3','age <= 7','age <= 10','age <= 11','age <= 20','age <=
25','age <= 30','age <= 45','age <= 50','age < 55','age >= 55')
var2<-c(3.8,5.4,3.7,3.8,5.
_
Em 01/01/2011 20:05, Victor F Seabra < vsea...@uol.com.br > escreveu:
Dear all,
Please, when I use the command:
table1<-read.table("table1.txt", header=TRUE, sep="\t")
cells that contain \ u 2264 (corresponding to <= si
please, when i use the command postscript, the symbol "<="(less than or
equal to) is replaced by "..." (ellipsis)
how can I fix that?
postscript("plot1.ps", width = 22, height =
11.5,pointsize=24,paper="special",bg="transparent")
plot(NULL,xlim=c(1,10),ylim=c(1,10))
text(5,5,"
Dear all,
Please, when I use the command:
table1<-read.table("table1.txt", header=TRUE, sep="\t")
cells that contain \ u 2264 (corresponding to <= sign) get imported as \ \
u2264.
which causes the need to manually edit each cell using the fix command.
Is there a way to fix tha
Please, you need to read.table to R as my problems start there
If you want you can download the txt file at the link below
https://docs.google.com/leaf?id=0BweZgDxYn9BkNmY1NThmMDEtOWUxZS00MzE0LTk0NTQ
tYzdlODMxODgxYzJh&hl=en
thanks, Victor
lish what end? You have not described what you are trying to
actually do. Is this text supposed to be plotted inside the plotting
area or are you going to be using it as axis labels? There is a
variety of approaches (especially the plotmath expression option) that
can be used depending on the ultim
Dear all,
Please, I have a doubt regarding symbols plotting
when the data originates from a table
(i.e. is not manually fed into the "text" function)
Please, see below:
I have a tab delimited file called table1.txt with 4 columns.
(I wasn't sure on how to attach the table to t
"bill >= tony" "bill \u2265 tony"
"9" "fish" "dude <= bro" "dude \u2264 bro"
By the way, I'm running R on windows and didn't try any of this on Linux.
thanks in advance, Victor
Â
Â
Victor Faria Sea
Dear all,
Please, I have a doubt regarding symbol plotting
with data originating from a table.
Please, see below:
I have a tab delimited file called table1.txt with 4 columns:
yposanimal var1var2
5 cat gina <= lady gina \u2264 lady
7 dog bill >= tonybill \u
I have a vector which is an interval on which I'm trying to calculate the
values of the following function for a probability distribution:
http://r.789695.n4.nabble.com/file/n3163464/Equation.jpg
I want to generate a k-size sample of values following the distribution
above.
For some reason, I'
http://www.efg2.com/Lab/Graphics/Colors/HSV.htm.
For info on R's hsv function: ?hsv
This page shows the "hue" map of an RGB image:
http://www.efg2.com/Lab/Graphics/Colors/ShowImage.htm
See the Color Chart page above for a brief example of using R's rgb2hsv
functi
What about this?
Remove the periods and change the "," to a ".":
s <- "12.084.547,17"
x <- as.numeric(gsub(',','\\.', gsub('\\.','',s)))
options(digits=10)
x
Escaping periods is not-so-obvious.
efg
Earl F Glynn
O
: Monday, November 29, 2010 12:58 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] List elements of NULL to value
Does
A = lapply(A,function(x)if is.null(x) 0 else x) or
for(i in 1:length(A))if(is.null(A[[i]]))A[i] = 0
do what you want
Let's assume that according to Anova(lm(y~a*b, data=d)) the a:b interaction is
significant, and I would like to know if there are specific combinations of a
and b levels that differ from the control group. Are there any caveats against
simply looking at the p-values in the output generated by
s
s there some memory-related parameter that I should adjust that might
explain the observed details above?
Shouldn't read.delim catch this failure instead of being silent about
dropping data?
Thanks for any help with this.
Earl F Glynn
Overland Park, KS
___
Sure I tried that and it works but I was formerly using just 'proportion ' so I
find it strange that this has occurred.
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Monday, September 13, 2010 4:08 PM
To: ROLL Josh F
Cc: r-help@r-project.org
S
Hello everyone,
This is just a quick double check. It concerns the 'scatterplot function' in
R.
I have 6 curves and I wish to represent each of them by a different kind of
line (their colour must be black).
The curves are derived from the cuminc function...the coordinates of which are
in '
Hi R-help,
I posted about this late yesterday but got no response. I may have put
TMI in the original request. Not to mention I couldn't cut and paste
yesterday because I was working R off a non-network computer while
asking for help on a network computer.
Essentially, I have this user-define
chisq <- svychisq(~svyX + SEX, design=audit, statistic="adjWald",
round=4)
chisq <- data.frame(do.call("cbind", chisq)
chisq <- data.frame(chisq[,3])
Table <- data.frame(tbl$var,
paste(formatC(tbl$X0.1*100, format="f", digits=1),
"%",
into NAs I can use NAToUnkown() to blank them out completely.
Thanks, again, for getting back to me!
Jen
-Original Message-
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Wednesday, May 19, 2010 1:59 PM
To: r-help@r-project.org
Cc: Sabatier, Jennifer F. (CDC/OID/NCHHSTP)
Subje
SWEET!
That's EXACTLY what I need. Thanks!
I can now just use NAToUnknown to turn the NA into blanks.
Thanks a lot!
Jen
-Original Message-
From: Stefan Grosse [mailto:singularit...@gmx.net]
Sent: Wednesday, May 19, 2010 1:53 PM
To: r-help@r-project.org; Sabatier, Jennifer F.
Hi R-Help,
I am a new R user. I have used SAS for many years (just FYI on what I
am used to and possible obstacles it presents).
I have a data frame:
mydf <-data.frame(matrix(rnorm(102), ncol=6)
I would like to be able to delete ALL the information in column 6 for
rows 2 through r, where r=#ro
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