This solution was the most elegant. Thanks everyone. Josh
-----Original Message----- From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com] Sent: Thursday, July 26, 2012 9:55 PM To: ROLL Josh F Cc: r-help@r-project.org Subject: Re: [R] add leading zeros Much easier than you think: x <- c(1L, 9000L) sprintf("%05i",x) Best, Michael On Thu, Jul 26, 2012 at 8:08 PM, LCOG1 <jr...@lcog.org> wrote: > Hi all, > Trying to use an apply to add leading zeros to a set of values in > a given vector. I only want to add enough zeros so that the total > number of characters is 5, so if I have an element "1" i want "00001" > or "9000" I want "09000". I tried > > vec <- 1:1000 > sapply(vec, FUN = sprintf(paste("%0",(5-nchar(x)),"d",sep=""),x)) > > but she doesnt work. I struggle with the apply family for sure. > Thanks > > Josh > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/add-leading-zeros-tp4638031.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
