[R] 'which' statement for recode?

Hi, Is there a way to easily convert the list of course terms into sequential integers in the dataframe (see code below)? eg. "199801" = 1; "199808"=2 I know I can use recode but shouldn't "which" work? Thanks in advance! sc = data.frame(c("200208", "200701", "201201")) names(sc) = c("TERM")

[R] which LETTERS?

I'm confused: Thanks in advance. > which(LETTERS == c("A")) [1] 1 > which(LETTERS == c("A","B")) [1] 1 2 > which(LETTERS == c("A","B","C")) [1] 1 2 3 Warning message: In LETTERS == c("A", "B", "

[R] Can't understand syntax

. >> >> __** >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help> >> PLEASE do read the posting guide http://www.R-project.org/** >> posti

Re: [R] which() in subset()

risons. With the >vector with length equal to the number of observations on the left hand >side. > >Hope this helps, > >Rui Barradas > >Em 13-07-2012 12:12, Charles Stangor escreveu: >> Why does the subset not work in the which() version below? >> >>

[R] which() in subset()

Why does the subset not work in the which() version below? Thank you v1 <- subset(t1, version_1==as.character("100-1") | version_1==as.character("100-2")) a<-c("100-1", "100-2") v1 <- subset(t1, which(a==as.character(version_1)) != 0) [[alternative HTML version deleted]] ___

Re: [R] Substitute list value

thanks! On Fri, Jul 13, 2012 at 4:35 AM, Jessica Streicher wrote: > two things: > > - R always counts from 1, not from 0 > - listmembers are accessed by using [[ ]] , not [ ] > > try > > t1[t==ll[[1]], "v"] <- 99 > > greetings Jessi > > > On

[R] Analyzing subsets

Say I want to perform transformations on row subsets of my dataframe. Do I have to break the dataframe into subsets, perform the analysis on each subset, and rbind() them together again? ..or is there another way. Thank you! [[alternative HTML version deleted]]

[R] sapply question

Why does this sapply code change df3 but not df1? Thanks df1 <- read.table(text=" cola colb colc cold cole 1NA59 NA 17 2NA6 NA 14 NA 3 3NA 11 15 19 4 48 12 NA 20 ", header=TRUE) df2 <-df1*2 df1 df2 df3 <-sapply(names(df1),function(x) {df

Re: [R] Help with loop

le.com/Help-with-loop-tp4636140.html > Sent from the R help mailing list archive at Nabble.com. > > __________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www

[R] Substitute list value

I can't seem to determine how to get the name of a list member to substitute as a variable name: ll <- list("a1" = "a","a2" = "b") t1[t==ll[1], "v"] <- 99 why doesn't this substitute to: t1[t=="a", "v"

[R] Substitute list value

I can't seem to determine how to get the name of a list member to substitute: ll <- list("a1" = "a","a2" = "b") t1[t==ll[0], "v"] <- 99 why doesn't this substitute to: t1[t=="a", "v"] <- 99 Thank you! [[alternative HTML version deleted]] __

[R] Substitute list value

I can't seem to determine how to get the name of a list member to substitute: ll <- list("a1" = "a","a2" = "b") t1[t==ll[0], "v"] <- 99 why doesn't this substitute to: t1[t=="a", "v"] <- 99