Thanks Dennis and Mike... I'm getting it!!! Sent from my Android
Rui Barradas <ruipbarra...@sapo.pt> wrote: >Hello, > >To know why, just evaluate the condition, with 't1$' before 'version_1': > >which(as.character(t1$version_1) %in% a) != 0 >[1] TRUE TRUE > > >It allways evaluates to TRUE, therefore, subset() returns all rows. > >See if this isn't simpler than both of your forms. > >v2 <- subset(t1, version_1 %in% a) >v2 > id version_1 >1 1 100-1 >2 2 100-2 > >The trick is to use %in% when doing multiple comparisons. With the >vector with length equal to the number of observations on the left hand >side. > >Hope this helps, > >Rui Barradas > >Em 13-07-2012 12:12, Charles Stangor escreveu: >> Why does the subset not work in the which() version below? >> >> Thank you >> >> >> v1 <- subset(t1, >> version_1==as.character("100-1") >> | version_1==as.character("100-2")) >> >> a<-c("100-1", "100-2") >> v1 <- subset(t1, which(a==as.character(version_1)) != 0) >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.