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Anne 耀日
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and
2` = c(5, 5, 6, 4, 5, 3), `3_T3_start` =
c(4.76,
5.1, 3.87, 3.61, 2.83, 3.7), `3_T3` = c(7, 3, 4, 2, 5, 3),
`4_T4_start` = c(6.09, 6.99, 5.21, 5.19, 5.02, 6.34), `4_T4` = c(4,
5, 5, 4, 3, 6)), row.names = c(NA, -6L), class = c("tbl_df",
"tbl", "data.frame"
understand what
I'm doing wrong.
```{r}
behavioral_df <- behavioral_df %>% rename_with(.fn = ~paste0("v"),
starts_with('^\\d'))
```
I appreciate if you can help.
Best,
Anne
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Can anyone please tell me how to change the language interface so as to receive
error messages in English. Currently it's a mixed jargon of French an English.
Thank you for any help.
Anne
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Dear Michael,
Thanks a lot for your suggestion. This is what I am trying to do with R
(longpower and gee packages). But I am getting stuck with a confusing error
message sent earlier I don't understand.
Best,
Anne
-Message d'origine-
De : Michael Dewey [mailto:li...@dewey.m
subject.
Yours sincerely,
Anne
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and provide commented, minimal,
hypothesis that the extra
parameters are all zero. But I might be wrong...
-Message d'origine-
De : CHATTON Anne
Envoyé : vendredi, 5 octobre 2018 10:46
À : 'r-help@r-project.org'
Objet : Strange paradox
Hello,
I am currently analysed two nested models using the same sample
), suggesting that the
confounders (x3 and x4) account for the prediction of the dependent variable.
Does anyone have an explanation of this strange paradox?
Thank you for any suggestion.
Anne
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nts
of the multiply-imputed regressions using this command :
sdBeta <- lm.beta(FitImp)
I get the following error message:
Error in b * sx : argument non numérique pour un opérateur binaire
Can anyone help me with this please?
Anne
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Hi R folks,
In my previous post I forgot to mention that I was new to R. I was really
grateful for your quick help. I have two further questions:
1) In the graph of a regression line I would like to show one specific residual
yi obs - yi pred (let's take the person whose residual is 76). How do I
Hi Gerrit!
Thank you so much! I mistakenly reversed the order of the variables of the
regression. Actually what I meant to write was: lm(BloodPressure ~ Age).
Best,
Anne
-Message d'origine-
De : Gerrit Eichner [mailto:gerrit.eich...@math.uni-giessen.de]
Envoyé : mercredi 18 avril
main = eq, xlab = "Age (Year)", ylab = "Blood Pressure (mmHg)")
abline(SimpleLinearReg1, col="red")
mean(Age)
mean(BloodPressure)
abline(h=142.53, col="green")
abline(v=45.13, col="green")
But I cannot get the regression line. Can anybody tell me w
18 150.543 385.172 3.91e+02
Chisq= 430 on 3 degrees of freedom, p= 0
Thank you in advance.
Anne.
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Thanks so SO much.
Brennan
www.toxstrategies.com
From: Anthony Damico
Date: Wednesday, May 11, 2016 at 11:17 AM
To: Anne Bichteler
Cc: "r-help@r-project.org"
Subject: Re: [R] Quantiles on multiply imputed survey data - mitools
hi, you want se=T
M_quantile <-
n(make.formula(get('var_name'
summary(M_mean)
M_quantile <- with(des_mult, svyquantile(make.formula(get('var_name')),
quantiles = c(.5)))
summary(M_quantile)
Thanks again,
Brennan
www.toxstrategies.com
From: Anthony Damico
Date: Tuesday, May 10, 2016 at 10:37
Hello, and thank you for considering this question:
The svystat object created with multiply imputed NHANES data files is failing
on calling survey::svyquantile. I'm wondering if I'm diagnosing the issue
correctly, whether the behavior is expected, and whether y'all might have any
ideas for wor
following error:
Error in pars[idx["mxreg", 1]:idx["mxreg", 2], 1] = fit.mean[i] :
replacement has length zero
Do you know where it comes from and how I can fix it?
Thank you and have a nice day,
Anne-Marie
(pa=1), the pe's would be a1=84 --> pe=12; a2=113
--> pe=89, a3=96 --> pe=24, a4=76 --> pe=0
I hope, that is clearer than before :)
Thanks a lot,
Anne
Am 24.07.2013 14:47, schrieb John Kane:
> Welcome to R-help
> it is a bit hard to see exactly what you want without d
w
variable "Percentile.AG1".
Every person that scored 6 in "Punkte.AG1" gets a "6" in the new
variable "Percentile.AG1".
The same thing should be done for the other tasks.
I new to R, so I don't have any clue, how to solve that. It would b
I am trying to learn to tune a svm model in R.
I'm using the sonar data set used by David Mease in his Google Tech
Talk video. I downloaded the data from his site. There are 130
observations in the training set. I am able to run a svm model. But
when I try to run this command:
tune_svm <-tune.sv
Thank very much you for your help,
Anne-Marie Gallrein
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Technische Universität Dresden
Institut für Klinische, Diagnostische und Differentielle Psychologie
Diagnostik und Intervention
01062 Dresden
Tel. +49 351 463-34004
gallr...@psychologie.tu-dresden.de
X<-
Hi,
I've got a new dataset which I don't know how to analyze with R. My knowledge
about R is limited for this kind of problem. I've tried to find a solution with
some spatio temporel packages and lme/lmer functions, but didn't find any
similar example.
I've got 10 locations on a coast on which
Hello,
When I run the following glm model:
modelresult=glm(CID~WS+SS+DV+DS, data=kimu, family=binomial)
I get the following warning messages:
1: glm.fit: algorithm did not converge
2: glm.fit: fitted probabilities numerically 0 or 1 occurred
What I am trying to do is model my response variable
Hello,
I am new at using R.
I would like to use the following functions of the "clim.pact" package:
ncdfcont and retrieve.nc
I have installed the package "clim.pact" in Rstudio.
I have downloaded the "ncdf pack" from unicar (including ncdump and ncgen).
The ncdf file I'm working on is called "es
Apologies for the empty email earlier!
I have species abundance data sampled at a weekly frequency or
sometimes monthly depending on the year.
The goal is to identify the dates in an annual cycle in which the
cumulative abundance of a species reaches some threshold.
Here's an example of the data
Dear R-users
--
-- Heather Anne
---
Heather A. Wright, PhD candidate
Ecology and Evolution of Plankton
Stazione Zoologica Anton Dohrn
Villa Comunale
80121 - Napoli, Italy
website<http://www.szn.it/SZNWeb/cmd/ShowArchiveItem?TYPE_ID=HUMANRESOURCE&
appropriate to use
interaction_average=TRUE when non-significant interaction terms are
present in the model, or does it depend on your specific research
questions? Alternatively, should you just remove non-significant
interaction terms from the model?
Thank you,
Anne
Quoting "Rich
. Both TukeyHSD and glht give
essesntially identical confidence intervals for
the example in ?glht. What aren't you satisfied with?
amod <- aov(breaks ~ tension, data = warpbreaks)
confint(glht(amod, linfct = mcp(tension = "Tukey")))
TukeyHSD(amod)
On Mon, Jan 2, 2012 at 6:19 PM,
sts
generated from the glht code is providing me with appropriate p-values
for my post-hoc comparisons.
I feel like I have reached a dead end and am not sure where else to
look for information on this issue. I would be grateful for any
feedback on this matter.
Anne Cheverie
M.Sc.
Would like to know how much data can R process - number of rows and columns?
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Hello!
I have measurements (length and volume) of fish collected in two years. I
want to know if the the relationship between length and volume is the same
for both years. The number of fish measured is different for each year. I
don't know whether lm or aov is more appropriate to use.
Here are t
>Hi Petr,
>
>thank you, I got it. In fact I was looking for the function aggregate() which
>I didn't know.
>
>aggregate(x = t(data), by = list(cov$Month, cov$Area), FUN = "sum")
>
>that is doing exactly what I need.
>
>Anne
>-Ursprüngli
it work or what would be an easier solution?
Thank you for your help,
Anne
data=data.frame(matrix(1:99,nrow=5,ncol=36))
colnames(data)=c(paste("plot",1:36))
cov=data.frame(rep(1:3,12),c(rep("Jan",12),rep("Feb",12),rep("Mar",12)),rep(c(1,1,1,2,2,2,3,3,3,4,4,4)
be a problem, that my
model isn't balanced? In Class1 I happen to have 4 elements, while there are 90
in class2.
Thank you for your help,
Anne
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find them.
Thanks again,
Regards,
Anne
John Fox a écrit :
Dear Anne,
I started to diagram your model but stopped when I noticed some problems:
(1) Some variables, such as pays_alti, are clearly endogenous, since they
have arrows pointing to them, yet are declared as fixed exogenous varia
tx_chomage, auto33, NA
pourcagric <-> pourcagric , auto34, NA
pourc_jeunes<-> pourc_jeunes , auto36, NA
pop99<-> pop99 , auto36, NA
rev_imp_foyer <-> rev_imp_foyer , auto38, NA
eq_CONC <-> eq_CONC, auto39, NA
eq_sante <->eq_sante , auto40, NA
eq_edu<->
The plot also works if you replace "na.exclude" with
"na.omit".
On Wed, 7 Jul 2010, Deepayan Sarkar wrote:
DS > On Fri, Jul 2, 2010 at 11:40 AM, Gregory Gentlemen
DS > wrote:
DS > > Fellow R-users,
DS > >
DS > > I have a longitudinal data set with missing values in it. I would like
to produce
really glad if anybody can help me understanding the functionality
and show me how to convert between the different data types.
Thanks in advance,
Anne S.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Thanks, that helped!
--
Anne Skoeries
Am 05.02.2010 um 10:40 schrieb Patrick Burns:
summary(c(the.matrix))
should work for you. Or perhaps more telling:
summary(as.vector(the.matrix))
On 05/02/2010 09:33, Anne Skoeries wrote:
Hi,
is there a way to receive a total summary of a numerical
atrix. Anyone an idea how to do it?
Thanks in advance,
--
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ackage was just for building a set of functions for my use
or to contribute to cran. But, another use is to "package"
up an analysis with all the data, functions, etc, including
sweave scripts. Your work can then be repeated by someone
else who has installed R.
Anne
__
Check out the interaction.plot function.
On Fri, 8 Jan 2010, lse1986 wrote:
l >
l > Hi i want do a line graph.
l >
l > My y axis contains numeric values. My x axis contains non numeric
l > statements.
l >
l > This is what i want the graph to look like.
l >
l > When i try to plot this graph
!
Cheers,
Anne
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column=1, row=0, sticky="ns")
tkgrid(scrergHor, column=0, row=1, sticky="we")
tkinsert(txt, "0.0", paste(capture.output(resultKmean), collapse="\n"))
Trying the upper code would wrap the lines that are contain more than
100 characters. How can I ke
Hi. With your help, I've fixed the errors in my for loops.
But now, the for loop isn't working correctly. There should be a plot,
but there's no plot when I run the for loop..
This is the code:
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){
The following code isn't working and we can't figure out why..
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){ #6 letters
for (j in 1:3) { #3 numbers
for (k in -1:1) {
#x27;t count.
Keep vector= (V,I,PT,M,E), count =5
OK. There must be a more elegant way to do this! Something with
vector-wise pattern matching or so?... By the way, I dont care e.g.
which of "V" or "MV" is counted, what is important is that they are
only counted as 1.
Thank
Thanks! That's it! Perfect!
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Olgastr. 54
74072 Heilbronn
Phone: +49 (0)7131 - 390 33 33
Mobil: +49 (0)176 - 212 37 770
Mail: h...@anne-skoeries.de
Am 14.09.2009 um 15:50 schrieb Henrique Dallazuanna:
tkinsert(tex, "end", paste(capture.output(summary(fit)), c
ummary of an object is a list, I always get back the
following error-message:
cannot handle object of mode 'list'
So, is there a different tk-window I should use for this kind of
"list" or does anyone have an idea how to put the list into a tktext-
wi
ackages:
[1] tcltk stats graphics grDevices utils datasets
methods base
other attached packages:
[1] tkrplot_0.0-18 rpart_3.1-44 relimp_1.0-1
Thanks so much!
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g of the boxes,
because some of the mins and first quantiles are 0.
Can anybody help and tell me how I can generate a logarithmic y scale
starting at 0?
Thanks in advance,
--
Anne Skoeries
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Thanks, works just fine! Great!
--
Anne Skoeries
Am 12.08.2009 um 16:04 schrieb jim holtman:
Untested, but try something like this:
for(i in 1:(reihen-1)) {
but <- tkbutton(base, text = classi[i], command = local({
anzeige <- data.matrix(dataframe[i,-c(s
d 3 buttons and choose button1, it generates a plot
with the parameters of button3. The same plot after pressing button2
or button3.
How can I make sure, that each button calls the function with it's
"own" parameters? So that button1 calls the function with the first
row of m
d base packages:
[1] tcltk stats graphics grDevices utils datasets
methods base
Thanks for the help,
--
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times. And make a histogram of the resulting
corelation coefficients.
You see, this is quite complicated. Does any of you have any idea how to
start? I am very very grateful for any suggestions!
The helper will get a parcel with swiss chocolate ;-) !!
Best wishes from Bern,
Anne
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That works perfekt! Thanks so much!
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= -delete)
newData <- data[-delete]
But as I try the way with a minus I'll get the message: "invalid
argument to unary operator"
There must be a simple way to delete all of the columns, but I just
don't get it.
Thanks for your help,
--
Anne Skoeries
nd if I try
summary(data[get("variable)] it gives me back a different result since
the data isn't a factor anymore but a list.
Thanks for the help,
Anne
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PL
INDOW=1; ORIENTATION=vertical; KEY=0; BARCOVERING=1.0]
slope; PEN=2
Does anybody have done something similar and has any idea how to make
the randomisation part?
I would be very grateful for any help!!
Thanks in advance,
Anne
--
Anne Kempel
Institute of Plant Sciences
University of Bern
RGR~Fertilizer+Status+Fertilizer:Status+(1|Age)+(1|Family/Species)+(0+Fertilizer|Family/Species),data=rgr)
I`m thankful for any comments!
anne
--
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Institute of Plant Sciences
University of Bern
Altenbergrain 21
CH-3103 Bern
kem...@ips.unibe.ch
__
R-h
RGR~Fertilizer+Status+Fertilizer:Status+(1|Age)+(1|Family/Species)+(0+Fertilizer|Family/Species),data=rgr)
I`m thankful for any comments!
anne
--
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Institute of Plant Sciences
University of Bern
Altenbergrain 21
CH-3103 Bern
kem...@ips.unibe.ch
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know if the problem is in the package I built or if I can
use some code to answer this question. I list all codes used to build and
install the package pd.ragene.1.0.st.v1 and used to analyze expression
arrays below.
Many thanks for your help,
Anne-Marie Madore
## building the
me some advices, please!?
Thanks
Anne Berger
Institute of Zoo- and Wildlife Research, Berlin, Germany
Swedish University of Agricultural Sciences, Dept. of Wildlife, Fish and
Environmental Studies, Umeå, Sweden
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ample - I promise
to look deeper into the details of exception handling in R when I'm
back.
Thanks a lot!!
Anne-Marie
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Wed, 2008-07-09 at 11:40 +0200, Anne-Marie Ternes wrote:
>> Hi,
>>
>> if given the value of, say, 15000, I would like to be able to divide
>> that value recursively by, say, 5, and to get a vector of a determined
>> length, say 9, the last value being (set to) zero
t.
Thanks a lot for your help, hope the question is not too dumb...
Anne-Marie
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all this I can get "whole document" PDFs or "per-chapter" PDFs - Great!
Actually, then I go on and feed the tex file(s) to "latex2html", a
great tool, to generate HTML equivalents all ready with navigation,
buttons and all.
Maybe it's not yet perfect, but for sur
graphical example
with code would be very helpful.
So, the question is, if there is per chance a way to pass "side" and
"line" arguments to "legend", and if not, what is the best way to do
what I try to do? BTW, the plot types involved are mostly line plots
and barplot
On Thu, 22 May 2008, francogrex wrote:
f >
f > Hi, this is probably quite simple but I can't seem to do it correctly. I
have
f > a data frame of counts of infections in different ages; something like:
f > count=c(1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 7, 8, 8, 9, 9,
f > 10, 11, 15, 17,
g
incidence rates several times in later chapters). If there is a better
way to split the code without having to requery the database at each
chapter, I'll be glad to know about that too!
BTW, I'm working on Ubuntu Linux.
Thanks a lot for your insight,
Anne-Marie
bars had contour lines (more like the barplot)...
would that be possible?
Thank you so much again.
Anne-Katrin
Barplot is probably not the best way here (it is possible, but more work
axis(4,at=c(1,2,3,4,5,6))
text(6,2.9, "2nd y-axis", srt = 270, xpd = TRUE)
par(new=TRUE)
plot(x, y2, lty=2,type="l", xlab="x-axis", ylab= "y-axis")
I dont think "barplot" is the right thing to use here since I cant specify
the x-valueswhat can I
that the "0"-values from the barchart
are displayed as well?
Thank you so much!
Anne-Katrin
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h basic statistical than R questions.
But I'd be glad if you could help me find the best solution for my
type of analysis, resp. point me to good resources that show me how to
do this. The problem is that most resources show "how to" do the
analysis, but they don't explain at all h
Dear R-helpers,
I would like to do a Spearman rank order test, and used the cor() function
with the method "spearman".
It gives me a number (correlation coefficient?) , but how can I get the
p-value?
Thank you for the help in advance!
Regards,
Anne-Katrin
--
[[a
On Mon, 4 Feb 2008, Falco tinnunculus wrote:
Ft > Dear all,
Ft >
Ft > How do I make reference to R in the method section in a scientific article?
Ft > Should I state the web aderess?
Ft >
Ft > And, is this the proper way to report the lme test?
Ft >
Ft >
Ft > "The relationships were assumed to be
On Mon, 4 Feb 2008, Falco tinnunculus wrote:
Ft > Dear all,
Ft >
Ft > How do I make reference to R in the method section in a scientific article?
Ft > Should I state the web aderess?
Ft >
Ft > And, is this the proper way to report the lme test?
Ft >
Ft >
Ft > "The relationships were assumed to
not locate that message on the
CH > archive.
CH >
CH > Thanks.
CH > -Christos
There are MANY FREE tutorials on regular expressions. Just
google regular expressions tutorial.
Anne
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