Laurent... Bill is suggesting building your own indexed database... but this
has been done before, so re-inventing the wheel seems inefficient and risky. It
is actually impossible to create such a beast without reading the entire file
into memory at least temporarily anyway, so you are better
Hi,
When you add a new layer to a plot and you provide new data, wouldn't it
make sense to provide aes() with some indication of the names of the
variables to use for coordinate plotting? You have provided a grouping
variable for the paths, but what of coordinates x and y? How could
geom_path()
Ok, thank you for the advice I will take some time to see in details
these packages.
Le 19/05/2020 à 05:44, Jeff Newmiller a écrit :
Laurent... Bill is suggesting building your own indexed database... but this
has been done before, so re-inventing the wheel seems inefficient and risky. It
Works for me.
set.seed( 42 )
a <- c(2,4,3,4,6,5,3,1,2,3,4,3,4,5,65)
b <- c(23,45,32,12,23,43,56,44,33,11,12,54,23,34,54)
d <- c(9,4,5,3,2,1,3,4,5,6,4,9,10,11,18)
my.experiment <- function() {
a <- a + rnorm( length( a ), 0, 0.05 )
b <- b + rnorm( length( b ), 0, 0.05 )
d <- d + rnorm( lengt
you need to pay attention to the intermediate structures that you generate.
If all you want is one number, then that is what you should create
mean(replicate( 500, my.experiment() ))
Since you do seem to want to store the intermediate values, then you must
name
the object according to its structu
Hi Rui,
If I don't transpose t() the output of the replicate (my R code here below) I
still get an error message !!
a=c(2,4,3,4,6,5,3,1,2,3,4,3,4,5,65)
b=c(23,45,32,12,23,43,56,44,33,11,12,54,23,34,54)
d=c(9,4,5,3,2,1,3,4,5,6,4,9,10,11,18)
my.experiment
Hello,
Inline.
Às 21:38 de 19/05/20, varin sacha via R-help escreveu:
Hi Richard,
Thanks for your response.
However, how can I correct my R code knowing that I want, as a result, only one
value : the mean of the 500 MSE_OLS values ?
Just don't transpose the output of replicate?
Hope this
Hi Richard,
Thanks for your response.
However, how can I correct my R code knowing that I want, as a result, only one
value : the mean of the 500 MSE_OLS values ?
Le mardi 19 mai 2020 à 21:59:07 UTC+2, Richard M. Heiberger a
écrit :
> dim(my.data)
[1] 1 500
you have a matrix
> dim(my.data)
[1] 1 500
you have a matrix with a single row and 500 columns.
you gave a name to only the first column.
Look at the result of replicate(). it is a vector. You transposed it into
a one-row matrix.
> tmp <- replicate( 500, my.experiment() )
> dim(tmp)
NULL
> length(tmp)
[1] 50
Dear R-experts,
Here is my R code, I get a result but I also get an error message so I doubt I
can trust the result I get.
What is going wrong ? Many thanks.
a<-c(2,4,3,4,6,5,3,1,2,3,4,3,4,5,65)
b<-c(23,45,32,12,23,43,56,44,33,11,12,54,23,34,54)
d<-c(9,4
Dear Ana
Perhaps paste together SNP and GENE using paste() and then supply that
as the snp parameter.
Michael
On 19/05/2020 17:12, Ana Marija wrote:
Hello,
I am making manhattan plot with:
library(qqman)
manhattan(a, chr="CHR", bp="BP", snp="SNP", p="P",annotatePval = 0.0001)
and I would l
Hi Michael,
can you please send me code how that would be done?
Thanks
Ana
On Tue, May 19, 2020 at 11:18 AM Michael Dewey wrote:
>
> Dear Ana
>
> Perhaps paste together SNP and GENE using paste() and then supply that
> as the snp parameter.
>
> Michael
>
> On 19/05/2020 17:12, Ana Marija wrote:
Hello,
I am making manhattan plot with:
library(qqman)
manhattan(a, chr="CHR", bp="BP", snp="SNP", p="P",annotatePval = 0.0001)
and I would like to annotate these two SNPs which are above the
threshold so that they have GENE name beside them:
> a[a$SNP=="rs4081570",]
SNPP CHR
Hello,
I'm getting a different error:
p <- ggplot(c1members2, aes(x,y)) +
geom_point()
p + geom_line(data = paths, aes(group = trip_id)) +
ggtitle(paste0("Optimal route with cost: ",
round(objective_value(result), 2)))
#Error in objective_value(result) : object 'result' not found
When
Hello Chris, and thank you for your response.
I tried it both TRUE and FALSE given my confusion with the reference I found
that idea in.
It did not help either way.
Glad you noticed though, thank you.
WHP
William H. Poling Ph.D., MPH | Senior Data Scientist, Medicare Stars, CVS
Health
p 813
- Original Message -
> From: "Poling, William via R-help"
> To: "Ben Tupper"
> Cc: r-help@r-project.org
> Sent: Tuesday, 19 May, 2020 15:04:25
> Subject: Re: [R] Help with ggplot error: #Error in FUN(X[[i]], ...) : object
> 'x' not found
> Hello Ben and thank you for your response.
>
Hello Ben and thank you for your response.
I thought that was what I was doing when I ran this version:
Test1
p <- ggplot(c1members2, aes(x,y)) +
geom_point()
p + geom_line(data = paths, aes(group = trip_id),inherit.aes = FALSE) + #Error
in FUN(X[[i]], ...) : object 'x' not found
ggtitle
#RStudio Version Version 1.2.1335
sessionInfo()
# R version 4.0.0 Patched (2020-05-03 r78349)
#Platform: x86_64-w64-mingw32/x64 (64-bit)
#Running under: Windows 10 x64 (build 17763)
Good morning.
I am testing a small sample of my data using an example found here:
#https://www.r-orms.org/mixed-i
I was impressed by Jim's effort.
So, I thought I'd try to produce an exploratory plot.
I've adapted some of his code.
The following script produces a heatmap for a cylindrical density estimate.
Bright areas are (mathematical) regions of high density.
However, the interpretation is complicated by t
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