> On 23 Sep 2017, at 01:32, array chip via R-help wrote:
>
> Hi,
>
> I am learning to use your gsDesign package! I have a question about Pocock
> and OBF boundary. As far as Iunderstand, these 2 boundaries require equal
> spacing between interim analyses(maybe this is not correct?). But I ca
Hi,
I am learning to use your gsDesign package! I have a question about Pocock and
OBF boundary. As far as Iunderstand, these 2 boundaries require equal spacing
between interim analyses(maybe this is not correct?). But I can still use
gsDesign to run an analysisbased on unequal spacing:
gsDes
Hi,
I tried to read xlsx files by "XLConnect" packages, but the dates are
one day earlier than it is supposed to be. I moved from California to
Taiwan (Eastern Asia), and it worked well in California, but not in Taiwan.
Even if I adjust my Mac time to California time zone, it gives the wrong
da
Thanks!
On 9/22/2017 12:34 PM, Bert Gunter wrote:
> Well, that's a bit like driving from Boston to New York by way of
> Chicago.
>
> See ?structure
>
> test <- list(a=1,b=2,c=3)
> new <- c(4,5,6)
> test.new <- structure(as.list(new), names=names(test))
> test.new
> $a
> [1] 4
>
> $b
> [1] 5
>
>
An obvious question is: why mess with RTF at all, as R and RStudio provide
support for document creation with embedded R content (i.e. through knitr
and associated)?
But be that as it may (i.e. don't answer that), have you tried posting on:
https://stackoverflow.com/ ?
Seems like this sort
R 3.4.1
OS X and Windows
Colleagues
I have a complicated problem that includes several components:
R
RTF
PDF
Using R (and a slew of RTF commands), I assemble a text document with an RTF
extension. The document contains text, tables, and images (JPEG format,
previously
Well, that's a bit like driving from Boston to New York by way of Chicago.
See ?structure
test <- list(a=1,b=2,c=3)
new <- c(4,5,6)
test.new <- structure(as.list(new), names=names(test))
test.new
$a
[1] 4
$b
[1] 5
$c
[1] 6
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is
Super,
Thanks
On Fri, Sep 22, 2017 at 4:57 PM, Boris Steipe
wrote:
> > a <- c("<0.1", NA, 0.3, 5, "Nil")
> > a
> [1] "<0.1" NA "0.3" "5""Nil"
>
> > b <- as.numeric(a)
> Warning message:
> NAs introduced by coercion
> > b
> [1] NA NA 0.3 5.0 NA
>
> > b[! is.na(b)]
> [1] 0.3 5.0
>
>
>
> a <- c("<0.1", NA, 0.3, 5, "Nil")
> a
[1] "<0.1" NA "0.3" "5""Nil"
> b <- as.numeric(a)
Warning message:
NAs introduced by coercion
> b
[1] NA NA 0.3 5.0 NA
> b[! is.na(b)]
[1] 0.3 5.0
B.
> On Sep 22, 2017, at 11:48 AM, Shane Carey wrote:
>
> Hi,
>
> How do I extract just n
Hi,
How do I extract just numbers from the following list:
a=c("<0.1",NA,0.3,5,Nil)
so I want to obtain: 0.3 and 5 from the above list
Thanks
--
Le gach dea ghui,
*Shane Carey*
*GIS and Data Solutions Consultant*
[[alternative HTML version deleted]]
My apologies for the late reply. I had scans after I last messaged you
yesterday.
Please find attached the ms-dos CSV file which I prepared using microsoft
excel. there should be GT1.csv and NPA1.csv.
Thanking you
From: ruipbarra...@sapo.pt
Sent: Thursday, S
Yes, perfect!
Thank you
L
On Fri, Sep 22, 2017 at 2:48 PM, Duncan Mackay wrote:
> Hi Luigi
>
> will this do
>
> barchart(
> D ~ A|E,
> DF,
> groups = C,
> stack = TRUE,
> horizontal = F,
> main = "Comparison of test results",
> xlab = "Count",
> col = c("yellow", "
Solved it:
test <- list(a=1,b=2,c=3)
new <- c(4,5,6)
hold <- as.list(new)
updated_test <- replace(test,c(1:3),hold)
$a
[1] 4
$b
[1] 5
$c
[1] 6
mean.parms <- as.list(mean.parms)
mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms)
On 9/22/2017 10:34 AM, Evan Cooch wrote:
Supp
Suppose I have the following:
test <- list(a=1,b=2,c=3)
I also have a vector (or list, or something else...) with new numbers
new <- c(4,5,6)
What I'm trying to figure out is how to take the list, and update the
numbers from {1,2,3} to {4,5,6}
So, in the end,I want the 'update' test list to
Hi Luigi
will this do
barchart(
D ~ A|E,
DF,
groups = C,
stack = TRUE,
horizontal = F,
main = "Comparison of test results",
xlab = "Count",
col = c("yellow", "orange"),
par.settings = list(
strip.background = list(col="light grey"),
superpose.po
On Fri, Sep 22, 2017 at 7:28 AM, yadav neog wrote:
> thankx to everyone for your valuable suggestions. one query regarding the
> GARCH model.
> I have applied the GARCH model for the same data that I send you all . and
> my results coming like
>
> Error in .sgarchfit(spec = spec, data = data, out.
thankx to everyone for your valuable suggestions. one query regarding the
GARCH model.
I have applied the GARCH model for the same data that I send you all . and
my results coming like
Error in .sgarchfit(spec = spec, data = data, out.sample = out.sample, :
ugarchfit-->error: function requires a
Dear all,
I have made a barplot using lattice in which the bars are stacked
horizontally. I would like to stack them vertically, but if I use the
parameter 'horizontal = FALSE' I get the error: 'Error in FUN(X[[i]],
...) : invalid 'type' (character) of argument'. The problem I face is
that, in draw
Hi
From: Upananda Pani [mailto:upananda.p...@gmail.com]
Sent: Friday, September 22, 2017 11:53 AM
To: PIKAL Petr
Cc: r-help ; Gabor Grothendieck
Subject: Re: [R] Convert data into zoo object using Performance analytics
package
Dear All,
Thanks a lot for your help. Would you please let me know
Hi
see in line
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Upananda
> Pani
> Sent: Friday, September 22, 2017 11:45 AM
> To: r-help
> Subject: [R] Treating NA in timeSeries package
>
> Dear All,
>
> I am facing problem with NA treatment in my fi
Dear All,
Thanks a lot for your help. Would you please let me know if i want to read
a csv file as zoo object from my local file rather than directly from the
website, how to do that?
library(zoo)
u <- "https://faculty.washington.edu/ezivot/econ424/sbuxPrices.csv";
fmt <- "%m/%d/%Y"
With sincer
Dear All,
I am facing problem with NA treatment in my financial time series data.
# data reading
aluminum = read.csv(file="alu.csv", header=T, sep=",")
fut = aluminum [,2]
spt = aluminum [,3]
# Missing Value Treatment (Linear Interpolation)
spt = interpNA(spt, method = c("linear"))
fut = inte
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